Bob and sarah need to paint a fence. bob can paint the fence in 4 hours and sarah can paint the fence in 2.5 hours. if they work together, how long will it take them to paint the fence?

Answers

Answer 1

Answer: If Bob can paint the fence in 4 hours, then in 1 hour he gets 1/4 of the fence painted. If Sarah can paint the fence in 2.5 hours, then she gets 2/5 of the fence painted in one hour (1/2.5 = 2/5). We add those amounts together and set them equal to 1/x, x being the the total time it will take them to paint the whole fence. 1/4 + 2/5 = 1/x. Find a common denominator first, then add the left side together. 5/20 + 8/20 = 1/x. 13/20 = 1/x. Cross-multiply to get 13x = 20 and x = 1.54 hours, just a bit over an hour and a half.

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Determine whether the following problem involves a permutation or combination. (It is not necessary to solve the problem.) How many different 33-letter passwords can be formed from the letters Upper QQ, Upper RR, Upper SS, Upper TT, Upper UU, Upper VV, and Upper WW if no repetition of letters is allowed?
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Which of the following describes the translation of y = |x| to y = |x + 7| - 2

Simplity
4x2 – 3x + 7 + 2x2 + 4x

Answers

Answer:

6x^2+x+7

Step-by-step explanation:

4x^2-3x+7+2x^2+4x

4x^2+2x^2+4x-3x+7

6x^2+x+7

Suppose you have two different linear equations. How would you tell if the lines represented are parallel, perpendicular, or neither?

Answers

parallel never cross
perpendicular is a 90 degree angle
its neither if its not 90 degree or never crossing

if the letters of the word 'MOTHER'are written in all possible order and these words are written out as in dictionary ,find the rank of the word 'MOTHER'.

Answers

There are 6 letters, each different
Before MOTHER, words from E , H will come
Words from E = 5! (there are 5 letters to arrange)
Words from H = 5!( there are 5 letters to arrange)

Now words starting by M will come.
First ME will have = 4! (as 4 letters will be arranged)
Then MH = 4!
Now words with MO
First words starting with MOE... =3!
And words starting with MOH... =3!
the words starting with MOR... =3!

Now, words starting from MOT will come
words starting with MOTE.. = 2!
then after words starting from MOTH will come and first word will MOTHER

so, total no. of words before MOTHER = 5! + 5! + 2* 4! + 3 * 3!
= 120 +120 + 48 + 18
= 306
so, rank of MOTHER = 307

5x^2+3x-6x^3+4x^2+2x^3-x+10 when this polynomial is simplified, what is the coefficient of x^3?

Answers

The polynomial would simplify to:
-4x^3 + 9x^2 + 2x + 10
Therefore the coefficient of x^3 would be -4.

2 tbsp peanut butter is how many servings of oil?

Answers

Answer:104 grams

Step-by-step explanation:

Triangles L O N and L M N share common side L N. Angles O L N and N L M are congruent. What additional information would be needed to prove that the triangles are congruent using the ASA congruence theorem? ON ≅ MN ∠LON ≅ ∠LMN LN ≅ NM ∠LNO ≅ ∠LNM

Answers

The additional information required to prove that the triangles are congruent using the ASAcongruence theorem is; ∠LNO ≅ ∠LNM

We are given that;

△LON and △LMN share a common side LN.

This means that for both triangles LN = LN by reflexive property as LN is congruent to itself.

Secondly, we are told that;

∠OLN and ∠NLM are congruent.

We can see that L is an included angle of the congruent side LN.

Now, ASA congruency means Angle - Side - Angle. That means two congruent angles and the included side.

Thus, we need one more angle of the included side LN.

We already have for L, and so the remaining angles that will make△LON and △LMN congruent are;∠LNO and ∠LNM.

Read more on ASA Congruence at; brainly.com/question/3168048

Answer:

The answer is " $\bold{\Delta LNO \cong \Delta LMN \ if\ \angle LNO = \angle LNM}$ "

Step-by-step explanation:

Two angles will be congruent to each other in order to show ASA congruence between all the triangles. Its angle $\angle LNO \cong \angle LNM$ is a common angle in both triangles As a result, we'll use the ASA congruence law to show that perhaps the triangles are congruent.

$In\ \Delta LON \ and \ \Delta LMN \n\n Side\ \ ON \cong Side\ \ MN \n\n\angle LNO \cong \angle LNM ( \because common ) \n\n \angle LON \cong \angle LMN (\because Given ) \n\n\to \Delta LON \cong \Delta LMN \text{( through the ASA congruence theorem)}\n$

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