The friction which acts on the object that is not moving is static friction, so, option A is correct.
Between two surfaces that are sliding or attempting to slide over one another, there is a force called friction. For instance, friction makes it challenging to push a book down the floor. Friction always moves an object in a direction that is counter to the direction that it is traveling or attempting to move.
Static friction is 0 for an object at rest on a level surface. Static friction generates an equal and opposite force that holds the book at rest if you push horizontally with a small force.
The static friction force grows to meet the force as you push harder. The book eventually moves when the maximum static friction force is reached.
Thus, the friction is static.
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a. Technician A
b. Technician B
c. Both Technicians
d. Neither Technician
Answer:
c. Both Technicians
Explanation:
A steering wheel position sensor is being discussed. Technician A says that the sensor is used to determine the direction of the steering wheel. Technician B says that the sensor detects how fast the steering wheel is turned. the following are used to sense
Hall-effect, Photo cell, Potentiometer are used on vehicles equipped with an electronically controlled suspension
sensors are like indicators in a vehicle to give signals for both direction and the speed of the vehicle
c. Both Technicians
The forest ecosystem will regain back its natural ecology compared to burning of the forest and other illegal activities done to the forest. And also, some of the animals living in that forest will live and those that are endangered will not be threatened.
Directly proportional
Answer:
The mass of the object is 0.2 kg
Explanation:
The magnitude of the applied force = 2.0 N
The duration of application of the force = 0.1 second
The increase in velocity given to the body by the force = 1.0 m/s
From the equation of motion under acceleration, we have;
v = u + a·t
Therefore;
a = (v - u)/t
Where;
v = The final velocity
u = The initial velocity
t = The time taken for the change in velocity = 0.1 s
Given that the change in velocity = 1 m/s, we have;
v - u = 1 m/s
∴ a = (v - u)/t = 1 m/s/(0.1 s) = 10 m/s²
The acceleration, a = 10 m/s²
The equation for the applied force, F is F = Mass, m × Acceleration, a
Therefore, when the applied force, F = 2.0 N, and the acceleration, a is a = 10 m/s², we have;
F = Mass, m × Acceleration, a
2.0 N = Mass of the object × 10 m/s²
∴ Mass of the object = 2.0 N/10 m/s² = 0.2 kg
The mass of the object = 0.2 kg.