For the values a = 2.9 which is a leg of a right triangle, and value c = 4.2, which is the hypotenuse, find the length of the other leg, b, to the nearest tenth.A. 2.9

B. 3.0

C. 2.8

D. 1.3

Answers

Answer 1
Answer: Given:
a = 2.9
c = 4.2
b = ?

Right triangle. Use Pythagorean Theorem.
a² + b² = c²
b² = c² - a²
b² = 4.2² - 2.9²
b² = 17.64 - 8.41
b² = 9.23
b = √9.23
b = 3.04  Choice B.

The length of the other leg is 3.0
Answer 2
Answer: The right one is B) 3.0, as you know a^(2) + b^(2) = c^2 due to Pythagoras' theorem. So b= √(c^2 - a^2). Put the right numbers into the formula and you get 3.0. That is B.

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What is 4x+3y=14 2y=6+4x

Answers

4x+3y=14
2y=6+4x
we can isolate the y in the second function
2y=6+4x
/2      /2
y=3+2x
then change all the y to 3+2x in first function
4x+3(3+2x)=14
4x+9+6x=14
10x=5
/10   /10
x=0.5  or 1/2
then fill the x in the function, get y.(each function will work)
2y=6+4x
2y=6+4(1/2)
2y=6+2
2y=8
y=4
x=0.5    y=4

Pls help me!!!! I don't know this.

Answers

Answer:

Step-by-step explanation: I dont know this either

If you teach me how to mark brainlest i will mark you brainlest and you will get 20 points.

Answers

Answer:

tab on it.

Step-by-step explanation:

its cost 50 to make a bracelet and 1$ to make a necklace to make a profit the total cost for bracelets and necklaces must be less than 10$ the jeweler can make no more than 14 pieces of jewelry each day write a system of inequalities to model the number of bracelets and necklaces to be made each day

Answers

b + n ≤ 14 and .50b + 1n < 10 This is because the total number of bracelets added to the total number of necklaces made each day must be less than or equal to 14. Also, the price of each bracelet (.50b) added to the price of each necklace (1n) must be less than $10.

You want to use a coordinate proof to prove that midsegment DE of ABC is parallel to AC and half the length of AC. Which is the best first step?

Answers

Answer:

the third one answer choice

Step-by-step explanation:

⊕ Place the triangle on a coordinate grid such that vertex A is at the origin, and segment AC lies on the x-axis.

You will be able to see the length of segment AC and length of segment DE, and also will be able to see if AC║DE.

Find the first six terms of the sequence. a1 = 4, an = an-1 + 8

OPTIONS ARE
a. 0, 8, 16, 24, 32, 40
b. 12, 20, 28, 36, 44, 52
c. 4, 12, 20, 28, 36, 44
d. 4, 8, 16, 24, 32, 40

Answers

The arithmetic sequence:
a 1 = 4,  a n = a n-1 + 8,  d = 8
a 2 = 4 + 8 = 12
a 3 = 12 + 8 = 20
a 4 = 20 + 8 = 28
a 5 = 28 + 8 = 36
a 6 = 36 + 8 = 44
Answer:
C ) 4, 12, 20, 28, 36, 44

Answer:

(C) 4, 12, 20, 28, 36, 44

Step-by-step explanation:

Given: a_(1)=4 and a_(n)=a_(n-1)+8

To find: Find the first six terms of the sequence

Solution: Since, it is given that a_(1)=4 and a_(n)=a_(n-1)+8, then the first term is 4 and the common difference, d=8.

Thus, the next terms are:

a_(2)=a_(1)+8=4+8=12,

a_(3)=a_(2)+8=12+8=20,

a_(4)=a_(3)+8=10+8=28,

a_(5)=a_(4)+8=28+8=36 and

a_(6)=a_(5)+8=36+8=44

Thus, the first six terms of the sequence will be 4, 12, 20, 28, 36, 44.

thus, option C is correct.