If an athlete expends 3480. kJ/h, how long does she have to play to work off 1.00 lb of body fat? Note that the nutritional calorie (Calorie) is equivalent to 1 kcal, and one pound of body fat is equivalent to about 4.10 × 103 Calories.

Answers

Answer 1
Answer:

Answer:

The time required by the Athlete to work off 1.00 lb of body fat = 0.296 minute

Explanation:

1 lb of body fat = 4.1 k cal

1 k cal = 4.184 Kilo joule

1 lb of body fat = 4.1 × 4.184 = 17.1544 Kilo joule

Athlete expends 3480 Kilo joule in one hour

⇒ Time required to expand 3480 Kilo joule  = 60 minute

⇒ Time required to expand 1 Kilo joule = (60)/(3480)(min)/(KJ)

⇒ Time required to expand 17.1544 Kilo joule = (60)/(3480) × 17.1544 = 0.296 min

Therefore the time required by the Athlete to work off 1.00 lb of body fat = 0.296 minute


Related Questions

Mass is measured using _____.scalesa triple beam balancea mass meterall of the above
What is the net force and acceleration of a ball of mass 0.750 kilograms that is subjected to forces of 11.00 newtons and 7.00 newtons from opposite directions?
What does the photoelectric effect prove?
Discuss how lawmakers could use scientific knowledge to help them make decisions that would benefit society.
When Ava first opened her beverage, there were lots of bubbles. However, as her drink got warmer, she noticed that there were fewer bubbles in it. In general, as the temperature increases, the solubility of solids _______ while the solubility of gases _______. 1) increases, decreases 2) increases, increases 3) decreases, decreases 4) decreases, increases

A car accelerates uniformly from +10.0 m/s to +40.0 m/s over a distance of 125 m. How long did it take to go that distance? Show all your work, including the equation used, given and unknown quantities, and any algebra required. Make sure your answer has the correct number of significant figures.

Answers

The time of motion of the car to the given distance is 5 seconds.

The given parameters;

  • initial velocity of the car, u = 10 m/s
  • final velocity of the car, v = 40 ms/
  • distance traveled by the car, s = 125 m

The time of motion of the car to the given distance is determined by applying average velocity formula as shown below;

s = ((u+ v)/(2) )t\n\n125 = ((10 + 40)/(2) )t\n\n125 = 25t\n\nt = (125)/(25) \n\nt = 5 \ s

Thus, the time of motion of the car to the given distance is 5 seconds.

Learn more here:brainly.com/question/18297834

Answer:

Explanation:

v^2-u^2=2as\n40^2-10^2=2a*125\n1600-100=250a\na=(1500)/(250)=6~m/s^2\nv=u+at\n40=10+6t\n6t=30\n t=(30)/(6)=5 ~s

Two pots are filled with boiling water. The pots are exactly the same size, but one pot is white and the other is black. Which pots cools faster?a. The black pot.
b. The white pot.
c. Neither—they both cool at the same rate.

Answers

The correct answer for the question that is being presented above is this one: "c. Neither—they both cool at the same rate."Two pots are filled with boiling water. The pots are exactly the same size, but one pot is white and the other is black. c. Neither—they both cool at the same rate.

A species of insect is newly introduced into the United States from the Philippines. This insect becomes established, laying its eggs on the leaves of oak trees. How can a biologist determine if the relationship between the insect and the oak tree is commensalism, mutualism, or parasitism?

Answers

Commensalism describes the interaction between the insect and the oak tree.

What is commensalism?

It is a type of biological interaction between two species in which one of the interacting species is benefitted while the other species is unaffected.

How is the above interaction commensalism?

Since the insect gets a safe place to lay its egg it gains from this interaction while the tree is unaffected.

When will this interaction be a mutualism interaction?

  • When both the organisms benefit from the interaction.
  • If the insect helps in the pollination of the tree while the insect gets a safe place to lay its egg.

When will this interaction be a parasitic interaction?

  • When one of the organism benefit at the expense of the other.
  • For example, If the insect sucks the sap of the tree on which it lays its egg. The insect benefits while the tree is harmed.

To learn more about biological interaction, species, and commensalism here,

brainly.com/question/14224704

#SPJ2

Answer:

its D!!!

Explanation:

If the insect benefits and the tree neither benefits nor is harmed, the relationship is commensalism.

What word describes the position in the moon's elliptical orbit when it is closest to Earth?

Answers

That's the moon's perigee.

a plane is traveling at a velocity of 50 m/s. it accelerates at a constant rate of 0.5 m/s until it's velocity reaches 65 m/s. what distance did the plane cover while it was accelerating?

Answers

Answer:

Displacement = 1725m

Explanation:

t = (u-v)/(a)

t = (65-50)/(0.5)  = 30s

s = ut+(1)/(2)at^(2) \ns = 50*30 + (1)/(2) *0.5*30^(2)  = 1725m

Final answer:

Using the equations of motion, we find that the plane covers a distance of 850 meters while it is accelerating from a velocity of 50 m/s to 65 m/s at the rate of 0.5 m/s².

Explanation:

You're asking about a motion problem in physics that requires using the equations of motion to solve. In this case, the formula we would use is v² = u² + 2as, where 'v' is the final velocity, 'u' is the initial velocity, 'a' is acceleration, and 's' is the distance covered.

Given:
Initial velocity (u) = 50 m/s
Final velocity (v) = 65 m/s
Acceleration (a) = 0.5 m/s²

We are asked to find the distance covered (s). Rearranging the formula to find 's', we get: s = (v² - u²) / 2a

Substituting the given values, the distance covered (s) = (65² - 50²) / (2*0.5) = 850 meters. So, the plane covers a distance of 850 meters while it is accelerating.

Learn more about Equations of Motion here:

brainly.com/question/35709307

#SPJ2

Our topic at school is light- What is dispersion, diffusion, refraction and reflection?

Answers

Dispersion-Distributing something over an area.Diffusion-the scattering of light by reflection from a rough surface.
Refraction-Turning or bending of any wave.
Reflection- Image.