Answer:
d = 235 nm.
Explanation:
Let the layer be of glass. Refractive index of glass μ = 1.5. Let the required thickness be d.
For minimum reflection , that is destructive interference in thin films , the condition is
2μd = λ ( for first order)
d = 705 / 2 x 1.5 = 235 nm [ λ =705 nm ]
b. sound waves.
c. gamma rays.
d. radio waves.
Sound waves are longitudinal waves. All are the examples of Electromagnetic waves except the sound wave.
EM Waves:
EM waves are transverse waves means the propagation of the wave is the perpendicular the the wave oscillation.
Sound waves:
These are the longitudinal waves because the propagation of the wave is parallel to the vibration of particles.
Therefore, all are the examples of Electromagnetic waves except the sound wave.
To know more about sound wave,
B The spring descriptions of motion are switched
C Particles travel along the wave in longitudinal waves
D Particles move long distances in transverse waves
Answer:
Explanation:
The photons travel faster faster through space because photons always travel through space faster than electrons, in fact when an electron gets hitted by a photon this boost its speed
Then go to this link when you go there you will see request access sent me request saying brainly in the box the I will accept it then you watch the video up there then you then you will complete the slide that you will request for I will be posting the link to that in the chat.
Here is the directions for the slide you guys are going to be doing:
Step 1: Draw a model to show how sound is created and how you think it makes the windows move.
Step 2: Label your model with explanations. Include all of these science vocabulary/concepts: vibrations/oscillations, force, energy, and transfer.
By the way this the Brainly committee we will be testing how smart you guys are so guys prove it. If you do this right the Brainly will sent 500 brainly points into the account that answers it right. If you have any questions please ask.
Answer:
Not 500 points I got 18 but thx
Explanation:
In a binary system with a main-sequence star and a brown dwarf, we can determine their masses by analyzing their radial velocity curve and measuring the Doppler shifts of their spectral lines. Kepler's law can then be used to calculate the sum of their masses.
The question is about a binary system containing a main-sequence star and a brown dwarf. We can determine the masses of the stars in a spectroscopic binary by analyzing their radial velocity curve. By measuring the Doppler shifts of the spectral lines, we can calculate the orbital speed of each star and use Kepler's law to calculate the sum of their masses.
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The orbital speed and separation of a binary system composed of a main-sequence star and a brown dwarf can be utilized to infer their respective masses. This is accomplished by studying the Doppler effect from the spectral lines of the system and applying Kepler's third law. Greater mass is found to exhibit slower orbital speed.
The main-sequence star and the brown dwarf form a binary system with an orbital period of 1 year and an average separation of 1 Astronomical Unit (AU). The Doppler shifts of the spectral lines from the main-sequence star and the brown dwarf indicate that the orbital speed of the brown dwarf in the system is 22 times greater than that of the main-sequence star.
We can estimate the masses of the stars in this binary system using the formula based on Newton's reformulation of Kepler's third law: D³ = (M₁ + M₂)P², where D represents the semimajor axis in AU and P represent the period in years. From this, we can calculate the sum of the masses of the two stars. Given the difference in orbital speeds, the main-sequence star has a higher mass to result in a slower speed, and the brown dwarf has a smaller mass to result in the higher speed.
In conclusion, by analyzing the radial velocity curve and using Kepler's third law, we can estimate the masses of the stars in a binary system.
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