Someone help me with this algebra 2 question
Someone help me with this algebra 2 question - 1

Answers

Answer 1
Answer:

We know that if Two Complex Numbers (p + qi) and (a + bi) are said to be Equal then (p = a) and (q = b)

Given : (2x + 5) + (1 - y)i = -3 - 4i

⇒ 2x + 5 = -3

⇒ 2x = -3 - 5

⇒ 2x = -8

⇒ x = -4

Option 2 is the Answer

Answer 2
Answer:

2x + 5 + i - yi = -3 - 4i

2x - yi = -8 - 5i

2x = -8 - 5i - yi

2x = -8 -i(5-y)

2(-4) = -8 -i(5-y)

0 = -i(5-y)

0 = 5 - y

-y = -5

y = 5

If x = -4, y is a real number.


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Three weeks ago John bought stock at 49 1/4; today the stock is valued at 49 7/8. We could say the stock is performing at which of the following?A. On par B. Par equality C. Above par D. Below par

Increase £84 by 3%
thank you!

Answers

If you would like to increase £84 by 3%, you can calculate this using the following steps:

3% * £84 = 3/100 * 84 = £2.52

£84 + £2.52 = £86.52

The correct result is £86.52.

Large chocolate bar has a base area of 48.96 square feet and its length is 0.6 foot shorter than twice its width. Find the length and width 

Answers

The length and the width of the bar are 6.7ft and 7.3ft respectively

The formula for calculating the volume of the chocolate bar is expressed as:

  • V = Base area * height

Given the following parameters

  • Base area = 48.96 square feet
  • B = length * width
  • 48.96 square feet = lw

If the length is 0.6 foot shorter than twice its width, hence;

l = w - 0.6

The expression becomes;

48.96 = w(w-0.6)\n48.96 = w^2 - 0.6w\nw^2 - 0.6w - 48.96 - 0

On factorizing the result, w = 7.3ft

Recall that l = w - 0.6

l = 7.3 - 0.6

l = 6.7ft

Hence the length and the width of the bar are 6.7ft and 7.3ft respectively.

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Answer:

Length=9.6

Width=5.1

Step-by-step explanation:

Step one:

given data

for the large chocolate

Area=48.96ft^2

let the width be x

w=xft

let the length be l

l=(2x-0.6)

Step two:

we know that area A=length * width

48.96=(2x-0.6)*x

48.96=2x^2-0.6x

2x^2-0.6x-48.96=0

divide through by 2 we have

x^2-0.3x-24.48=0

solving the quadratic equation, the roots are

x=5.1

x=-4.8-----not correct cannot be -ve

so x=5.1

the width is 5.1

the length = 2(5.1)-0.6

l=10.2-0.6

l=9.6

check Area= 9.6*5.1= 48.96

A car insurance company has determined that 7% of all drivers were involved in an accident last year. If 11 drivers are selected at random, what is the probability that 3 or more were involved in an accident last year?

Answers

Using the binomial distribution, it is found that there is a 0.0369 = 3.69% probability that 3 or more were involved in an accident last year.

For each driver, there are only two possible outcomes, either they were involved in an accident, or they were not. The probability of a driver being involved in an accident is independent of any other driver, hence, the binomial distribution is used to solve this question.

Binomial probability distribution

P(X = x) = C_(n,x).p^(x).(1-p)^(n-x)

C_(n,x) = (n!)/(x!(n-x)!)

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 7% of all drivers were involved in an accident last year, hence p = 0.07.
  • 11 drivers are selected at random, hence n = 11.

The probability is:

P(X \geq 3) = 1 - P(X < 3)

In which:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

Then

P(X = x) = C_(n,x).p^(x).(1-p)^(n-x)

P(X = 0) = C_(11,0).(0.07)^(0).(0.93)^(11) = 0.4501

P(X = 1) = C_(11,1).(0.07)^(1).(0.93)^(10) = 0.3727

P(X = 2) = C_(11,2).(0.07)^(2).(0.93)^(9) = 0.1403

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.4501 + 0.3727 + 0.1403 = 0.9631

P(X \geq 3) = 1 - P(X < 3) = 1 - 0.9631 = 0.0369

0.0369 = 3.69% probability that 3 or more were involved in an accident last year.

To learn more about the binomial distribution, you can check brainly.com/question/24863377

Answer:

Therefore the probability that 3 or more were involved in an accident last year is 0.376.

Step-by-step explanation:

Binomial distribution:

A discrete random variable X having the set {0,1,2.....,n} as the spectrum, is said to have binomial distribution with parameter n= the number of trial and p = probability of getting successes in one trial if the p.m.f of X is give by

P(X=x)=C(n,x)p^x(1-p)^(n-x)   for x=0,1,2,....,n

               =0                                   elsewhere

where C(n,x)= (n!)/(x!(n-x)!), n is a positive integer and 0<p<1.

Given that,

7% of all drivers were involved in an accident last year that was determined by a car insurance company.

p= 7%=0.07, n=11, x=3

P(X≥3)

= 1-P(X≤2)

= 1- P(X=0)-P(X=1)-P(X=2)

          =1- C(11,0)(0.07)^0(1-0.07)^(11)- C(11,1)(0.07)^1(1-0.07)^(10)- C(11,2)(0.07)^2(1-0.07)^(9)

=1- C(11,0)(0.07)^0(0.93)^(11)- C(11,1)(0.07)^1(0.93)^(10)- C(11,2)(0.07)^2(0.93)^(9)

=1-0.624

≈0.376

Therefore the probability that 3 or more were involved in an accident last year is 0.376.

Which expression is equivalent to 15a^9b^4 over 5a^5b?Assume the denominator does not equal 0.

A. 10a^4b^3
B. 3a^4b^4
C. 10a^4b^4
D. 3a^4b^3

Answers

If you would like to solve 15a^9b^4 / 5a^5b, you can calculate this using the following steps:

15a^9b^4 / 5a^5b = 3a^(9-5)b^(4-1) = 3a^4b^3

The correct result would be D. 3a^4b^3.

Which zero pair could be added to the function so that the function can be written in vertex form?A.3, –3
B.6, –6
C.9, –9
D.36, –36

Answers

The function in this problem should be: f(x) =x² + 12x + 6 

y = x
² + 12x + 6
y - 6 = x² + 12x 

x² ⇒ x * x
12x ⇒ 2*6*x
missing number is 6² = 36 

y - 6 + 36 = x² + 12x + 36

(x+6)(x+6) ⇒ x(x+6)+6(x+6) ⇒ x² + 6x + 6x + 36 = x² + 12x + 36

y + 30 = x² + 12x + 36
y = (x+6)² - 30

Choice is D. 36,-36

470 + how many tens = 1000? Tick the correct option A) 530 B) 430 C) 53

Answers

Answer: A) 530

Step-by-step explanation:

1000-470=530

Final answer:

To find out how many tens are needed to add to 470 to equal 1000, subtract 470 from 1000 and divide the difference by 10.

Explanation:

To find out how many tens are needed to add to 470 in order to equal 1000, we need to subtract 470 from 1000. This will give us the difference, which is 530. Since each ten is worth 10, we divide the difference by 10 to find out how many tens are needed. So, 530 divided by 10 equals 53. Therefore, the correct option is C) 53.

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