PHYSICS HIGH SCHOOL

An object is located 51 millimeters from a diverging lens. The object has a height of 13 millimeters and the image height is 3.5 millimeters. How far in front of the lens is the image located? A. 1.12 millimeters
B. 13.7 millimeters
C. 51 millimeters
D. 189 millimeters

Answers

Answer 1
Answer: The correct answer is letter B. 13.7 millimeters. An object is located 51 millimeters from a diverging lens. The object has a height of 13 millimeters and the image height is 3.5 millimeters.

mi / mo = hi / ho
mi / 51 = 3.5 /13
178.5 = 13 mi
mi = 13.7 mm

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NEED THIS ANSWERED ASAP PLEASE!!!! Ocean Water Density 1 Lab

Materials-

Earth Science: A Reference Guide -Earth Science: A Reference Guide - Earth's Oceans (pp. 124-125), Oceans Temperature (pp.130-131), Ocean Salinity(pp.132-133), Density of Ocean Water (pp.134-135)

watch

4 cups -tap water - You will need an ice cube tray and access to a freezer to freeze the water.

teaspoon

salt, table

______________________________________________________________


1.) How will the ice water mix with the salty water? Write your hypothesis below.

(I can't add the picture of the chart so bear with me)

Solution - Hypothesis Describing Mixing - Hypothesis Describing Temperature

(Will the top be warmer, cooler, or the same as the bottom?)

Solution 1

(Freshwater) - -


Solution 2

(salty water) - _____________________ - ________________________


Solution 3

(saturated water)- ______________ - _____________________


2.) Complete the data table. Sketch, use your computer to draw or write a detailed description to describe how the ice melts into the different solutions. At each interval, record the temperature at the top and bottom of the glass.

(Again I can't add the pic of the chart so bear with me)


Solution 1 - 0 minutes- 5 minutes- 10 minutes- 30 minutes-

(Freshwater)


Temperature

(top of glass) -______________________________-

Temperature

(bottom of the glass)-_______________________________-


Solution 2- 0 minutes- 5 minutes- 10 minutes- 30 minutes-

(salty water)


Temperature

(top of glass)- ____________________________________-

Temperature

(bottom of glass)-_______________________________________


Solution 3

(saturated water)- 0 minutes- 5 minutes- 10 minutes- 30 minutes-


Temperature

(top of glass)-___________________________________

Teperature

(bottom of glass)-_______________________________________


3.) Summarize your data. Describe how the ice melted into each solution, and compare the temperatures at the top and bottom of the glass.

(can't add the pic, bear with me)

Solution-
Mixing (how did the colord, fresh, melt-water mix with the salty water?)- Temperature (Was the top warmer or cooler, or was it the same as the bottom?) -


Solution 1

(freshwater)-__________________________________________-

Solution 2

(salty water)-___________________________________________

Solution 3

(saturated water)- ____________________________________


4.) What does your experiment suggest about what happens when icebergs melt into the ocean? Based on your data, do you think the sea-surface temperatures are warmer or cooler due to the melting water? Make sure you explain how your experiment helps you answer this question.


I really need help with this as soon as possible, if you do not know the answer to this do not answer please, let me repeat that, PLEASE DON'T ANSWER IF YOU DON'T KNOW THE ANSWER TO ALL THE QUESTIONS, also if your a k12 student, friend me so we can help each other with quizzes and stuff, and if you are a k12 student and you answer this, please don't put your exact answers on this, make it different from yours, I don't want a heart-attack email from my teacher

Answers

The way ice water mix with the salty water is that  when a person adds salty water to ice, the salt will be the first thing to dissolves in the layer of liquid water that is seen on the surface.

By reducing the  freezing point below the ices temperature, when the Ice is said to be in contact with salty water, it tends to melts, forming more liquid water, that will then dissolves more salt, causing a lot of ice to melt, and the process still goes on.

Learn more about Water Density from

brainly.com/question/15885

A compass needle normally points toward Earth’s magnetic pole, which is near the North Pole. Which best explains why the needle moves away from the pole when it comes close to a current-carrying wire?-Current within the wire weakens the magnetic force of the pole.
-Magnetism surrounding the wire weakens the magnetic force of the pole.
-Magnetism surrounding the wire draws the needle toward the wire.

Answers

Answer

-Magnetism surrounding the wire draws the needle toward the wire.

