Which are associated with nuclear fission but are not associated with nuclear fusion? Check all that apply. neutrons striking nuclei two small nuclei joining together the release of large amounts of energy a single large nucleus breaking apart two small nuclei forming

Answers

Answer 1
Answer:

Answer:

neutrons striking nuclei

a single large nucleus breaking apart

two small nuclei forming

Explanation:

- Nuclear fission occurs when a large, unstable nucleus absorbs a slow-moving neutron and breaks apart into two smaller nuclei + additional neutrons. In the process, the mass of the final product is smaller than the mass of the initial nucleus, so this mass difference is converted into a large amount of energy, according to Einstein's equation:

E=\Delta m c^2

- Nuclear fusion occurs when two small nuclei join together forming a larger nucleus. In the process, the mass of the final nucleus is smaller than the sum of the masses of the initial nucleu, so this mass difference is converted into a large amount of energy, according to Einstein's equation:

E=\Delta m c^2


We can now analyze each statement and see which one is valid only for nuclear fission:

neutrons striking nuclei --> valid only for nuclear fission

two small nuclei joining together --> valid only for nuclear fusion

the release of large amounts of energy --> valid for both fission and fusion

a single large nucleus breaking apart --> valid only for nuclear fission

two small nuclei forming --> valid only for nuclear fission

Answer 2
Answer:

Answer:

A, D, E

Edge. 2023

Explanation:

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66. Calculate the displacement and velocity at times of (a) 0.500 s, (b) 1.00 s, (c) 1.50 s, and (d) 2.00 s for a ball thrown straight up with an initial velocity of 15.0 m/s.

Answers

Answer:

a) t=1s

y = 10.1m

v=5.2m/s

b) t=1.5s

y =11.475 m

v=0.3m/s

c) t=2s

y =10.4 m

v=-4.6m/s  (The minus sign (-) indicates that the ball is already going down)

Explanation:

Conceptual analysis

We apply the free fall formula for position (y) and speed (v) at any time (t).

As gravity opposes movement the sign in the equations is negative.:  

y = vi*t - ½ g*t2 Equation 1

v=vit-g*t  Equation 2

y: The vertical distance the ball moves at time t  

vi: Initial speed

g= acceleration due to gravity

v= Speed the ball moves at time t  

Known information

We know the following data:

Vi=15 m / s

g =9.8 (m)/(s^(2) )

t=1s ,1.5s,2s

Development of problem

We replace t in the equations (1) and (2)  

a) t=1s

y = 15*1 - ½ 9.8*1^(2)=15-4.9=10.1m

v=15-9.8*1 =15-9.8 =5.2m/s

b) t=1.5s

y = 15*1.5 - ½ 9.8*1.5^(2)=22.5-11.025=11.475 m

v=15-9.8*1.5 =15-14.7=0.3m/s

c) t=2s

y = 15*2 - ½ 9.8*2^(2)= 30-19.6=10.4 m

v=15-9.8*2 =15-19.6=-4.6m/s  (The minus sign (-) indicates that the ball is already going down)

an object with a mass of 70 kilograms is supported at a height 8 meters above the ground . whats the potential energy of the object with respect to the ground?....A...560 J ...B... 3,430 J...C...5,488.... D...2,058 J

Answers

As per the question the mass of the object is given as 70 kg.

The height of the object from ground is 8 m.

We are asked to calculate the potential energy of that object.

The potential energy of a object is the energy gained by the body due to its position or configuration. The energy due to the position of object from the surface is called gravitational potential energy .

If a body of mass m is at a height of h from the ground,then its potential energy is calculated as -

                               potential energy [P.E]= mgh

where g is the acceleration due to gravity.

    we have been given h= 8 m and m= 70 kg

we know that acceleration due to gravity g =9. 8 m/s^2

                                        ⇒P.E =70 kg *9.8 m/s^2*8 m

                                                    =5488 Joule

Here Joule is the unit of energy.


using the formula E = m* g*h the answer is C...5,488 J. BTW m is mass g is gravitational pull ( 9.8 )and h is height above ground

Maurice directs a beam of light on a sheet of glass at an angle of 51°. What is the angle of refraction in the glass? The refractive index of glass is 1.46.A: 22 degrees
B: 29 degrees
C: 32 degrees
D: 36 degrees

Answers

Answer:

Angle of refraction in the glass is 32 degrees

Explanation:

It is given that,

Maurice directs a beam of light on a sheet of glass at an angle, θ₁ = 51°

The refractive index of the glass is, n₂ = 1.46

We know that the refractive index of the air is, n₁ = 1

We have to find angle of refraction in glass i.e. θ₂

According to Snell's law :

(n_1)/(n_2)=(sin\ \theta_2)/(sin\ \theta_1)

Putting all the values we get :

(1)/(1.46)=(sin\ \theta_2)/(sin51)  

\theta_2=sin^(-1)((sin(51))/(1.46))

\theta_2=32\ ^0

Hence, the correct option is (c) " 32 degrees ".  

Maurice directs a beam of light on a sheet of glass at an angle of 51°. The refractive index of glass is 1.46. The angle of refraction in the glass is 29 degrees. The answer is letter B.

If light travels from oil (slower medium) to water (faster medium) at an angle, what happens to the direction of the light ray in water with respect to normal?A. It moves away from the normal. B. It moves toward the normal.
C. It will move along the normal. D. It will move perpendicular to the normal.
E. It stops traveling.

Answers

If light travels from oil to water at an angle, what happens to the direction of the light ray in water with respect to the normal, is it moves away from the normal.

Answer:

to shorten the other answer...its A

Explanation:

In a nuclear fusion reaction, what state is matter in?a. gas
b. solid
c. liquid
d. plasma

Answers

the matter is in chemical plasma
 

Alternatively d)


I hope I was helpfull




Answer:

plasma

Expl

This other guy said it was plasma

What is the speed of a swimmer if she covers 100m in 60 seconds?

Answers

To calculate the speed of a swimmer, you can use the formula:

Speed = Distance / Time

In this case, the distance covered is 100 meters, and the time taken is 60 seconds.

Speed = 100 meters / 60 seconds = 1.67 meters per second

So, the speed of the swimmer is approximately 1.67 meters per second.
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