Answer:
15
Explanation:
15
2.Reducing the friction between the wagon wheels
3.Reducing the length of the wagon handle
4.Increasing the friction between the wagon wheels
Answer:
2.Reducing the friction between the wagon wheels
Explanation:
If the friction between the wagon wheels and the rail is reduced, then less force will be needed to pull the wagon up. This is because the friction force goes in the opposite direction of the movement, that is, friction force opposes the desired movement, making it more difficult.
Answer: 1.38 m/s to the right.
Explanation: We can solve this problem using the principle of conservation of momentum. The momentum of an object is defined as the product of its mass and velocity, and the total momentum of a closed system is conserved, meaning that the total momentum before a collision is equal to the total momentum after the collision.Let the initial velocity of the dart be v, and let the final velocity of the dart and the block be vf. The momentum of the dart before the collision is given by p = mv, where m is the mass of the dart. The momentum of the dart and block after the collision is given by (m + M)vf, where M is the mass of the block.Using the principle of conservation of momentum, we have:p = (m + M)vfSubstituting the given values, we get:0.012 kg v = (0.012 kg + 0.2 kg) 0.78 m/sSimplifying, we get:v = (0.212 kg) (0.78 m/s) / 0.012 kgv ≈ 1.38 m/sTherefore, the velocity of the dart just before it hits the block is approximately 1.38 m/s to the right.
14 m/s
6.0 m/s
16 m/s
Answer:
Explanation:
Linear Momentum
Two objects of masses and moving in a linear path at speeds and respectively have a total momentum of
When the objects collide, a change of conditions occurs and they start to move at different speeds. The necessary condition to find the after-colliding speeds is the conservation of linear momentum that states the total momentum of an isolated system doesn't change regardless of the internal interactions of the objects. Thus, the new momentum is
And they must be the same, thus
We know both cars stick together after the collision, so the final speed is common to both, and the above formula becomes
Solving for v'
Plugging in the values, we have
Correct option (closest to the computed speed): 14 m/s
Answer:
52.5 mph
Explanation:
part 1,
speed=40mph
distance= 40×3=120 miles
time= 3 hours
part 2
speed= 60mph
distance= 300 miles
time= 300÷60= 5hours
Average speed= (300+120)÷(5+3) = 52.5mph
The force that must be applied to stop the SUV in 8 seconds is approximately 3,487.5 Newtons (N).
To calculate the force required to stop the SUV, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) times acceleration (a). In this case, the acceleration is the change in velocity over time.
First, let's find the acceleration (a):
Acceleration (a) = (final velocity - initial velocity) / time
a = (0 m/s - 18 m/s) / 8 s
a = -18 m/s / 8 s
a = -2.25 m/s²
The negative sign indicates that the SUV is decelerating or slowing down.
Now, we have the acceleration (-2.25 m/s²) and the mass of the SUV (1,550 kg). We can use Newton's second law to find the force:
Force (F) = mass (m) x acceleration (a)
F = 1,550 kg x (-2.25 m/s²)
F = -3,487.5 N
To know more about acceleration here
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