jens motorboat travels at a speed of 15mph in still water, the river flows at a speed of 2pmh, how long will it take jen to travel 20mi upstream? 20mi downstream?

Answers

Answer 1
Answer: The speed of the motorboat travelling up stream will be 13mph, therefore it will take 20/13 hours to travel 20 miles upstream. This is about 1 and a half hours. The speed of the motorboat travelling downstream will be 17mph, therefore it will take 20/17 hours to travel 20 miles downstream. This is about 1 hour 10 minutes.

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60 min is 20 percent of how many min

Answers

There is 100% total
20% goes into 100% 5 times
If 60 is 20%, multiply 60 by 5 to get 100%
60 x 5 = 300 min

60 times 5 is 300 minutes, The 5 is there because 20% goes into 100% 5 times

A standard showerhead in Andrew's house dispenses 8 gallons of water per minute. Andrew changed this showerhead to an energy-saving one. The equation shows the amount of water dispensed, y, as a function of the number of minutes, x, for the new showerhead.y = 3x

How much water does Andrew save each day with the change in showerheads if he uses the shower for 8 minutes each day?

5 gallons
16 gallons
24 gallons
40 gallons

Answers

64-24 = 40

D) 40 gallons

Answer:

40 gallons

Step-by-step explanation:

OLD SHOWERHEAD

y=8x

y=8(8)

y=64

NEW SHOWERHEAD

y=3x

y=3(8)

y=24

64-24=40

Hope it helps!!!!

BTW it was correct in the test!

Solve the linear equation 2.25 – 11j – 7.75 + 1.5j = 0.5j – 1.

Answers

2.25-11j-7.75+1.5j=0.5j-1 -5.5-9.5j=0.5j-1 10j=-4.5 j=-0.45=9/20

Answer:

j = –0.45

Step-by-step explanation:

just got it right

a sum of money is divided between isha and roger in the ratio 2:3. if isha's share is $600, find roger's share

Answers

There are two solutions to this problem, either:
 1: Isha has the bigger part (:3)
 2: or Isha has the smaller part (2:)

1.
Isha = 3x = 600
solve for x:
x = 600/3 = 200
Then Roger has 2x = 2*200 = 400
600:400
6:4
3:2
the ratio complies, Isha has 600 and Roger 400

2.
Isha = 2x = 600
x = 300
Roger = 3x = 3*300 = 900
600:900
6:9
2:3
the ratio complies, Isha has 600 and Roger 900

Use a net to find the surface area of the right triangular prism shown below: Three rectangles next to each other with a width of 7 feet. The first and second rectangles length are unknown, and the last is 10 feet long. There are two right triangles above and below the last rectangle. One is labeled with a base of 6 feet and a height of 8 feet.

Answers

well to find area you just put squares in the inside

Determine the equation of the line, in point-slope form, that will get your spacecraft from Point A (0,3) to Point B (-3,0)

Answers

A (0,3), \ \ B (-3,0) \n\n\n First \ find \ the \ slope \ of \ the \ line \ thru \ the \ points \: \n \n m= (y_(2)-y_(1))/(x_(2)-x_(1) ) \n \nm=( 0-3)/(-3-0) = (-3)/(-3)=1 \n \n Use \ point \ form \ of \ a \ line\ with \ one \ point: \n \n y-y_(1) =m(x-x _(1)) \n \nm=1,\ \ x_(1)=0, \ \ y_(1)=3 \n \n y-3= (x-0}\n\ny= x +3
m= (y2-y1)/(x2-x1)

m= (0-3)/(-3-0)

m= (-3)/(-3)

m=1

Point Slope Form:  (y-y1)=m(x-x1)

(y-3)=1(x-0)

(y-3)=(x-0)

(y-3)=(x)