Answer:
LM = 2(MP)
Step-by-step explanation:
The radius KN is perpendicular to LM meaning that the line is split in half at the crossing. Review properties of circles to see why this is true.
Since we know this, we can say LM = LP + MP. And LP = MP.
So we can say LM = 2(MP).
Cheers
A.29
B.39
C.41
D.65
Answer:
B
Step-by-step explanation:
52
-
13
39
To find the value of k such that (k, k) is equidistant from (-2, 0) and (0, 5), we can use the distance formula.
The distance between two points (x1, y1) and (x2, y2) is given by the formula:
Distance = √((x2 - x1)² + (y2 - y1)²)
Let's calculate the distances from (k, k) to (-2, 0) and (0, 5) and set them equal to each other:
√((k - (-2))² + (k - 0)²) = √((k - 0)² + (k - 5)²)
Simplifying this equation:
√((k + 2)² + k²) = √(k² + (k - 5)²)
Squaring both sides of the equation to eliminate the square roots:
(k + 2)² + k² = k² + (k - 5)²
Expanding and simplifying:
k² + 4k + 4 + k² = k² + k² - 10k + 25
2k² + 4k + 4 = 2k² - 10k + 25
Rearranging terms:
4k + 4 = -10k + 25
Combining like terms:
14k = 21
Dividing both sides by 14:
k = 21 / 14
Simplifying the fraction:
k = 3 / 2
Therefore, the value of k that makes (k, k) equidistant from (-2, 0) and (0, 5) is k = 3/2.
4a+4b+4c
2x + 3y = -16
What is the solution
Answer:
x=-5
y=-2
Step-by-step explanation:
equation 1 - equation 2
(2x-4y=-2) - (2x+3y=-16) = (-7y=14)
y=14/-7=-2
then substitute y=-2 into any equation
2x-4(-2)=-2
2x+8=-2
2x=-10
x=-10/2=-5
x = −8
y = 10
x = 2