Answer:
STRING held by the man
Explanation:
Wave is defined as a disturbance that travels through a MEDIUM and transfer energy from one point to another without causing any permanent displacement of the medium itself.
The medium through which wave travels varies e.g water, string, air etc
According to the diagram, wave travels through the string held by the man. This string is referred to as the MEDIUM through which the wave moves. The wave generated produces both crest (D) and trough (C) when displaced from its initial position (A)
Rope or one could consider it to be C to B or A to D
Answer:
24km/h
Explanation:
go it right on ingenuity 2020
A. Energy
B. The rope
C. The athlete
D. Air
Answer:
It would be B. The Rope
Explanation:
I say this because the rope is transferring energy from one location to another. Now, I could be totally wrong on this but I think this is right lol.
Answer:
The answer is B the rope.
Hope this helps <3 ;)
Answer:
37.5 J
Explanation:
With work done equation: W=Fs
W=75*0.50=37.5 J
or use mgh=(75)(0.5) which is the same
m
(b) If each holds one end of a rope, and the man pulls on the rope so that he moves 1.3 m, how far from the woman will he be now?
m
(c) How far will the man have moved when he collides with the woman?
m
Answer:
Given that
m₁ = 50 kg
m₂=80 kg
d= 12 m
a)
We know that center of mass given as
X = (x₁m₁+x₂m₂)/(m₁+m₂)
Lets take distance of CM from woman is X
So now by putting the value
X = (0 x 50+12 x 80)/(50+80)
x=7.38 m
b)
There is no any external force so the CM will not move.
So we can say that
x₁m₁+x₂m₂ = 0
50(x) - 80(1.3)=0
x=2.08
So the distance move by woman d=12-2.08-1.3=8.62 m
d=8.62 m
c) lets take distance move by man is x
50 (x) - 80 (12-x) =0
x=7.38
So the distance move by woman d=12-7.38
d=4.62 m
It is shared electrons.
The following information should be considered:
learn more: brainly.com/question/2514933?referrer=searchResults
Answer:
try electrons i hope this helps!!
Explanation:
Answer:
115 ⁰C
Explanation:
Step 1: The heat needed to melt the solid at its melting point will come from the warmer water sample. This implies
-----eqution 1
where,
is the heat absorbed by the solid at 0⁰C
is the heat absorbed by the liquid at 0⁰C
the heat lost by the warmer water sample
Important equations to be used in solving this problem
, where -----equation 2
q is heat absorbed/lost
m is mass of the sample
c is specific heat of water, = 4.18 J/0⁰C
is change in temperature
Again,
-------equation 3
where,
q is heat absorbed
n is the number of moles of water
tex]\delta {_f_u_s}[/tex] is the molar heat of fusion of water, = 6.01 kJ/mol
Step 2: calculate how many moles of water you have in the 100.0-g sample
Step 3: calculate how much heat is needed to allow the sample to go from solid at 218⁰C to liquid at 0⁰C
This means that equation (1) becomes
79.13 KJ +
Step 4: calculate the final temperature of the water
Substitute in the values; we will have,
79.13 kJ + 990.66J* = -1463J*
Convert the joules to kilo-joules to get
79.13 kJ + 0.99066KJ* = -1.463KJ*
collect like terms,
2.45366 = 283.133
∴ = 115.4 ⁰C
Approximately the final temperature of the mixture is 115 ⁰C