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If f (x)=x/2+8 what is f (x) when x=10​
if f (x)=x/2+8 what is f (x) when x=10​ - 1

Answers

Answer 1
Answer:

Answer: 13

Step-by-step explanation: Plug 10 in for x; 10/2=5; 5+8=13

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Rylen hiked 3/4 of a mile in 2/3 of an hour . What was his hiking speed in miles per hour?1/8 miles per hour


1 1/8 miles per hour


8/9 miles per hour


1 5/12 miles per hour

Answers

Answer:

The hiking speed in miles per hour is 1 1/8.

Step-by-step explanation:

This can be solved by a simple rule of three.

In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.

When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too.

When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease.

In this problem, the measures are the time spent hiking and the distance hiked. As the the time spent hiking increases, so will the distance hiked. So their relationship is direct.

So:

3/4 - 2/3 hour

x miles - 1 hour

(2x)/(3) = (3)/(4)

x = (9)/(8)

x can also be written in this format

x = (9)/(8) = (8)/(8) + (1)/(8) = 1 + (1)/(8)

So the hiking speed in miles per hour is 1 1/8.

If bulb 4 were removed from the circuit what would happen to the brightness of the remaining bulbs? would this change if bulbs 3 or 5 were removed rather than 4? explain.

Answers

I thought i knew how to do this but I don’t, sorry

Graph please!!!!
y = 4x - 10

Answers

Answer:

(2,5; 0)

(0: - 10)

A cylindrical package to be sent by a postal service can have a maximum combined length and girth (perimeter of a cross section) of 141 inches. Find the dimensions of the package of maximum volume that can be sent. (The cross section is circular.)

Answers

Answer:

Length = 47 in

Radius = 47/π in

Step-by-step explanation:

Let 'h' be the length of the package, and 'r' be the radius of the cross section.

The length and girth combined are:

L+G=141=h+2\pi r\nh=141-2\pi r

The volume of the cylindrical package is:

V=A_b*h\nV=\pi r^2*h

Rewriting the volume as a function of 'r':

V=\pi r^2*h\nV=\pi r^2*(141-2\pi r)\nV=141\pi r^2-2\pi^2 r^3

The value of 'r' for which the derivate of the volume function is zero yields the maximum volume:

V=141\pi r^2-2\pi^2 r^3\n(dV)/(dr)=282\pi r-6\pi^2r^2=0\n 6\pi r=282\nr=(47)/(\pi) \ in

The length is:

h=141-2\pi r=141-2\pi*(47)/(\pi)\nh=47\ in

The dimensions that yield the maximum volume are:

Length = 47 in

Radius = 47/π in

What is the sum of two solutions of the quadratic equation ax^2+bx+c=0

Answers

if we were to use the quadratic formula, we would get that the roots are

(-b\pm√(b^2-4ac))/(2a)

or that the 2 seperate roots are

(-b+√(b^2-4ac))/(2a) and (-b-√(b^2-4ac))/(2a)

if we sum these, then the √(b^2-4ac) bits will cancel and we wil be left with

(-b-b)/(2a) or (-2b)/(2a) or (-b)/(a)


the sum of the solutions is (-b)/(a)

Try this option:

According to the properties of the quadratic equation the sum of its roots is '-b', in other words x₁+x₂= -b

Answer: -b

Anyone know this? that box is just when I get the answr​

Answers

\huge\textsf{Hey there!}

\mathsf{(1)/(5)*(1)/(2)}

= \mathsf{(1*1)/(5*2)}

\mathsf{1 * 1 = \boxed{\bold{1}} \leftarrow NUMERATOR\ (TOP\ number)}

\mathsf{5*2 = \boxed{\bold{10}} \leftarrow DENOMINATOR\ (BOTTOM \ number) }

\mathsf{= (1)/(10)}

\boxed{\boxed{\large\textsf{Answer: }\mathsf{\bf (1)/(10)}}}\huge\checkmark

\large\textsf{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

Answer:

1/10

Step-by-step explanation:

1/5 x 1/2

1/10

Bye , hope this helps!

Give brainliest !
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