An object is in uniform circular motion, tracing an angel at 30 degrees every 0.010 seconds. What's the period of this motion and how do I work it out?
Answers
Answer 1
Answer:
Here's the rule you need to know in order to answer this question:
1 full circle ==> 360 degrees .
Got that ?
Now you could set up a proportion:
(30 degrees) / (0.01 second) = (360 degrees) / (time for full period)
Cross-multiply the proportion:
(30°) · (period) = (360°) · (0.01 sec)
Divide each side by (30°) : Period = (360° · 0.01 sec) / (30°)
= (3.6° · sec) / (30°)
= (3.6 / 30) sec
= 0.12 sec . ___________________________________
Another way to look at it:
30° takes 0.01 second 60° takes 0.02 second 90° takes 0.03 second 120° takes 0.04 second 150° takes 0.05 second 180° takes 0.06 second 210° takes 0.07 second 240° takes 0.08 second 270° takes 0.09 second 300° takes 0.10 second 330° takes 0.11 second 360° takes 0.12 second
A 500 kg compact car and a 1500 kg truck are accelerated equally.which vehicle exerts more force?how many times more?(im guessing the 1500kg truck exerts more force but i don't know how to solve for how many times more)
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The truck doesn't "exert more force".
It TAKES more force to accelerate the truck at the same rate as the car, because the truck has more mass.
Think: In order to move two rocks, you have to push harder on the heavy one than you do on the lighter one.
How much more ?
In order to produce the same acceleration . . .
half as much mass ===> half as much force
twice as much mass ===> twice as much force
ten times as much mass ===> ten times as much force
a 1500-kg truck compared to a 500-kg car . . . triple the mass ===> triple the force, in order to accelerate them equally .
Objects with greater mass have a weaker force of gravity between them.
True False
Answers
False, more massive objects exert a stronger gravitational force.
If you start skating down this hill, your potential energy will be converted to kinetic energy. At the bottom of the hill, your kinetic energy will be equal to your potential energy at the top. What will be your speed at the bottom of the hill?
Answers
Your potential energy at the top of the hill was (mass) x (gravity) x (height) .
Your kinetic energy at the bottom of the hill is (1/2) x (mass) x (speed)² .
If there was no loss of energy on the way down, then your kinetic energy at the bottom will be equal to your potential energy at the top.
(1/2) x (mass) x (speed)² = (mass) x (gravity) x (height)
Divide each side by 'mass' :
(1/2) x (speed)² = (gravity) x (height) . . . The answer we get will be the same for every skater, fat or skinny, heavy or light. The skater's mass doesn't appear in the equation any more.
Multiply each side by 2 :
(speed)² = 2 x (gravity) x (height)
Take the square root of each side:
Speed at the bottom = square root of(2 x gravity x height of the hill)
We could go one step further, since we know the acceleration of gravity on Earth:
Speed at the bottom = 4.43 x square root of (height of the hill)
This is interesting, because it says that a hill twice as high won't give you twice the speed at the bottom. The final speed is only proportional to the square root of the height, so in order to double your speed, you need to find a hill that's 4 times as high.
Today, Earth’s magnetic field is losing approximately 7 percent of its strength every 100 years. If thestrength of Earth’s magnetic field at its surface is 0.5 gauss today, what will it be 100 years from now?
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It would be 0.5-0.5*0.07=0.5-0.035=0.465 gauss.
How much force is needed to accelerate a 3kg skateboard at 5m/s2
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F = ma
F = 3*5
F = 15 N
Hope it helps :)
Answer:
F=15
Explanation:
Both retinal disparity and convergence increase as an object gets closer to the individual.
Answers
That statement is true
Retinal disparity : space between your eyes that allow binocular vision to create depth perception
Retinal Convergence : Space between your eyes that signal visual moves to the retina
They both will increases as an object get closer to the individual, allowing them acknowledge and observe the existence of the object