A rectangular swimming pool is 25 ft long and 20 1/2 ft wide, and it must be filled to a depth of 4 1/2 ft. One cubic foot of water is equal to 7 1/2 gallons. How many gallons of water will it take to fill the pool?​

Answers

Answer 1
Answer:

ANSWER

307½ gallons of water

EXPLANATION

The volume of the rectangular swimming pool is

V = l * w * h

where l=25ft and w=20½ ft.

when it is filled to a depth of 4½ ft ,then the height is , h=4½ ft.

We substitute these values into the formula to get:

V = 25* 20.5* 4.5

V = 2306.25 {ft}^(3)

If one cubic foot of water is 7½ gallons, then 2306.25 cubic feet will be

(2306.25)/(7.5)  = 307.5gallons

We need 307.5 gallons of water to fill the pool.


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What is the mode of the data set?
23 95 100 23 100 100

Answers

Go to the second pic for your answer. I got problem 4 wrong but it shows the correct answer.

The mode would be 100

2x + 7 = x + 3 what is X ?

Answers

2x + 7 = x + 3

First, subtract x from both sides. / Your problem should look like: 2x + 7 - x = 3
Second, simplify 2x + 7 - x to x + 7. / Your problem should look like: x + 7 = 3
Third, subtract 7 from both sides. / Your problem should look like: x = 3 - 7
Fourth, subtract 3 - 7 to get -4. / Your problem should look like: x = -4

Answer: x = -4

x = -4 

2x+7 = x+3
 - x       -x
_________
1x+7 = 3
     -7   -7
_________
      x = -4



Given the function f(x)=0.5(3)^x, what is the value of f^-1(7)?

Answers

f\left( x \right) =\frac { 1 }{ 2 } \cdot { 3 }^( x )\n \n \frac { 1 }{ 2 } \cdot { 3 }^( x )=y

\n \n 2\cdot \frac { 1 }{ 2 } \cdot { 3 }^( x )=2\cdot y\n \n { 3 }^( x )=2y\n \n \log _( 3 ){ \left( 2y \right)  } =x

\n \n \therefore \quad { f }^( -1 )\left( x \right) =\log _( 3 ){ \left( 2x \right)  }

\n \n \therefore \quad { f }^( -1 )\left( 7 \right) =\log _( 3 ){ \left( 2\cdot 7 \right)  } =\log _( 3 ){ 14 }

Explain in your own words why (x y)2 ≠ x2 y2. Provide a numerical example to illustrate.

Answers

I believe I misread the question but I don't know how to delete this. Sorry!

Y-1=5/6(x-4) in standard form

Answers

           y - 1 = ⁵/₆(x - 4)
           y - 1 = ⁵/₆(x) - ⁵/₆(4)
           y - 1 = ⁵/₆x - 3¹/₃
             + 1         + 1
                 y = ⁵/₆x - 2¹/₃
        ⁻⁵/₆x + y = ⁵/₆x - ⁵/₆x - 2¹/₃
   -6(⁻⁵/₆x + y) = -6(-2¹/₃)
-6(⁻⁵/₆x) - 6(y) = 14
         5x - 6y = 14
If you would like to write the equation Y - 1 = 5/6 * (x - 4) in standard form, you can do this using the following steps:

Y - 1 = 5/6 * (x - 4)
Y - 1 = 5/6 * x - 5/6 * 4
Y - 1 = 5/6 * x - 10/3
Y - 5/6 * x = 1 - 10/3
Y - 5/6 * x = - 7/3       /*6
6 * Y - 5 * x = - 14

The correct result would be 6 * Y - 5 * x = - 14.

One of two complementary angles is 4 degrees more than the other. Find the angles. (Recall that complementary angles are angles whose sum is 90 degrees.)Which of the following equations can not be used to solve the problem if x represents one of the angles?

Answers

   
\displaystyle \n \alpha + \beta = 90^o \n \alpha - \beta = 4^o \n \texttt{----------- } + \n 2\alpha ~~/~= 94^o \n \n \alpha = (94)/(2) = \boxed{47^o}\n \n \beta = 90 -\alpha = 90 - 47 = \boxed{43^o}