What is the main force that causes a star to turn into a black hole?Temperature
Gravity
Pressure
Nuclear explosions.

Answers

Answer 1

Answer: Gravity. When a dying star of sufficient mass is no longer to support nuclear reactions in its core, it loses the pressure in the core that supports the entire star. Since there is now nothing to counter its own gravity, the entire star implodes until it becomes either a neutron star or, if its mass is large enough, a black hole.

Related Questions

What effect does adding more loops to the wire coil have on the electromagnet?
The statement that "The universe is the same everywhere and does not change over time" is known as _____.a. the cosmological principle b. the perfect cosmological principle c. the oscillating universe theory d. the steady state theory
sticking your fingers into a wall socket will not bring you into direct contact with an electrical current. true or false
Short answerYou are provided a 20-mL solution of methanol and water. a. Name the technique that you would use to separate and identify the components of the solution. b. Provide specific details of the method used. c. State the advantage of the method you choose.
While skiing, Ellen encounters a ledge that sends her flying horizontally at a rate of 12 m/s. How far away will she land if the ledge is 7 meters high? ...?

A dolphin swims 1.85 km/h. How far has the dolphin traveled after .60 h?

Answers

1.85 km every hour x 0.60 hours

1.85 x 0.6 = 1.11

The dolphin traveled 1.11 km.

A train whistle is at a higher pitch (note) as it approaches you and then drops to a lower pitch as it moves away. This effect is called?

Answers

the effect is called The doppler effect

The effect being mentioned is called "The doppler effect".

Which inventor created a delivery system for electricity that was deemed safer than Thomas Edison's system? a. Henry Flagler
b. George Proctor
c. George Westinghouse
d. Thomas DeSaille Tucker

Answers

c. George Westinghouse is the inventor who created a delivery system for electricity that was deemed safer than Thomas Edison's system.

George Westinghouse created a safer and more efficient system for electricity delivery using Alternating Current (AC), which proved superior to Thomas Edison's Direct Current (DC) system.The correct option is C.

The inventor who created a delivery system for electricity that was deemed safer than Thomas Edison's system is George Westinghouse. While Edison's system utilized Direct Current (DC), Westinghouse's approach involved the use of Alternating Current (AC).

This advanced system enabled the delivery of electric power across much farther distances and changed how electricity was used in homes, businesses, and industries.

It led to the expansion of urban areas and allowed factories to operate round-the-clock.

Edison and Westinghouse engaged in a public contention over which system was superior. Despite Edison's efforts to discredit AC power, his method was eventually deemed less efficient, and he had to adapt to the use of AC power due to its growing popularity.

Therefor the correct option is C.

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A −12 nC charge is located at (x,y) = (1.0 cm, 0 cm).What is the electric field at the position (x₁,y₁) = (5.0 cm, 0 cm) in component form?What is the electric field at the position (x₂,y₂) = (−5.0 cm, 0 cm) in component form?What is the electric field at the position (x₃,y₃) = (0 cm, 5.0 cm) in component form?Express your answer in terms of the unit vectors i^ and j^. Use the 'unit vector' button to denote unit vectors in your answer.

Answers

Final answer:

The electric fields at the points (5.0 cm, 0 cm), (-5.0 cm, 0 cm), and (0 cm, 5.0 cm) due to a -12 nC charge are -67.5x10^3 i^ N/C, 30x10^3 i^ N/C and -67.5x10^3 j^ N/C respectively.

Explanation:

The subject of this question is Electric Field, a part of physics. Specifically, we're looking at point charges and using the formula for the electric field due to a point charge, which is E = k|Q|/r², where k is the Coulomb's constant, Q is the charge and r is the distance to the point where the electric field is calculated.

