PLSSSS HELPPP i need help on matthh

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Answer 1

Answer: The answer iissssssssssssssssssss 20

Related Questions

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The Ross family and the Russell family each used their sprinklers last summer. The water output rate for the Ross family's sprinkler was 35L per hour. The water output rate for the Russell family's sprinkler was 30L per hour. The families used their sprinklers for a combined total of 55 hours, resulting in a total water output of 1725L. How long was each sprinkler used?
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Which of the following number is between 5 and 10 on a number line
Which of the following is equivalent to the expression below for x≠6?2x²-18x+36/x-62(x+3)2x-32x+32(x-3)

Las fracciones que tienen denominador 10, 100, 1000, etc las llamamos fracciones decimales y a su vez las podemos escribir como nummeros decimales 1) encierro las fracciones decimales con color 21/10; 43/8 ;31/12 ;439/100 ;34/10 ;84/7 , 35/1000 ;28/15 ;851/1000

Answers

Answer:

las fracciones decimales son:

21/10 = 2,1

439/100 = 4,39

34/10 = 3,4

35/1000 = 0,035

851 / 1000 = 0,851

Step-by-step explanation:

Toda fraccion cuyo denominador (el numero de abajo) es multiplo de 10 es considerada una fraccion decimal. No importa si el numerador es mayor al denominador. Justamente el sistema decimal fue concebido para facilitar la multiplicacion y division de los numeros por algun multiplo de 10.

1.75 = 12.3 - x / 2.8

Solve for x

Answers

1.75=12.3-x/2.8
x=(12.3-1.75)2.8
x=29.54

1.75 = 12.3 - x / 2.81.75-12.3=-x/2.8

-10.55=-x/2.8

-10,55*-2.8=x

x=29.54

Explain the derivation behind the derivative of sin(x) i.e. prove f'(sin(x)) = cos(x)How about cos(x) and tan(x)?

Answers

1.

$f'(\sin x) = \lim_(h \to 0) (f(x+h) - f(x))/(h) = \lim_(h \to 0) (\sin(x+h) - \sin(x))/(h) = \n \n = \lim_(h \to 0) (2 \sin( (x+h - x)/(2)) \cdot \cos( (x+h+x)/(2)) )/(h) = \lim_(h \to 0) (2 \sin( (h)/(2)) \cos( (2x+h)/(2) ) )/(h) = \n \n = \lim_(h \to 0) [ (\sin( (h)/(2)) )/( (h)/(2) ) \cdot \cos ((2x+h)/(2)) ] = \lim_(h \to 0) [1 \cdot \cos( (2x+h)/(2) ) ] =$

$= \cos( (2x)/(2)) = \boxed{\cos x}$

2.

$f'(\cos x) = \lim_(h \to 0) (f(x+h) - f(x))/(h) = \lim_(h \to 0) (\cos(x+h) - \cos(x))/(h) = \n \n = \lim_(h \to 0) (-2 \sin ( (x+h+x)/(2)) \cdot \sin ( (x+h-x)/(2)) )/(h) = \lim_(h \to 0) (-2 \sin ( (2x+h)/(2)) \cdot \sin ( (h)/(2)) )/(h) = \n \n = \lim_(h \to 0) (-2 \sin ( (2x+h)/(2)) )/(2) \cdot (sin( (h)/(2)) )/( (h)/(2) ) = \lim_(h \to 0) -\sin( (2x+h)/(2)) \cdot 1 =$

$= -\sin( (2x)/(2)) = \boxed{\sin x }$

3.

$f'(\tan) = \lim_(h \to 0) (f(x+h) - f(x))/(h) = \lim_(h \to 0) (\tan(x+h) - \tan(x))/(h) = \n \n = \lim_(h \to 0) ( (\sin(x+h-x))/(\cos(x+h) \cdot \cos(x)) )/(h) = \lim_(h \to 0) ( (\sin(h))/( (\cos(x+h-x) + \cos(x+h+x))/(2) ) )/(h) =$

$= \lim_(h \to 0) ( (\sin(h))/(\cos(h) + \cos(2x+h)) )/( (1)/(2)h ) = \lim_(h \to 0) (\sin(h))/( (1)/(2)h \cdot [\cos(h) + \cos(2x+h)] ) = \n \n = \lim_(h \to 0) (\sin(h))/(h) \cdot (1)/( (1)/(2) \cdot (\cos(h) + cos(2x+h) ) = 1 \cdot (1)/( (1)/(2) \cdot (1+ cos(2x) ) = (2)/(1 + 2 \cos^(2) - 1 ) = \n \n = (2)/(2 \cos^(2) x) = \boxed{ (1)/(\cos^(2)x) }$

4.

$f'(\cot) = \lim_(h \to 0) (f(x+h) - f(x))/(h) = \lim_(h \to 0) (\cot(x+h) - \cot(x))/(h) = \n \n = \lim_(h \to 0) ( (\sin(x - x - h))/(\sin (x+h) \cdot \sin (h)) )/(h) = \lim_(h \to 0) ( (\sin(-h) )/( (\cos(x+h-x) - \cos(x+h+x))/(2) ) )/(h) =$

$= \lim_(h \to 0) ( (-\sin(h))/(\cos(h) - \cos(2x+h)) )/( (1)/(2)h ) = \lim_(h \to 0) ( - \sin(h))/( (1)/(2)h \cdot [\cos(h) - \cos(2x+h)] ) = \n \n = \lim_(h \to 0) (- \sin (h))/(h) \cdot (1)/( (1)/(2) \cdot [\cos(h) - \cos(2x+h)] ) = -1 \cdot (2)/(1 - cos(2x)) = \n \n = - (2)/(1 -1 + 2 \sin^(2)x) = - (2)/(2 \sin^(2) x) = \boxed{- (1)/(\sin^(2) x) }$

I posted an image instead.

Please help me please please

Answers

We have to consider the Order of Operations
And Divide the question into different parts
So we first do the Exponent: $2^(5)$ = 32
(3×32-26)=(96-26)=70
Solve the parts in parenthesis
(8-(4-9)=(8-(-5)=(8+5)=13 (minus and minus becomes addition)
Distribute 7
7(13)=91
Now put the equation and equate everything
(3× $2^(5)$ +13(-2))+7(8-(4-9)=70+91=161
Final Answer=161

Which expression is equivalent to 21 + 49?A 7(3 + 49)

B 7(3 + 7)

C 7(14 + 42)

D 7(14 + 49)

Answers

It would be the second choice, B. 7(3+7) because when you distribute, you get 21+49, because 7x3=21 and 7x7=49.

the answer would be b because 3+7 is 10 and multiple that by 7 is 70. and 20 plus 49 is 70

Angles help find values

Answers

Here's the rule. I'm SURE you learned it in Middle School. Or,
I guess I should say: I'm SURE it was taught in Middle School.

Vertical angles are equal.

"Vertical angles" are the pair of angles that don't share a side,
formed by two intersecting lines.

AND ... even if you forgot it since hearing it in Middle School,
it was clearly explained in the answer to the question that
you posted 9 minutes before this one.

In #8, 'x' and 'z' are vertical angles.
'y' and 116° are vertical angles.

In #9, 'B' and 131° are vertical angles.

In #10, 'B' and 135° are vertical angles.

For all of these, it'll also help you to remember that all the angles
on one side of any straight line add up to 180°.

Angles around a point = 360°
Opposite angles are the same

8. y=116°
   x=64°
   z=64°

9.B=131°
   x=49°

10.B=135°
     x=45°

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