Answer:
This is because even when the quality of the variable x is 0, the value of b still exists and is the starting point for y.
Step-by-step explanation:
To prove this, we start with the base form of the equation and input 0 for x.
y = mx + b
y = m(0) + b
y = 0 + b
y = b
Price of an adult ticket is $6
Explanation:
7 adult tickets and 12 child tickets are equivalent to
(7 + 2/3 ⋅ 12) = 7 + 8 = 15 adult tickets.
So the price of an adult ticket is 90/ 15= $6
First, you must know what 5^2 and 5^3 are equal to.
5^2 = 5 * 5 = 25
5^3 = 5 * 5 * 5 = 125
If x^2 is equal to 25, x = 5. If x^2 is greater than 25, x > 5. If x^2 is less than 25, then x < 5.
If x^3 is equal to 125, x = 5. If x^3 is greater than 125, x > 5. If x^3 is less than 125, then x < 5.
x^3 = 15; x < 5
x^2 = 25; x = 5
x^3 = 36; x < 5
x^2 = 49; x < 5
x^2 = 50; x > 5
x^3 = 125; x = 5
Answer:
Since 0 in ln(3x) - 0 is not a logarithm, the property of logarithms cannot be used here.
The difference shown cannot be written as a quotient of logarithms.
The step ln(x2) = ln(3x) - (0) reduces to
ln(x2) = ln(3x).
The possible solutions are 0 and 3, with 0 being extraneous.
Step-by-step explanation:
on edg
(y-3)^2=4y-12
(y-3)²=4y-12
First we need to start by subtract 4y-12 from both sides
y²-6y+9-(4y-12)= 4y-12-(4y-12)
y²-10y+21=0
Now we need to do the factorization of the equation
we gonna factor the left side of it
(y-3)(y-7)=0
Set factors equal to 0
y-3=0 or y-7=0
y=3 or y=7
I hope that's help :0