For this case, we have that by definition, in a parallelogram, the opposite angles are congruent, that is, they are equal. So, given the measurements of two opposite angles of a parallelogram, we have:
Clearing "n":
Subtract "n" from both sides of the equation:
We subtract 30 from both sides of the equation:
Thus, the value of n is 15.
Answer:
Opposite angles in parallelogram are equal so the answer will be;
2n+30=n+45
2n-n=45-30
n=15
B. 42 mm3
C. 1176 mm3
D. 196 mm3
the correct answer is A.
Answer:
2:5 I think
Step-by-step explanation:
Class A: {2, 5, 7, 6, 4, 3, 8, 7, 4, 5, 7, 6, 3, 5, 4, 2, 4, 6, 3, 5}
Class B: {3, 7, 6, 4, 3, 2, 4, 5, 6, 7, 2, 2, 2, 3, 4, 5, 2, 2, 5, 6}
Which statement is true for the data sets?
A.
The mean study time of students in Class A is less than students in Class B.
B.
The mean study time of students in Class B is less than students in Class A.
C.
The median study time of students in Class B is greater than students in Class A.
D.
The range of study time of students in Class A is less than students in Class B.
E.
The mean and median study time of students in Class A and Class B is equal.
Answer:
b
because the mean refers to the most recurring numeral and in b it is two recurring about 5 times
f(x) = (x + 2)2 + three fourths
f(x) = −(x − 2)2 + three fourths
f(x) = −(x − 2)2 − three fourths
Answer:
f(x) = −(x − 2)2 − three fourths
Step-by-step explanation:
Answer:
~91 chirps/min
Step-by-step explanation:
This exercise is asking us to estimate based on the values in the table. If we know the temperature is 65°F, let's find the closest values given to interpolate (assuming the data is fairly linear, which it appears to be).
Looks like the closest ones are 60° and 68°. We will look at their corresponding chirps/min and guess a number in between those two.
60° -> 81 chirps/min
68° -> 97 chirps/min
Because 65 is closer to 68 than 60, we expect our result to be closer to 97 than 81.
slope = rise/run
= = 2 chirps/min/°F. So for every °F increase, we expect to increase by 2 chirps/min.
60+5 = 65, so let's add 2*5 = 10 chirps/min to 60 to get 91 chirps/min. This corresponds with what we would have guessed.