James started tutoring children several times a week. The first 2 weeks he had to purchase tutoring supplies and had losses of $40 and $65. The next 3 weeks he made a profit of $105, $70, and $140. At the end of the 6 weeks, he had a net profit of $252.1. Write an equation to find the profit or loss for the 6th week in this situation.

2. Solve your equation.

3. Was there a profit or a loss for that week?

4. What was James's average profit or loss for the 6 weeks?

Answers

Answer 1
Answer: He lost 252-6=246
he has $246 but he spent that so he would have $41
246 divided by 6=$41

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Here is a picture of a math problem.
the radius and height of a cylinder are in the ratio 5:7.if it's volume is 4400cm cube, find the radius of the cylinder

A bus travels through the city and stops every mile. The first stop on the route is the 8th Avenue Coffee Shop, which is located 15 blocks east and 22 blocks north of the central station. The last stop on the route is the airport, which is located 25 blocks west and 36 blocks south of the central station. A student calculated the middle stop along the bus route to be located 20 blocks east and 29 blocks north of the central station. Evaluate the student’s answer.

Answers

Answer:Student calculation is incorrect

Step-by-step explanation :

Given the First stop is the 8th Avenue Coffee Shop, which is located 15 Blocks east and 22 blocks north of the central station

and the last stop on the route is 25 blocks west and 36 blocks south of the central station .

Lets take the First stop co-ordinates be (15,22)

and last stop co-ordinates (-25,-30)

So there mid-point is x=(x_1+x_2)/(2)

y=(y_1+y_2)/(2)

x=(15-25)/(2)=-5

y=(22-30)/(2)=-4

Therefore middle stop is 5 blocks west and 4 blocks South

Thus calculated the middle stop incorrectly.

The student apparently added numbers without taking into account direction. They seem to have added 15 and 25 and divided by 2 to get the horizontal component of the middle stop when they should have added 15 and -25 and divided by 2. A similar mistake was made on determining the vertical component. The middle stop should have been calculated as 5 blocks west and 7 blocks south of the central station. So your answer is C.

PLEASE HELP i really need the answer asap

Answers

Answer:

its 16

Step-by-step explanation:

8 /x = 10/20

20 * 8 =160

10 * x =10x

10x = 160

x=16

The answer is
X is 16

Yesterday, the snow was 2 feet deep in front of Archie’s house. Today, the snow depth dropped to 1.6 feet because the day is so warm. What is the percent change in the depth of the snow?

Answers

earlier snow depth = 2 feet
later snow depth = 1.6 feet

change 
2 - 1.6
0.4 feet

percentage change
(0.4 / 2) * 100
20 %
The correct answer of this question is 20%.
The given values are the initial depth of snow which is 2 feet and the final depth which is 1.6 feet.
The solution of the problem is:
2 ft. - 1.6 ft. = 0.4 ft.
0.4 ft. / 2 ft. = 0.2
To calculate for the percentage,
0.2 x 100% = 20%

(2ײ -׳-18ײ-7÷(×+2)
i need solution and explanation​

Answers

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The quotient is equal to :

  • -  {x}^(2)  - 14x + 28

remainder :

  • - 63

Solution is in attachment ~

Answer:

{ \rm{( {2x}^(2) -  {x}^(3)  - 18 {x}^(2) - 7) / (x + 2)  }}

• now, (x + 2) is the factor.

• let's find the value of xfrom the factor:

{ \rm{x + 2 = 0}} \n { \underline{ \rm{ \:  \: x =  - 2 \:  \: }}}

• let's substitute for xinto the quotient:

{ \rm{f(x) =  {2x}^(2) -  {x}^(3)  -  {18x}^(2) - 7  }} \n  \n { \rm{f( - 2) = 2 {( - 2)}^(2) -  {( - 2)}^(3) - 18 {( - 2)}^(2)  - 7  }} \n  \n { \rm{f( - 2) = 8 +8 - 72 - 7}} \n  \n { \boxed{ \boxed{ \pmb{answer \:  \dashrightarrow \:  \:  {}^( - ) 63 \:  \: }}}}

Divide 7/24 by 35/48 and reduce the quotient to the lowest fraction

Answers

(7)/(24) ÷ (35)/(48)
Multiply (7)/(24) by the reciprocal of (35)/(48), which is (48)/(35)

=(7)/(24) × (48)/(35)
=(336)/(840)

We can simplify it further:
The greatest common factor here is 168
(336/168)/(840/168)

=(2)/(5)

Help pleaseee! Thank you

Answers

Answer:

Step-by-step explanation:

width of a rectangle=11 cm=11*5=55 ft

length of  rectangle =8 cm= 8*5=40

Area=55*40=2220 ft²

height=3 cm=3*5=15

base=11 cm=11*5=55

Area of a triangle=base*height/2=15*55/2= ft^2

2220+412.5=2632.5 ft^2

this number is close to 2615 if the square unit on the grid =1 cm