Length of a curve is the length of its plot its curve. The length of the given curve for given range of t is: L = 1.44 units approx.
If the curve has position vector p(x) for value of x ranging from x = a to x = b,
then, the curve's length is calculated as:
units.
For the given case, we have:
Position vector =
Its differentiation gives:
Its non negative magnitude is: ||R'(t)|| =
Thus, as t ranges from a = 0 to b = 1, thus, length of the curve is:
Thus,
The length of the given curve for given range of t is: L = 1.44 units approx.
Learn more about length of the curve here:
curve equation is
,0≤ t≤ 1
now taking the differentiation
now taking the modulus
=
now taking the integration
length of the curve =
now put the value v= 4 + 9t²
dv= 18 tdt
now put this value in the above equation
we get
length of the curve =
now taking integation we get and put the value of the v
we get
= ×
×
=
now find out the length of the curve in the interval from 0 to 1.
length of the curve
Hence proved
Answer:
The operation for 7 and x = addition
The expression= 7 + x
The quotient of z and 3
The operation is= dividing
The expression is=
Complete the table for the given rule.
X Y
0 __
1 __
2 __
Answer:
18√2
Step-by-step explanation:
The area of the smaller triangle is 1/2 that of the larger one. Since the triangles are similar, the dimensions of the smaller triangle are √(1/2) those of the larger one.
36 · √(1/2) = 36 · (√2)/2 = 18√2 . . . . length of line dividing the triangle
Answer: 8
Step-by-step explanation: Think of the 32 in this problem as 32/1.
So rewriting, we have 1/4 × 32/1.
Now, the 4 and 32 cross-cancel to 1 and 8.
So we have 8/1 or just 8.
Answer:
34.64 ft
Step-by-step explanation:
Distance from the building = 20 ft
Angle of inclination = π/3 radians
The tangent of the angle of inclination must equal the height of the building divided by the distance of the observer from the building:
The building is 34.64 ft tall
Answer:
27 feet for the south wall and 18 feet for the east/west walls
Maximum area=
Step-by-step explanation:
Optimization
This is a simple case where an objective function must be minimized or maximized, given some restrictions coming in the form of equations.
The first derivative method will be used to find the values of the parameters that control the objective function and the maximum value of that function.
The office space for Billy-Sean will have the form of a rectangle of dimensions x and y, being x the number of feet for the south wall and y the number of feet for the west wall. The total cost of the space is
C=8x+12y
The budget to build the office space is $432, thus
Solving for y
The area of the office space is
Replacing the value found above
Operating
This is the objective function and must be maximized. Taking its first derivative and equating to 0:
Operating
Solving
Calculating y
Compute the second derivative to ensure it's a maximum
Since it's negative for x positive, the values found are a maximum for the area of the office space, which area is