Explanation
When a compass needle is placed near a conductor carrying current, it deflects to one side. 
This happens because the magnetic field due to the needle interact with electric fields around the conductor carrying carrying current resulting to a force that makes the needle to deflet. 
The best answer that suits the question asked is -Magnetism surrounding the wire draws the needle toward the wire.
A compass needle normally points toward Earth’s magnetic pole, which is near the North Pole. The best explanation why the needle moves away from the pole when it comes close to a current-carrying wire is Magnetism surrounding the wire draws the needle toward the wire.

What is the power of a refrigerator with voltage 110 V and
current 0.8 A?

Answers

Answer: 88

Explanation:

What is the difference between magnetic field and magnetic flux

Answers

Explanation:

The region around a moving charge in which it experience a force is called magnetic field. The force is called magnetic force. The force experienced due to moving charge is given by :

F=q(v* B)

q is the charged particle

v is the speed of particle

B is the magnetic field

The number of magnetic field lines passing through any surface is called magnetic flux. The formula used to find the magnetic flux is given by :

\phi=B.A

\phi=BA\ cos\theta

Hence, this is the required solution.

A rock at the top of a 30 meter cliff has a mass of 25 kg. Calculate the rock’s gravitational potential energy when dropped off the cliff. Assuming that energy is conserved and there is no air friction and gravity is 9.8 m/sec., at the bottom of the cliff the rock’s potential energy is completely converted to kinetic energy. Use the formula for kinetic energy to calculate the rock’s speed at the bottom of the cliff. Show all calculations.

Answers


Potential energy =

                     (mass) x (gravity) x (height above the reference level) .

Relative to the bottom of the cliff, the potential energy
at the top of the cliff is

                         (25kg) x (9.8 m/s²) x (30 meters)

                     =  (25 x 9.8 x 30)  kg-m²/s²

                     =        7,350 joules .

Kinetic energy = (1/2) x (mass) x (speed²)

The rock's kinetic energy at the bottom is
the same as its potential energy at the top.

                                        7,350 joules = (1/2) x (25 kg) x (speed²)

Divide each side
by 12.5kg :                7,350 joules/12.5 kg  =  speed²

                                 7,350 kg-m²/s² / 12.5kg  =  speed²

                                 (7,350 / 12.5)  m²/s²  =  speed²

                                      588 m²/s²  =  speed²
Take the square root
of each side:            
                                   Speed = √(588 m²/s²) 

                                             =  24.248... m/s       (rounded)
Lets see:-

We have our formula for potential energy, which we are trying to solve for, 

PE = mgh  or  potential energy = mass * gravity * height

So we know that PE all depends on these. 

Height :  30 meters
Mass : 25 kg
Gravity (which is always constant) : 9.8 m/s/s

Now add into formula. 

PE = 25*30*9.8 
PE = 7350 Joules

Answer: PE = 7350 Joules

Radium-226 is unstable. What is the process that allows the nucleus of radium-226 to become more stable? Question 14 options: A. ionic bonding B. radioactive decay C. hydrogen bonding D. covalent bonding E. nuclear fusion

Answers

Answer: The correct answer is Option B.

Explanation:

We are given a radioisotope which is unstable in nature. For this isotope to become stable, it has to undergo radioactive decay. There are various processes by which a radioisotope may decay:

1. Alpha decay: In this decay process, a heavier nuclei decays into lighter nuclei. The particle released is alpha particle.

_Z^A\textrm{X}\rightarrow _(Z-2)^(A-4)\textrm{Y}+_2^4\alpha

2) Gamma decay: In this decay process, an unstable nuclei gives excess energy by a process of spontaneous electromagnetic process. This decay process releases \gamma -radiations.

_Z^A\textrm{X}^*\rightarrow _Z^A\textrm{X}+_0^0\gamma

3) Beta-plus decay: In this decay process, a neutron gats converted into a proton and an electron. The particle released is \beta-particle

_Z^A\textrm{X}\rightarrow _(Z+1)^A\textrm{Y}+_0^(-1)\beta

4) Beta-minus decay: In this decay process, a proton gets converted into a neutron and an electron neutrino which is known as a positron particle. This is also known as \beta ^+-decay.

_Z^A\textrm{X}\rightarrow _(Z-1)^A\textrm{Y}+_(+1)^0e

Radium-226 nuclei undergoes alpha decay to form Radon-222 nuclei by releasing alpha-particle.

_(88)^(226)\textrm{Ra}\rightarrow _(86)^(222)\textrm{Rn}+_2^4\alpha

Hence, the answer is Option B.

the correct answer for this question is radio active decay or option b ! press brainliest...
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