How is the frequency of an electromagnetic wave related to energy?A) As the frequency of the wave decreases, its energy increases.
B) As the frequency of the wave fluctuates, its energy decreases.
C) As the frequency of the wave increases, its energy also increases.
D) As the frequency of the wave changes, its energy remains constant.
Answers
As the frequency of the wave increases, its energy also increases. The correct option is C.
The frequency of an electromagnetic wave is defined as the number of oscillations or cycles per unit of time.
The frequency of the wave, on the other hand, is directly proportional to energy.
The energy of an electromagneticwave is precisely proportional to its frequency, according to the equation E = hf, where E represents energy, h is Planck's constant, and f is the frequency of the wave.
Simply said, higher frequency waves have more energy than lower frequency waves.
This is true over the whole electromagneticspectrum, from radio waves to gamma rays. The energy carried by the wave rises as the frequency of the wave increases.
Thus, the correct option is C.
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A system uses 2,380 J of energy to do work as 12,900 J of heat are added to the system. What is the change in internal energy of the system?
Answers
The speed of the object at its' final location is; 38 m/s
What is work energy theorem?
For the first force, we are given;
Force; F₁ = 220i + 320j - 120k
Initial Position; r₁ = 13i - 19j - 3k
Final Position; r₂ = 18i - 11j - 8k
Thus; Displacement; Δr = r₂ - r₁
Δr = 18i - 11j - 8k - (13i - 19j - 3k)
Δr = 5i + 8j - 5k
From work energy theorem, we know that;
F₁ * Δr = ¹/₂m(v₂² - v₁²)
We are given v₁ = 2.5 m/s and m = 60 kg. Thus;
(220i + 320j - 120k) × (5i + 8j - 5k) = ¹/₂ * 60(v₂² - 3.5²)
4260/30 = v₂² - 3.5²
1420 = v₂² - 12.25
Solving gives v₂ = 37.85 m/s
For the second force, we are given;
Force; F₂ = 150i + 230j - 220k
Initial Position; r₁ = 18i - 11j - 8k
Final Position; r₂ = 22i - 17j - 3k
Thus; Displacement; Δr = r₂ - r₁
Δr = 22i - 17j - 3k - (18i - 11j - 8k)
Δr = 4i - 6j + 5k
From work energy theorem, we know that;
F₂ * Δr = ¹/₂m(v₂² - v₁²)
Now, v₁ = 37.85 m/s and m = 60 kg. Thus;
(150i + 230j + 220k) × (4i - 6j + 5k) = ¹/₂ * 60(v₂² - 37.85²)
320/30 = v₂² - 37.85²
10.67 = v₂² - 1,432.6225
Solving gives v₂ = 38 m/s
Read more about Work Energy theorem at; brainly.com/question/14468674
(220, 320, -120).(18-13,-11+19,-8+3) +(150, 230, 220).(22-18,-17+11,-3+8)= 1/2 *60*(V^2- 3.5^2)
220*5+320*8+ -120*-5 + 150*4 + 230* 6 +220* -5= ..
simplify his
Answers
Answer:
Explanation:
We shall apply conservation of mechanical energy
kinetic energy of alpha particle is converted into electric potential energy.
1/2 mv² = k q₁q₂/d , d is closest distance
d = 2kq₁q₂ / mv²
= 2 x 9 x 10⁹ x 79e x 2e / 4mv²
= 1422 x2x (1.6 x 10⁻¹⁹)² x 10⁹ /4x 1.67 x 10⁻²⁷ x (1.5 x 10⁷)²
= 3640.32 x 10⁻²⁹ /2x 3.7575 x 10⁻¹³
= 484.4 x 10⁻¹⁶
=48.4 x 10⁻¹⁵ m
1.
What do you mean by a unit?
2.
unit or a derived unit.
are the fundamental units used in physics?
al Bureau of Weights and Me
Answers
Answer:
1)the unit of work is joule. 2)it is derived unit because it is made by two different unit force and displacement .3)
b. meteoroid
c. dwarf planet
d. Kuiper Belt object
Answers
Ceres is best classified as a dwarf planet. Ceres is located in he asteroid belt. Ceres is much closer to Earth than Pluto and it was discovered in the year of 1801.
Ceres is considered the smallest dwarf planet of the solar system.
B. It increases the potential energy of electrical charges to produce a current.
C. It increases the kinetic energy of electrical charges to produce a static discharge.
D. It transfers electrons through induction so they generate electrical energy.
Answers
Answer:
B. It increases the potential energy of electrical charges to produce a current.
Explanation:
Battery is a source of constant potential difference
When a charge is passed through the battery then its potential energy changes by
here we know that
= potential difference of battery
so as the charge is passing through the terminals of battery its potential energy is changed by above value.
Now by the conservation of energy principle we know that this change in potential energy will convert into kinetic energy of charge and then the flow of charge will produce current in the circuit.
So battery is used to maintain a constant current in the circuit by giving potential energy to the charge.