cleopatra needle, an ovelisk given by the egyptian government to great britian in the 19th century, is 20+m tall and has a mass of about 189,000 kg. suppose the monument is lowered onto its side and dragged horizontally to a new location. an applied force of 760,000 N is excerted on the monument, so that its net acceleration is 0.11 m/s2. what is the weight, the net force, the frictional force and the coefficient of friction phycis
Answers
Weight = mass × acceleration due to gravity
Weight = 189,000 kg × 9.81 m/s² ≈ 1,854,090 N
Next, let's calculate the net force acting on the monument using Newton's second law (F = m × a), where F is the force, m is the mass, and a is the acceleration:
Net Force = mass × acceleration
Net Force = 189,000 kg × 0.11 m/s² ≈ 20,790 N
The net force applied is 760,000 N, so the frictional force can be calculated by subtracting the net force from the applied force:
Frictional Force = Applied Force - Net Force
Frictional Force = 760,000 N - 20,790 N ≈ 739,210 N
The coefficient of friction (μ) can be calculated using the formula for frictional force (Frictional Force = μ × Normal Force). Since the normal force is equal to the weight of the monument:
μ = Frictional Force / Weight
μ = 739,210 N / 1,854,090 N ≈ 0.3987
So, the coefficient of friction is approximately 0.3987.
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