What is 62.5% in two equivalent forms ?

Answers

Answer 1
Answer:

Answer: Two equivalent forms are :

(5)/(8)\ and\ (125)/(200)

Step-by-step explanation:

Since we have given that

62.5%

We have to write in equivalent forms:

1) First equivalent form is given by

62.5\%\n\n=(62.5)/(100)\n\n=(625)/(1000)\n\n=(25)/(40)\n\n=(5)/(8)

2) Second equivalent form is given by

62.5\%\n\n=(62.5)/(100)\n\n=\frac{625}[1000}\n\n=(625/ 5)/(1000/ 5)\n\n=(125)/(200)

Answer 2
Answer: 62.5%

Percents are parts of 100, so write 62.5 as a fraction over 100:

62.5/100

Divide the numerator and denominator by 12.5:

62.5 / 12.5 = 5
100 / 12.5 = 8

5/8

This is one form.

62.5 / 100 = 0.625

This is another form.

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If a triangle has 3 side one is 12 one is 72 what is the last sude

Answers

this triangle has 3 sides one is 12, lets call this side a²

another side is 72, lets call this side c²

this triangle must follow Pythagoras therom if it is right angled, that is a²+b²=c²

where a and b are the two shorter sides and c is the longest side (called the hypotenuse) opposite the right angle

to find the last side you do 72² - 12² = 5040

but it is the square root of 5040 which is 70.99 (two decimal places) if you want it in decimal form, if you want it in surd form it is √5040

There is no way to answer that with only the information given. 
The 3rd side can be ANY length between 60 and 84.  You can't
solve a triangle if you only know 2 sides of it.

IS 71 OVER 20 SIMPLEST FORM?IF NOT WHATS THE ANSWER?

Answers


71/20 is not in simplest form because you need to change it into a mixed number by dividing 71 and 20 and putting the remainder over 20.
no, simplest for would be 3 and eleven twentieths

Convert 4.5yards to inches.

4.5 yd = __ in.

A.

1.5
B.

54
C.

144
D.

162

Answers

The answer is D. 162 inches.

5/6 - 1/6 =
in simplest form

Answers

5/6 - 1/6 forget about the denominator since it's the same denominator
5 - 1 = 4
4/6 is the answer and 2/3 simplified :)
5/6 - 1/6 = 2/3
5-1=4 keep the dinominator. so u have 4/6. simplify by 2 , 4/6÷2=2/3

On a scale drawing of a workshop, 1 inch equals 4 feet. The actual dimensions of the workshop are 40 feet by 60 feet. What are the dimensions of the workshop in the scale drawing?

Answers

On a scale drawing 1 inch equals to 4 feet. 40 by 60 feet is the real one. If you want to find how many inches it is actually you need to divide 40 and 60 by 4. 40 divided by 4 is 10.  60 divided by 4 is 15. The real dimension is 10 by 15.

X – 4y = 7 5x + 9y = 6 (4 points) A(3, –1)
B(3, 1)
C(1, –3)
D(–1, –3)

Answers

The solution to the given system of equations is (3, –1). The correct answer is option A.

The system of equations is given as:

x - 4y = 7   ....(1)

5x + 9y = 6 ....(2)

Solve the first equation for x:

x = 7 + 4y

Substitute the value of x in the second equation:

5(7 + 4y) + 9y = 6

35 + 20y + 9y = 6

29y = -29

y = -1

Substitute the value of y back into the first equation to find x:

x = 7 + 4(-1)

x = 7 - 4

x = 3

Therefore, the solution to the system of equations is x = 3 and y = -1.

Thus, the correct answer is option A.

Learn more about the equation here:

brainly.com/question/10413253

#SPJ3

The complete question is as follows:

Solve the below system of equations.

x – 4y = 7

5x + 9y = 6

A. (3, –1)

B. (3, 1)

C. (1, –3)

D. (–1, –3)

A is the correct answer.
Other Questions
Plz help, I need answers to these questions ASAP, would appreciate a short step-by-step explanation with each! WILL MARK BRAINLIEST!!!You’ve been given $500.00 for your fencing. So first we are going to make as big of a rectangular field as we can with the money that we have for the fencing to surround it. The cost of premium fencing (only the best for your farm, of course) is $11.41 per metre. So with that, and the following equations:A=l*wP=2l+2wWhere A is the area, P is the perimeter, l is the length, and w is the width of a rectangle, we can find the maximum area that we can have for this field.Perimeter of fence:Area of farm:Let’s say we have access to planting 2 different crops, Watermelons and Grapes. We can find the revenue of a crop by the equation:R = (p0 + px)(n0 - nx)Where R is the revenue, p0 is the starting price, n0 is the amount sold at the starting price, p is the price increase, n is the decrease in the amount sold per price increase, and x is the number of price increases.Crop A: Watermelons have a starting price of $12.00 per m2 of area sold. At this price, you can sell 45 m2 worth. For every $2.00 increase, you will sell 1 m2 less. So the first task is to figure out how to put these values into the equation above and turn it into a quadratic function. Then you will need to find the value of x to make the revenue as large as possible. Once you know x, the number of price increases, you can then find what you should price your Watermelons per m2.Equation: R =Number of price increases: x =Price of Watermelon per m^2 =Okay, now we can do the same thing with the grapes, just to give you that extra practice with quadratic functions. The starting price of grapes per m² is $8.00, at which you can sell 60 m² worth. For every $3.00 increase in price, you sell 3 m² less. So use the same method you just used to find the price of grapes per m² of area to maximize revenue.Equation: R =Number of price increases: x =Price of grape per m^2 =Okay, so now, all in all, we have built our farm and found what to price each of our crops at. Now let’s find what amount of each crop to grow and find our profits. Getting right into it, we have the following cost equations:CW = $20.00 * W + $50.00CG = $10.00 * G + $40.00Where CW is the total cost of planting and growing Watermelons, CG is the total cost of planting and growing Grapes, W is the area of Watermelons planted, and G is the area of Grapes planted. Now that we know our cost, we can finally find our profits. Profit is equal to the price per unit area, multiplied by the area sold, subtracted by the total cost planting and growing them, or, Profit = Price * Area - Cost. But at this point, we still don’t know the area of each crop in our field. But we do know a couple of things to figure it out. We know the total area of our farm, found in the first part. Which we can say is, Area = G + W And we were also only given $1590 to plant the crops. So, $1590.00= CW+CG I’ll help you simplify this a bit:$1590.00=$20.00*W+$50.00+$10.00*G+$40.00 $1590.00=$20.00*W+$10.00*G+$90.00So now we have enough information to solve for the areas of Watermelons and Grapes in your field. Here’s some room to do that. Hint: Use either substitution or graph the two equations to find an intersection.Area of watermelon to plant:Area of grapes to pant:Profit of the crops: