Answer:
The time required by the Athlete to work off 1.00 lb of body fat = 0.296 minute
Explanation:
1 lb of body fat = 4.1 k cal
1 k cal = 4.184 Kilo joule
1 lb of body fat = 4.1 × 4.184 = 17.1544 Kilo joule
Athlete expends 3480 Kilo joule in one hour
⇒ Time required to expand 3480 Kilo joule = 60 minute
⇒ Time required to expand 1 Kilo joule =
⇒ Time required to expand 17.1544 Kilo joule = × 17.1544 = 0.296 min
Therefore the time required by the Athlete to work off 1.00 lb of body fat = 0.296 minute
The time of motion of the car to the given distance is 5 seconds.
The given parameters;
The time of motion of the car to the given distance is determined by applying average velocity formula as shown below;
Thus, the time of motion of the car to the given distance is 5 seconds.
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Answer:
Explanation:
b. The white pot.
c. Neither—they both cool at the same rate.
Commensalism describes the interaction between the insect and the oak tree.
It is a type of biological interaction between two species in which one of the interacting species is benefitted while the other species is unaffected.
Since the insect gets a safe place to lay its egg it gains from this interaction while the tree is unaffected.
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Answer:
its D!!!
Explanation:
If the insect benefits and the tree neither benefits nor is harmed, the relationship is commensalism.
Answer:
Displacement = 1725m
Explanation:
Using the equations of motion, we find that the plane covers a distance of 850 meters while it is accelerating from a velocity of 50 m/s to 65 m/s at the rate of 0.5 m/s².
You're asking about a motion problem in physics that requires using the equations of motion to solve. In this case, the formula we would use is v² = u² + 2as, where 'v' is the final velocity, 'u' is the initial velocity, 'a' is acceleration, and 's' is the distance covered.
Given:
Initial velocity (u) = 50 m/s
Final velocity (v) = 65 m/s
Acceleration (a) = 0.5 m/s²
We are asked to find the distance covered (s). Rearranging the formula to find 's', we get: s = (v² - u²) / 2a
Substituting the given values, the distance covered (s) = (65² - 50²) / (2*0.5) = 850 meters. So, the plane covers a distance of 850 meters while it is accelerating.
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