Answer:
2943J
Explanation:
Ep = mgh
given that,
m = 15kg
h= 20m
and
g = 9.81 m/s^2
Ep= 15 × 9.81 × 20
Ep= 2943J
magnitude of Alpha Crucis is 0.77. Identify which star appears brighter when observed from
Earth. Explain your answer.
Answer:
Alpha centauri will be brighter than Alpha Crucis .
Explanation:
Apparent magnitude of a star measures how bright a star is .
This scale is reverse logarithmic ie , the brighter the star , the lower is its magnitude . A magnitude equal to 5 scale higher represents less magnitude by a factor of 1/ 100 . In this way a difference of 1 magnitude represents a brightness ratio of 2.512 . Hence a star of brightness magnitude of 7 is less bright by a factor 2.512 than that of a star magnitude of 6 .
b. large
c. small
d. unbalanced
Before solving this question first we have to understand Newton's first law of motion
As per Newton's first law it is impossible to change the state of rest or uniform motion along a straight line unless and until it is compelled by some external unbalanced forces.
Everybody tends to oppose the change of state of rest due to their inertia.A book present on a table pushes the table with its weight in vertically downward direction while table applies same amount of force on the book in vertically upward direction.The net force acting on each body is zero.So the book will show no motion.
Actually balanced force have no role in changing the state of rest of the body. Only unbalanced force will cause the body to move.
Hence the washer who does not want to change his position will want the force acting on him to be [balanced ].
Answer:
Explanation:
r = v^2 / g
where:
r is the radius of the path (in meters)
v is the speed of the car (in meters per second)
g is the acceleration due to gravity (in meters per second squared)
In this case, v = 29 m/s and g = 9.81 m/s^2. Therefore, the radius of the car's path is:
r = 29^2 / 9.81 = 82.5 meters
So the answer is 82.5