I Need Help PLease!Ashton estimates the square root of 72 in the following way:
√72=
2√36=
2×6=12
Explain why his reasoning is incorrect.
Estimate the square root of 72 to the nearest tenth without using your calculator. Show your work.
Answer:

Answers

Answer 1
Answer:

Answer:

\sqrt {72} = 6\sqrt 2

Step-by-step explanation:

Ashton estimates the square root of 72 in the following way:

√72=

2√36=

2×6=12

a) Explain why his reasoning is incorrect

This is incorrect because \sqrt2 * 6 is the correct answer but he has missed the square root term on 2.

=\sqrt {2^2X2X3^2 }

=\sqrt {2^2} \sqrt 2 \sqrt {3^2 }

=2 X \sqrt 2 X 3

= \sqrt 2 X 6

or can be written as:

= 6\sqrt 2

b) Estimate the square root of 72 to the nearest tenth without using your calculator. Show your work.

Find the factors of 72 we get \sqrt {2X2X2X3X3 }  

Now, we will combine 2 terms if the are same so,

=\sqrt {2^2X2X3^2 }

=\sqrt {2^2} \sqrt 2 \sqrt {3^2 }

=2 X \sqrt 2 X 3

= \sqrt 2 X 6

= 6\sqrt 2

\sqrt {72} = 6\sqrt 2


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Help with this math problem

Which properties were applied in steps 1 and 3step 1 5(11z+6z+29)
step 3 85z+145


commutative property, then distributive property
communtative property, then identify property
associative property, then distributive property
associative property, then commutative property?

Answers

C - Associative then Distributive

Associative allows the combining of like terms (Both with variable z)
Distributive allows the 5 to distribute through

5(11z+6z+29)
5(17z+29)
5(17z)+5(29)
85z+145

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Answers

do it like this, for the 1st one, 1/3 of 72, and do it for the rest.. lol

Expand and simplify these(X+6) (x+9)
(X-5) (x+2)
(X-1)(x-7)
(4x+9)(3x+8)
(3x-8)(2x-1)
(X+9) ^2(squared)
(3x+2)^2

Answers

(x+6)(x+9)=x^2+9x+6x+54=x^2+15x+54 \n\n(x-5)(x+2)=x^2+2x-5x-10=x^2-3x-10\n\n(x-1)(x-7)=x^2-7x-x+7=x^2-6x+7\n\n(4x+9)(3x+8)=12x^2+32x+27x+72=12x^2+59x+72\n\n(3x-8)(2x-1)=6x^2-3x-16x+8=6x^2-19x+8\n\n(x+9) ^2=x^2+2\cdot x\cdot9+9^2=x^2+18x+81 \n\n(3x+2)^2=(3x)^2+2\cdot3x\cdot2+2^2=9x^2+12x+4

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Answers

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Answers

Morgen, (hoe is nederlands)

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Answers

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