Phosphofructokinase is an important control enzyme in the regulation of cellular respiration. Which of the following statements correctly describes phosphofructokinase activity? A) It is inhibited by AMP.
B) It is activated by ATP.
C) It is activated by citrate, an intermediate of the citric acid cycle.
D) It catalyzes the conversion of fructose 1,6-bisphosphate to fructose 6-phosphate, an early step of glycolysis.
E) It is an allosteric enzyme.

Answers

Answer 1

Answer: The answer is E) It is an allosteric enzyme.

Phosphofructokinase changes it conformational ensemble when is bound to an effector. This suggests that it is an allosteric enzyme. It is activated by AMP, and inhibited by ATP and citrate. It catalyzes the conversion of fructose 6-phosphate to fructose 1,6-bisphosphate.

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Answers

I think the correct answer from the choices listed above is option D. The thing that can be evident on a karyotype but not seed on a pedigree would be that the presence of a visual image of a chromosomal defect. Hope this answers the question. Have a nice day.

Answer:

The correct answer would be D. a visual image of a chromosomal defect.

Karyotype is defined as a visual display of the number and appearance of all the chromosome present in the cell.

It is used to detect any chromosomal abnormality such as a change in chromosome number, change in chromosome set, malformed chromosome et cetera.

In contrast, a pedigree chart is a diagrammatic representation of phenotype or appearance of a particular gene in a number of generations.

it shows the family history of the genetic disorder, risk of that disorder in an offspring, et cetera.

A box with a mass of 7 kilograms is pushed up a ramp to a height of 5 meters. what is the work done against the force of gravity? assume the ramp has negligible friction.

Answers

Answer: The work done by the ramp against the force of gravity is -343 J

Explanation:

Work is defined as the force that is causing the movement or displacement of an object.

Mathematically,

$W=F* d$

We know that:

$F=m* g$

where,

W = work done by the ramp = ?

m = mass of the box = 7 kg

g = acceleration due to gravity = $-9.8m/s^2$ (Negative sign appears because it is acting against the gravity)

d = displacement = 5 m

Putting values in above equation, we get:

$W=7kg* (-9.8m/s^2)* 5m\n\nW=-343J$

Hence, the work done by the ramp against the force of gravity is -343 J

so work done = mgh = 7×10×5 = 350 joules

so answer is 350 joules !!

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Answers

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Answers

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Answers

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Answers

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