Ann and Betty together have $60. Ann has $9 more than twice Betty's amount. How much money does each have?

Answers

Answer 1

Answer: first and mainly keep that 9 one side,
There are 2 people involved Ann and Betty, Then divide the TOTAL AMOUNT BY THE NUMBER OF PEOPLE.
· Then it will look like $60÷2= $30 per person.
In this case everyone has equal amount of money, but the question say Ann has $9 more than Betty's. so, Ann≈ $30 +$9= $39.
Betty≈ $30-$9= $21
Because loses money because Ann has more,
TOTAL=Ann+Betty
$60= $39+$21

Answer 2

Answer:

Final answer:

Betty has $17 and Ann has $43.

Explanation:

This problem is a basic algebraic equation. Let's denote Betty's amount as x. From the problem information, we know that Ann's amount is twice Betty's plus $9, so we can denote it as 2x + $9. It's also told in the problem that together they have $60, so we can form the equation: x (Betty's money) + 2x + $9 (Ann's money) = $60.

Solving this equation, we combine like terms, which gives us 3x + $9 = $60. Subtract $9 from both sides to get 3x = $51. Divide each side by 3, we get x = $17. So, Betty has $17. We substitute x = $17 into the equation 2x + $9 to find Ann's money, which gives us 2*$17 + $9 = $43. So, Ann has $43.

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Answers

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------- x -----   ÷ -----
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In dividing fractions. Get the reciprocal of the 2nd fraction and multiply it to the 1st fraction.

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--------------- × -------------
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---------------------- × -----------
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Answers

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Answers

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