Where on a coordinate graph are the first numbers before the dashes located?
The coordinates in parenthesis are the answer choices. Where do they go?
Example on how to position your answers: (1, 1) and (0, 0) = 1 (Just an example, this is not a correct answer.)

8
4
10
12
Square root of 41
Square root of 68
Square root of 2
Square root of 50
-------------------------
(-10, 2) and (-2, 2)
(-3, -1) and (5, 1)
(-3, -2) and (1, 3)
(-3, -5) and (-2, -4)
(0, 0) and (5, 5)
(1, 2) and (1, -10)
(1, 2) and (5, 2)
(2, 3) and (10, 9)

Explain your answers thoroughly, please. Thank you! :D
Will pick Brainliest!

Answers

Answer 1

Answer: basiclly, we look at the 2 points below and find the distance between them, then we match

d= $\sqrt{( x_(2) -x_(1) )^(2)+( y_(2)-y_(1) )^(2)}$
when finding the distance between points (x1,y1) and (x2,y2)

if the x values, or y values are same, you don't need the distance formula, just use logic

(-10, 2) and (-2, 2)
the y value is the same so find the distance between the x values
from -10 to -2 is 8
8 matches with this one

(-3, -1) and (5, 1)
use distance formula
d= $\sqrt{( 5-(-3) )^(2)+( 1-(-1) )^(2)}$ =√68

(-3, -2) and (1, 3)
input
d= $\sqrt{( 1-(-3) )^(2)+(3-(-2))^(2)}$ =√41

(-3, -5) and (-2, -4)
input
d= $\sqrt{( -2-(-3) )^(2)+( -4-(-5) )^(2)}$ =√2

(0, 0) and (5, 5)
input
d= $\sqrt{( 5-0 )^(2)+( 5-0 )^(2)}$ =√50

(1, 2) and (1, -10)
x values are same so find distance between 2 and -10
answer is 12

(1, 2) and (5, 2)
y values are same
find distance between 1 and 5
answe ris 4

(2, 3) and (10, 9)
input
d= $\sqrt{( 10-2 )^(2)+(9-3)^(2)}$ =10

ANSWERS (because the spacing has gone wierd)
(-10, 2) and (-2, 2)=8
(-3, -1) and (5, 1)=√68
(-3, -2) and (1, 3)=√41
(-3, -5) and (-2, -4)=√2
(0, 0) and (5, 5)=√50
(1, 2) and (1, -10)=12
(1, 2) and (5, 2)=4
(2, 3) and (10, 9)=10

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Answers

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Answers

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Answers

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