Answer:
To determine the value of the function at x = -3, we need to substitute -3 into the given function and evaluate it. Let's go through each option one by one:
1. y = 4: If this is the function, then substituting x = -3 would give us y = 4. However, this option does not match the given function.
2. y = 0: Substituting x = -3 into this function would give us y = 0. However, this option does not match the given function either.
3. y = 30: Substituting x = -3 into this function would give us y = 30. However, this option does not match the given function.
4. y = -3: Substituting x = -3 into this function would give us y = -3. This option matches the given function, so the value of the function at x = -3 is indeed y = -3.
Therefore, the correct answer is:
y = -3
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y = x + 3
If the two equations are graphed, at what point do the lines representing the two equations intersect?
(−1, 2) - answer?
(−2, 1)
(1, −2)
(2, −1)
Answer: a = -3
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Work Shown:
The point (1, -3) is on the blue graph p(x) = a|x|
This means x = 1 and y = -3 pair up.
Use these two values to find 'a'
p(x) = a|x|
y = a|x|
-3 = a*|1|
-3 = a*1
-3 = a
a = -3
The negative 'a' value will apply the reflection over the x axis. The fact that |a| = 3 is larger than 1 indicates the graph is vertically stretched by a factor of 3.
Answer:
Step-by-step explanation:
Note the equal sign, what you do to one side, you do to the other side. Do the opposite of PEMDAS. Isolate the variable, x.
PEMDAS is the order of operation, and =
Parenthesis
Exponents (& Roots)
Multiplication
Division
Addition
Subtraction
~
First, subtract 7y from both sides:
3x + 7y (-7y) = 27 (-7y)
3x = -7y + 27
Next, divide 3 from all terms on both sides:
(3x)/3 = (-7y + 27)/3
x = (-7y/3) + 9
The numerical length of JK is 21 units.
Given that, point J is on line segment IK.
We need to determine the numerical length of JK.
In geometry, a line segment is a part of a line that is bounded by two distinctend points and contains every point on the line that is between its endpoints.
Given JK=x+6, IJ=9, and IK=2x.
Now, IK=JK+IJ
⇒2x=x+6+9
⇒2x=x+15
⇒x=15
Now, JK=x+6=21
Therefore, the numerical length of JK is 21 units.
To learn more about the line segment visit:
brainly.com/question/25727583.
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The distance of the line segment is solved and length of JK = 21 units.
Given data:
Since point J is on the line segment IK, the sum of lengths JK and IJ should be equal to the length of the whole line segment IK.
IJ + JK = IK
IJ = 9
IK = 2x
Now, substitute the values and solve for JK:
9 + JK = 2x
To find JK, we need to isolate it on one side of the equation. Subtract 9 from both sides:
JK = 2x - 9
Now, we are also given that JK = x + 6, so we can set these two expressions equal to each other:
2x - 9 = x + 6
Subtract x from both sides:
2x - x = 6 + 9
x = 15
Now, substitute the value of x back into the expression for JK:
JK = 2(15) - 9
JK = 30 - 9
JK = 21
Hence, the numerical length of JK is 21 units.
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2 44 16
(a) Without using your calculator, approximate the decimal equivalent of each number to the nearest
tenth
(b) Order the string sizes from least to greatest
A fair coin is tossed 10 times. The coin lands heads up all 10 times. What is the probability that it will land heads up on the next toss?