At the position (5.0 cm, 0 cm), the distance from the charge is 4.0 cm. Thus, the electric field is E₁ = k|-12 x 10^(-9) C|/(0.04 m)² = -67.5 x 10^3 N/C. In terms of unit vectors, this is -67.5 x 10^3 i^ N/C, because the field points in the negative x direction.
At the position (-5.0 cm, 0 cm), the distance from the charge is 6.0 cm. Thus, the electric field is E₂ = k|-12 x 10^(-9) C|/(0.06 m)² = -30 x 10^3 N/C. In terms of unit vectors, this is 30 x 10^3 i^ N/C, because the field points in the positive x direction.
At the position (0 cm, 5.0 cm), the field is purely in the y-direction, and the point is 4.0 cm above the charge. Thus, the field is E₃ = k|-12 x 10^(-9) C|/(0.04 m)² = -67.5 x 10^3 N/C. In terms of unit vectors, this is -67.5 x 10^3 j^ N/C.

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Calculate how much work is required to launch a spacecraft of mass m from the surface of the earth (mass mE, radius RE) and place it in a circular low earth orbit--that is, an orbit whose altitude above the earth's surface is much less than RE. (As an example, the International Space Station is in low earth orbit at an altitude of about 400 km, much less than RE

Answers

The work done to launch the spacecraft in low earth orbit is $(GM_emh)/(R_e(R_e+h))$

Work-energy theorem:

The gravitational force is a conservative force. So, the total energy of the system must be conserved.

According to the work-energy theorem:

work done = - change in potential energy of the system.

W = -ΔPE

Initially, the potential energy of the satellite on the surface is:

PE = $-(GM_em)/(R_e)$

where m is the mass of the satellite

Let the orbit be at a height of h from the surface, so the potential energy in the orbit is :

PE' = $-(GM_em)/(R_e+h)$

ΔPE = PE'-PE

ΔPE = $-GM_em((1)/(R_e+h)-(1)/(R_e))$

$\Delta PE=-(GM_emh)/(R_e(R_e+h))$

Now work done:

W = - ΔPE

Thus,

$W=(GM_emh)/(R_e(R_e+h))$

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Answer:

Work done to shift the spacecraft from Earth surface to low Earth radius is given as

$W = (GM_e m)/(2R_e)$

Explanation:

As we know that spacecraft is at surface of Earth initially

So we will have

$U_i = -(GM_e m)/(R_e)$

now when it is at low radius Earth Orbit then we have

$U_f = -(GM_e m)/(2(R_e + h))$

now we know that work done to shift the spacecraft from Earth Surface to Low earth orbit is change in total energy

$W = -(GM_e m)/(2(R_e + h)) + (GM_e m)/(R_e)$

so we have

$W = (GM_e m)/(R_e) (-(1)/(2(1 + h/R_e)) + 1)$

$W = (GM_e m)/(R_e) (-(1)/(2)(1 - (h)/(R_e)) + 1)$

$W = (GM_e m)/(2R_e)(1 + (h)/(R_e))$

since we know h << Re

so work done is given as

$W = (GM_e m)/(2R_e)$

When a marble is at rest what happened

Answers

The marble will stay in place until another force pushes it

Answer: the marble will remain in place at a constant velocity of zero

Explanation:

Newton's first law states that a body at rest will remain at rest, and a body in motion will remain in motion in a straight line at a constant velocityunless acted upon by an outside force

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In any one material, all electromagnetic waves have the samea. wavelength.b. velocity.c. frequency.d. amplitude.

When Anna eats an apple, the sugars in that apple are broken down into the substance called glucose. Glucose is then burned in her body for energy. One of the body parts that needs this energy is the heart, which beats due to electrical impulses. A byproduct of this glucose breakdown is the heat that warms her body and is later released.Which identifies the energy transformations that take place in Anna’s body as this process takes place?A: Mechanical energy is converted to kinetic energy, which is then converted to potential energy.B: Chemical energy is converted to thermal energy and electrical energy.C: Electrical energy is converted to chemical energy and thermal energy.D: Mechanical energy is converted to potential energy which is then converted to kinetic energy.