Two balls of equal mass collide. One of them experiences an acceleration of 12m/s 2 at one moment.What acceleration does the other ball experience at the same time?
Answers
Answer:
12m/s²
Explanation:
Two balls with equal masses and speed engage in a head-on elastic collision. Since the balls of equal mass are moving at equal and opposite speeds, the total linear momentum of the system is zero.
Therefore, the second ball experience an acceleration of 12m/s² at the same time.
Final answer:
Due to the law of conservation of momentum, two balls of equal mass colliding will experience equal but opposite accelerations at the simultaneous point of collision. In this case, if one ball experiences an acceleration of 12m/s^2, the other will experience -12m/s^2.
Explanation:
In the field of physics, this scenario falls under the law of conservation of momentum. According to this law, the total momentum before and after the collision remains the same. If two balls of equal mass collide, and one experiences an acceleration of 12 m/s2, the other ball will experience an equal but opposite acceleration, so -12 m/s2. Please keep in mind, that this is a simplification and real-life situations might be more complex due to factors like friction, air resistance and the angle of collision.
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Where does the energy that the sun emits come from?
Answers
Final answer:
To find the momentum of an object, we multiply its mass and velocity together. Using this method, a bowling ball with a mass of 7.10 kg moving at a velocity of 5 m/s has a momentum of 35.5 kg * m/s.
Explanation:
The subject of your question involves calculating momentum. It's based on the principles of Physics. Momentum is defined as the product of an object's mass and its velocity. It's crucial in understanding motion, specifically related to the concepts of force and mass.
To calculate the momentum of the bowling ball, the formula p = mv is used where 'p' represents momentum, 'm' stands for mass and 'v' is the velocity. In this case, the mass of the bowling ball is 7.10 kg and its velocity is 5 m/s.
So, multiplying these together (7.10 kg x 5 m/s), the resulting momentum of the bowling ball is 35.5 kg * m/s.
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P momentum
m mass
v velocity
The average time to travel just between 0.25m and 0.50m is_____
Given the time taken to travel the second 0.25m section, the velocity would be____m/s
Answers
1. Average time for the first 0.25 m: 2.23 s
Explanation:
The average time that it takes for the car to travel the first 0.25 m is given by the average of the first three measures, so:
2. Average time to travel between 0.25 m and 0.50 m: 0.90 s
Explanation:
First of all, we need to calculate the time the car takes to travel between 0.25 m and 0.50 m for each trial:
t1 = 3.16 s - 2.24 s = 0.92 s
t2 = 3.08 s - 2.21 s = 0.87 s
t3 = 3.15 s - 2.23 s = 0.92 s
So, the average time is
3. Velocity in the second 0.25 m section: 0.28 m/s
Explanation:
The average velocity in the second 0.25 m section is equal to the ratio between the distance covered (0.25 m) and the average time taken (0.90 s):
Answer:
1. 2.23
2. 0.90
3. 0.28
longitudinal
compression
circular
Answers
An ocean wave is an example of a(n) transverse wave form. Therefore option 1 is correct.
Transverse waves are characterized by the displacement of particles perpendicular to the direction of wave propagation. In other words, the oscillations of the particles occur in a direction that is perpendicular (or transverse) to the direction of wave travel.
When an ocean wave forms, the particles of water move up and down in a vertical motion, while the wave itself moves horizontally. This up-and-down motion of the water particles is perpendicular to the direction in which the wave is traveling, making it a transverse wave.
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Answers
P1*V1=P2*V2
Then,
100*3=203*V2
Then,
V2=1.48 L
Answers
Answer:
v = 0
Explanation:
Given that,
Total distance is 50 yards
Dugan got an early lead by finishing the first 25.00 yd in 10.01 seconds
Dugan finished the return leg (25.00 yd distance) in 10.22 seconds.
We need to find Dugan's average velocity for the entire race. As he returns at the initial position. As a result, the net displacement is equal to 0. So,
Average velocity = net displacement/time
v = 0
Hence, his average velocity for the entire race is 0.
Final answer:
Dugan's average velocity for the entire 50 yd race is 2.47 yd/sec, calculated by dividing the total distance (50 yd) by the total time (20.23 sec).
Explanation:
The first step involved is to calculate the total distance that Dugan had covered. In this case, he swam 25 yd twice, making the total distance 50 yd.
Next, we need to find the total time it took Dugan to swim the entire distance. We add the time of the first leg, which is 10.01 seconds, to the time of the return leg, which is 10.22 seconds, providing a total time of 20.23 seconds.
The average velocity is defined as the total distance divided by the total time. So, for Dugan, it would be 50 yd divided by 20.23 sec, which equals 2.47 yd/sec (rounding to the nearest hundredth).
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b. 4es
c. homes
d. all of the above