A second baseman tosses the ball to a first baseman, who catches it a the same level from which it was thrown. The throw is made with an initial speed o 19.0 m/s at an angle of 37 degrees above the horizontal. Neglect air resistance. How long is the ball in the air?

Answers

Answer 1

Answer: -- The toss was directed 37° above horizontal, at 19 m/s.

The horizontal component is 19 cos(37°) = 15.174 m/s .

The vertical component is 19 sin(37°) = 11.434 m/s .

The ball will continue to climb until its vertical speed is zero,
then will begin falling. It'll fall to the same level from which
it was thrown in the same time it spent rising.

Time spent rising = (11.434 m/s) / (acceleration of gravity) = 11.434/9.8 = 1.166 second.

Return to the same level from which it was thrown in (2 x 1.166) = 2.332 seconds.

The ball is in the air for 2.332 seconds.

In that amount of time, it travels horizontally (2.332) x (15.174) = 35.39 meters.

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Answers

Answer:

The Answer is D

Explanation:

I know because I just took the test.

Answer:

answer is D

Explanation:

How far will you travel if you run for 10. minutes at 2.0 m/s?

Answers

We know that 1 minute= 60 seconds (or 1 min= 60 s).

10 min* (60 s/ 1 min)* (2.0 m/ 1 s)= 1,200 m.
(Note that the units cancel out so you get the answer)

The final answer is 1,200 m.

Hope this helps~

PLEASE help me with these questions as soon as possible i need to turn it in!!!!A 60 watt light bulb uses 60 joules of electrical energy every second. However, only 6 joules of electrical energy is converted into light energy each second.
a. What is the efficiency of the light bulb? Give your answer as a percentage.

b. What do you think happens to the “lost” energy?

19. The work output is 300 joules for a machine that is 50% efficient. What is the work input?

20. A machine is 75% efficient. If 200 joules of work are put into the machine, how much work output does it produce?

Answers

a. I believe this might be the answer but
6 J/60 J= .1
.1 x 100= 10%

b. I'm not sure of this question

19. I'm not sure if I did this correct way or if there is a better way (I'm rusty)
300 J/.50 %= 600
600/100= 6 (answer)

20. (200 J)(.75%) = 150 (answer)
Check:
Efficiency: output/input x 100
150 J/200 J= .75
.75 x 100= 75%

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b. 0.50 kgm/s

c. 0.70 kgm/s

d. 3.5 kgm/s