a. Force is multiplied by 4
b. Force is divided 3
c. Force is multiplied 3/4
d. Force is divided 3/4
The approximate horizontal component of the initial velocity is 12.3 m/s
When an object is thrown at an angle from the horizontal direction, the object is said to be in projectile motion. The object which follows the projectile motion.
Given is Ronnie kicks a playground ball with an initial velocity of 16 m/s at an angle of 40° relative to the ground.
The horizontal component of the projectile is
Vx= V cosθ
Substitute the values, we get
Vx = 16 cos(40) =
Vx =12.3 m/s
Thus, approximate horizontal component of the initial velocity is 12.3 m/s.
Learn more about projectile.
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B. positron
C. neutrino
D. helium-4
Answer:
The answer is B i just took the test and got it correct:)
Explanation:
The angle of refraction of the light in turpentine will be .
Explanation:
Given:
The refractive index of the turpentine is.
The refractive index of the water is .
The angle that the light makes with the surface of the turpentine is .
Concept:
As the light is incident on the surface of the turpentine at the air-turpentine interface, the light gets refracted from the surface. The refraction of light occurs due to change in the refractive index at the air-turpentine surface.
The angle of the refracted ray after undergoing refraction is given by the Snell's law.
Here, is the refractive index of first medium, is the refractive index of second medium, is the angle of incidence and is the angle of refraction.
The angle of incidence is the angle made by the light from the normal to the surface. So, in this case, the angle of incidence will be i.e. .
Substitute the values in above expression.
Thus, The angle of refraction of the light in turpentine will be .
Learn More:
1. How does the reflection differ from refraction and diffraction brainly.com/question/3183125
2. The reason for the refraction of light at air water interface brainly.com/question/3095091
3. Approximate length of the unsharpened pencil brainly.com/question/6140057
Answer Details:
Grade: High School
Subject: Physics
Chapter: Refraction
Keywords:
thin layer, turpentine, Snell's law, refraction, air, interface, normal, incident, light, refracted, refraction, refraction angle.
Answer:
16.6 degrees
Explanation:
We can solve the problem by using Snell's law for refraction:
where:
is the index of refraction of the first medium (air)
is the angle of incidence
is the index of refraction of the second medium (turpentine)
is the angle of refraction of light in turpentine
By re-arranging the equation and using the numbers, we find
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