Only the component of force perpendicular to the direction motion does work. true or false

Answers

Answer 1
Answer: No.  Only the component of force parallel
to the direction of motion does work.


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A uniform Capillary tube closed at one end Contain dry air trapped by a thread of mercury 8.5x10 m long when the tube was held horizontally, the length of the air Column 5.0X10^2 Wher it held verti cally with the closed end downward the length was 4.5x10^2m Determine the value of atmospheric pressure take g=10m/s, density of mercury (1.36×10^4kg/m) ​

Answers

Answer:

To determine the value of atmospheric pressure, we can use the concept of hydrostatic pressure. By comparing the lengths of the air column in the capillary tube when held horizontally and vertically, we can equate the pressure difference to the difference in height of the mercury column. Using the given values and the density of mercury, we can calculate the atmospheric pressure.

Well-designed weight-training programs only target two or three body areas.a. True
b. False

Answers

False, well designed weight training programs actually target most of the muscles in the body. A good weight training program includes many compound exercises to activate multiple muscle groups and promote muscle hypertrophy. Some isolation exercises may also be included to target a specific muscle and help it grow.

Well-designed weight-training programs do not only target two or three body areas.

The statement that well-designed weight-training programs only target two or three body areas is FALSE.

Well-designed weight-training programs aim to target different muscle groups in the body to promote overall strength and balanced development. These programs often include exercises that involve the chest, back, shoulders, arms, legs, and core.

For example, a weight-training program might include exercises like bench press (chest), rows (back), shoulder press (shoulders), bicep curls (arms), squats (legs), and planks (core).

Learn more about Well-designed weight-training programs here:

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You own a high speed digital camera that can take a picture every 0.5 seconds. You decide to take a picture every 0.5 seconds of your physics teacher as she drops a watermelon off the top of the school. After you develop and analyze the pictures, you realize that the distance the watermelon falls from the teacher in each new picture isA) the same in each picture.
B) gradually less in each picture.
C) gradually more in each picture.
D) proportional to the mass of the watermelon.

Answers

-- There is no need to develop the pictures.  They are available immediately in a digital camera.

-- There is no change in the teacher from one picture to the next.

-- The distance the watermelon falls from the teacher in each new picture is more in each picture than in the picture before it. (C)


What ion is most closely associated with bases?

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Answer: hydroxyl ion

Explanation:

When base is dissolved in water it dissociate and produce an hydroxyl ion

The ion most closely associated is hydroxide.

Ions can have a positive or negative charge. Please select the best answer from the choices provided T F

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From among the choices provided, the more appropriate
answer is ' T ', the initial letter often used to represent
words that include 'true', 'truth', 'trust', etc., (as well as
'tree', 'train', 'transmit', 'Transylvania', 'trachea', 'travesty',
and 'trick', which are irrelevant to the present discussion).

This response is the most fitting and appropriate, because
the statement that precedes the list of allowable choices is
exemplary in its accuracy and veracity.  An ion can, in fact,
have a positive or negative charge, although the same ion
cannot have both.

What is the velocity of the dart just before the collision?

Answers

Answer: 1.38 m/s to the right.

Explanation: We can solve this problem using the principle of conservation of momentum. The momentum of an object is defined as the product of its mass and velocity, and the total momentum of a closed system is conserved, meaning that the total momentum before a collision is equal to the total momentum after the collision.Let the initial velocity of the dart be v, and let the final velocity of the dart and the block be vf. The momentum of the dart before the collision is given by p = mv, where m is the mass of the dart. The momentum of the dart and block after the collision is given by (m + M)vf, where M is the mass of the block.Using the principle of conservation of momentum, we have:p = (m + M)vfSubstituting the given values, we get:0.012 kg v = (0.012 kg + 0.2 kg) 0.78 m/sSimplifying, we get:v = (0.212 kg) (0.78 m/s) / 0.012 kgv ≈ 1.38 m/sTherefore, the velocity of the dart just before it hits the block is approximately 1.38 m/s to the right.