Models are representations that help us understand and analyze real-life situations, but they may have limitations or assumptions that make some statements not universally true.
Models are representations of real-life situations or things that help us understand and analyze them better. However, the statement, 'all of the following are true of models except,' implies that there are some characteristics that do not apply to models. Different models may have different purposes, limitations, or assumptions that may make some statements not universally true. For example, while models can provide insights and predictions, they cannot capture the full complexity of the real world or account for all variables. Models are valuable tools in various fields and disciplines, including social studies, as they help us simplify, analyze, and communicate complex phenomena and processes.
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A. Puck
B. Oberon
C. Bottom
D. Peaseblossom
The expression for the bullet's speed vbullet is and the speed of a 9.0 g bullet is v=16.8 m/s
A bullet of mass m is fired into a block of mass m that is at rest. the block, with the bullet embedded, slides distance d across a horizontal surface. the coefficient of kinetic friction is μk.
The initial kinetic energy of the bullet is given by
where
m is the mass of the bullet
v is the initial speed of the bullet
The expression for the bullet's speed vbullet is
where
is the coefficient of kinetic friction
g is the acceleration of gravity
The work done by the force of friction is
where d is the displacement of the block+bullet.
Because the final kinetic energy is zero (the bullet with the block comes at rest), we can write:
And so
By solving for v, the solution for the bullet speed:
The speed of a 9.0 g bullet that, when fired into a 12 kg stationary wood block causes the block to slide 5.4 cm across a wood table. Assume that k=0.20.
We have:
the mass of the bullet, m = 9.0 g = 0.009 kg
the mass of the block, M = 12 kg
the distance covered by the block+bullet, d = 5.4 cm = 0.054 m
the coefficient of friction,
the acceleration of gravity,
By substituting, we got
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Answer:
SI unit for Joule per second is .
Explanation:
When a distance of 35 m is multiplied by a force of 27 N.
Force × distance = 27 N × 35 m = 945 Joule
945 Joule = 945
945 joule = 945
This is SI unit for force multiplied by distance.
The above quantity is divided by 5 s.
= 189
SI unit for Joule per second is .
Answer:
Explanation:
Here first we multiplied the force with the distance so we have
F = 27 N
distance = 35 m
so the product is given as
now we have to divide it by time
so we have
so it is
kilograms
Answer:
mass=56.12kg
Explanation:
PE=mgh
4620=m×9.8×8.4
make msubject of the formula...
m =4620/(9.8×8.4)
m=4620/82.32
m=56.12kg