I need help with # 8 & # 10 please
Answers
Answer:
8) -0.05 lb/day . . . . or . . . . -1.5 lb/month
10) 43.6%
Step-by-step explanation:
8) Using the given units, the "unit rate" is the rate expressed with a denominator of 1. For rates involving time, usually the time period is in the denominator. That is, we're interested in what happens in a unit of time.
... (change in pressure)/(change in time) = (-1.5 lb)/(30 day) = -0.05 lb/day
You can recognize that 30 days is a month, so we could just change the 30 day period to 1 month. Then the denominator will be 1 unit as desired.
... (change in pressure)/(change in time) = (-1.5 lb)/(1 month) = -1.5 lb/month
(My guess is that this latter solution may not fly.)
___
10) 34/78 × 100% = 43.589743_589743% . . . . a repeating decimal with a 6-digit repeat
... ≈ 43.6%
_____
Comment on unit rates involving time
Sometimes, we're interested in the amount of time to do a task. Then the unit rate is expressed as "time per task", rather than "tasks per time".
In the above problem, we might be interested in the amount of time it takes to lose 1 lb of air pressure. Then the unit rate would be 20 days/lb.
Other kinds of unit rates can be inverted similarly, often for similar reasons.
Related Questions
In the box below, enter the value that is missing from the table.
6)Do these calculations and use proper significant figures:26 X 0.02584 =15.3 +1.1 =782.45 X 3.5 =63.258 + 734.2 =
If f (x)=x/2+8 what is f (x) when x=10
The number of text messages sent by 25 13-year-olds over the past month are as follows791 542 671 672 555 582 616 961 639691 648 967 959 826 573 598 790 954711 515 649 960 949 802 507 a. Construct the frequency distribution using classes of 500 up to 600, 600 up to 700, etc.Texts Frequency500 up to 600 600 up to 700 700 up to 800 800 up to 900 900 up to 1000 Totalb. Construct the relative frequency distribution, the cumulative frequency distribution and the cumulative relative frequency distribution. (Round "Relative Frequency" and "Cumulative Relative Frequency" to 2 decimal places.)Texts Relative Frequency Cumulative Frequency Cumulative Relative Frequency500 up to 600 600 up to 700 700 up to 800 800 up to 900 900 up to 1000c-1. How many of the 13-year-olds sent at least 600 but less than 700 text messages?c-1. Number of 13-year-oldsNumber of 13-year-oldsc-2. How many sent less than 900 text messages?Number of 13-year-oldsd-1. What percent of the 13-year-olds sent at least 800 but less than 900 text messages? (Round your answer to the nearest whole percent.)Percent of 13-year-olds %d-5. What percent of the 13-year-olds sent less than 600 text messages? (Round your answer to the nearest whole percent.)Percent of 13-year-olds %
Answers
Answers
Answer:
18 napkins
Step-by-step explanation:
If the restaurant gives 3 napkins for every 5 items ordered, and there's 30 items... you must divide 30 by 5 which is 6. Then, multiply 6 by 3. Therefore the answer is 18.
Hopethishelped:)
Answer:
18 napkins
Step-by-step explanation:
Answers
Answer:
( 5 , 10 )
Step-by-step explanation:
Solution:-
- There are two ships, A and B, currently located by their respective coordinates in the cartesian coordinate system:
Position of ship A: ( - 1 , -2 )
Position of ship B: ( -4 , 1 )
- Both ships try to locate a lifeboat. The spotlights used by each ship are modelled as straight line functions of cartesian coordinate originating from their respective ships.
- Spot lights for each ship were able to locate the same lifeboat. The respective spotlights are modelled by the following functions:
Spotlight Ship A: y = 2x
Spotlight Ship B: y = x + 5
- To locate the position of the lifeboat with respect to the origin ( 0 , 0 ) we will use the spotlight model functions and equate them. This is because the spotlights must converge or meet at the position of lifeboat provided the lifeboat is found by both ships.
- Therefore,
Spotlight A = Spotlight B
y = 2x = x + 5
2x = x + 5
x = 5 , y = 10
Answer:The two spotlight meet at the coordinates ( 5 , 10 ). This is also the position of the lifeboat located by both the ships.
Answers
let's solve :
so, the slope intercept form of given line will be :
Answer:
130
Step-by-step explanation:
sorry if wrong :-( :-( :-(
an=___⋅an−1, a1=___
Answers
Answer:
an= 1/4 · an-1 a1= 2
Step-by-step explanation:
Got it correct on the test.
Show work
Answers
Answer:
Center: (3, - 4)
Step-by-step explanation:
We can start to solve this problem by converting this equation into standard form. In other words, by completing the square --- (1)
Subtract " 10 " from either side of the equation x² + y² - 6x + 8y + 10 = 0
x² + y² - 6x + 8y = - 10
Step 1: Complete the square for the expression " x² - 6x "
Using the quadratic equation ax² + bx + c we know that a = 1, b = - 6, c = 0. Assume that d = b / 2a. We have...
d = - 6 / 2(1) = - 6 / 2 = - 3
Now let's assume that e = c - (b²) / 4a...
e = 0 - (-6)² / 4(1) = 0 - 36 / 4 = 0 - 9 = 9 (Substitute values d and e)
(x - 3)² - 9
Step 2: Respectively we can complete the square for the remaining expression " y² + 8y "
Here a = 1, b = 8, c = 0
d = 8 / 2(1) = 8 / 2 = 4
e = 0 - (8)² / 4(1) = 0 - 64 / 4 = 0 - 16 = - 16 (Substitute values)
(y + 4)² - 16
This leaves us with the expression " (x - 3)² - 9 + (y + 4)² - 16 = - 10. " If we simplify this a bit further it leaves us with the following circle equation. Using this we can identify the center of the circle as well --- (2)
As you can see our center here is (3, - 4)