PHYSICS HIGH SCHOOL

what is the free-fall acceleration at the surface of the jupiter?you may have submitted the value posted in the internet. recall newton's law of universal gravitation and use the values for jupiter's mass and mean radius from the textbook.no credit lost. try again.

Answers

Answer 1

Answer:

Answer:

The formula for acceleration due to gravity at the surface of a celestial body is:

a = (G * M) / r^2

Where:

G (the gravitational constant) is approximately 6.67430 x 10^-11 m^3 kg^-1 s^-2.

M (the mass of Jupiter) is approximately 1.898 x 10^27 kilograms.

r (the mean radius of Jupiter) is approximately 71,492,000 meters.

Now, let's calculate it:

a = (6.67430 x 10^-11 m^3 kg^-1 s^-2 * 1.898 x 10^27 kg) / (71,492,000 meters)^2

a ≈ 24.79 m/s^2

So, the free-fall acceleration at the surface of Jupiter is approximately 24.79 m/s^2.

Answer 2

Answer:

Final answer:

The free-fall acceleration on the surface of Jupiter (g) is calculated by using Newton's Universal Law of Gravitation (g = G * M / r^2), where G is the gravitational constant, M is the mass of Jupiter and r is the radius of Jupiter.

Explanation:

To calculate the acceleration due to gravity at the surface of Jupiter, we can use Newton's Universal Law of Gravitation. It states that the force of gravity is equal to the gravitational constant (G) times the mass of the body (in this case, Jupiter) divided by the radius of the body squared. The formula can be expressed as F = G * (M * m / r^2), where F is the force of gravity, G is the gravitational constant, M is the mass of the larger body (Jupiter), m is the mass of the smaller body (object in question), and r is the distance between the centers of the two bodies - which is the radius of Jupiter when the object is on its surface.

The formula to find the acceleration due to gravity (g) on the surface of Jupiter is found by setting the weight of an object (F = m*g) equal to the gravity force (F = G * (M * m / r^2)) leading to the cancellation of the mass of the object (m). That results in g = G * M / r^2. This means that the acceleration due to gravity on the surface of Jupiter depends on the mass of Jupiter and the radius of Jupiter, and not on the mass of the object.

Learn more about Jupiter's Free-fall Acceleration here:

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Which of the following can be determined by studying the spectrum of a star?the chemicals in the atmosphere of the star
the motion of the star
the temperature of the atmosphere of the star
all of the above

Answers

Answer:

all of the above

Explanation:

The spectrum of the star is is used to study its composition, motion and surface temperature. The absorbed or emitted wavelength indicates the elements present. The peak wavelength determines the surface temperature of the star using Wein's law. Peak wavelength is inversely proportional to temperature. The red-shift or blue shift indicates whether the star is moving away or towards us.

The right answer for the question that is being asked and shown above is that: "all of the above." the following that can be determined by studying the spectrum of a star includes: the chemicals in the atmosphere of the star; the motion of the star; the temperature of the atmosphere of the star.

The length of some fish are modeled by a von Bertalanffy growth function. For Pacific halibut, this function has the form L(t) = 200(1 – 0.956e–0.18t ) where L(t) is the length (in centimeters) of a fish t years old.(a) Find the rate of change of the length as a function of time

Answers

Answer:

Rate of change of length as a function of time is given by $(dL(t))/(dt)=34.416e^(-0.18t)$

Explanation:

The length as function of time is given by $L(t)=200(1-0.956e^(-0.18t))$

Differentiating with respect to time we get

$(dL(t))/(dt)=(d(200(1-0.956e^(-0.18t))))/(dt)\n\n(dL(t))/(dt)=200(d(1-0.956e^(-0.18t)))/(dt)\n\n=200* 0.18* 0.956e^(-0.18t)\n\n(dL(t))/(dt)=34.416e^(-0.18t)$

What happens to the current as we increase the amount of stepping of our transformer? Does this help explain why the primary was warm but not the secondary? How does this result demonstrate that we can’t just use a step-up transformer to create free energy?

Answers

Answer:

Current will decrease.

Explanation:

When we increase the number of stepping in transformer, the voltage will increase as its is directly proportional to the number of turn of stepping. Thus as the voltage will increase, current will decrease. As per the equation of ideal transformer, E1 / E2 = I2 / I1

E1 and E2 are the voltages in primary and secondary winding and I1 and I2 are the current.

As the number of turns will be increased more inevitable losses will be generated that dissipates heat thus warming the primary.

Though the conservation of energy is obeyed but losses occur in this scenario hence step-up transformers cannot be used to create free energy.

What is the energy of work done lifting 2kg mass rocket to a height of 130 m

Answers

Work done to lift the mass is given by

W = mgH

here we know that

m = mass = 2 kg

g = acceleration due to gravity = 9.8

H = height = 130 m

now using the above equation we can write

$U = 2* 9.8 * 130$

$U = 2548 J$

so the energy required to do the work is 2548 J

work done = force × distance travelled in the direction of the force
Force= 2(9.81) = 19.62N
WD= 19.62×130= 2550.6Nm

If the potential energy and the kinetic energy are not the same, where did the leftover energy go?

Answers

Energy cannot be created or destroyed it can only be transformed into a different kind of energy work or power.

If this is the case, then the energy likely left the system through external forces or heat dissipated into the environment.

The forklift exerts a 300.0 N force on the box and moves it 15.0 m into the air. How much work does the forklift do? A. 500 J B. 1.50 * 10^3 J C. 4.50 * 10^3 J D. 0.00 J

Answers

Since the equation for Work is as follows....

Work = Force x Displacement

Your equation is...

Work = 300N x 15m

Work = 4,500 Joules

Answer:

0.00 J

Explanation:

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