Pls, help. ASAP. just think about the pts and brainliest
pls, help. ASAP. just think about the pts and brainliest - 1

Answers

Answer 1
Answer:

Answer:8.9

Step-by-step explanation:

192/43 is about 4.46

4.46*2 is about 8.9

Answer 2
Answer:

8.9

192/43 is around 4.46

4.46*2 is around 8.9


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Please show you're work! THANKS! Need help asap

Find the limit of the formula given​

Answers

Answer:

\displaystyle  \lim_(x \to 0^+) x^\big{√(x)} = 1

General Formulas and Concepts:

Algebra II

  • Natural logarithms ln and Euler's number e
  • Logarithmic Property [Exponential]:                                                             \displaystyle log(a^b) = b \cdot log(a)

Calculus

Limits

  • Right-Side Limit:                                                                                             \displaystyle  \lim_(x \to c^+) f(x)
  • Left-Side Limit:                                                                                               \displaystyle  \lim_(x \to c^-) f(x)

Limit Rule [Variable Direct Substitution]:                                                             \displaystyle \lim_(x \to c) x = c

L’Hopital’s Rule:                                                                                                     \displaystyle \lim_(x \to c) (f(x))/(g(x)) = \lim_(x \to c) (f'(x))/(g'(x))

Differentiation

  • Derivatives
  • Derivative Notation

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹  

Step-by-step explanation:

We are given the following limit:

\displaystyle  \lim_(x \to 0^+) x^\big{√(x)}

Substituting in x = 0 using the limit rule, we have an indeterminate form:

\displaystyle  \lim_(x \to 0^+) x^\big{√(x)} = 0^0

We need to rewrite this indeterminate form to another form to use L'Hopital's Rule. Let's set our limit as a function:

\displaystyle y = \lim_(x \to 0^+) x^\big{√(x)}

Take the ln of both sides:

\displaystyle lny = ln \Big( \lim_(x \to 0^+) x^\big{√(x)} \Big)

Rewrite the limit by including the ln in the inside:

\displaystyle lny = \lim_(x \to 0^+) ln \big( x^\big{√(x)} \big)

Rewrite the limit once more using logarithmic properties:

\displaystyle lny = \lim_(x \to 0^+) √(x)ln(x)

Rewrite the limit again:

\displaystyle lny = \lim_(x \to 0^+) (ln(x))/((1)/(√(x)))

Substitute in x = 0 again using the limit rule, we have an indeterminate form in which we can use L'Hopital's Rule:

\displaystyle \lim_(x \to 0^+) (ln(x))/((1)/(√(x))) = (\infty)/(\infty)

Apply L'Hopital's Rule:

\displaystyle \lim_(x \to 0^+) (ln(x))/((1)/(√(x))) = \lim_(x \to 0^+) \frac{(1)/(x)}{\frac{-1}{2x^\big{(3)/(2)}}}

Simplify:

\displaystyle \lim_(x \to 0^+) \frac{(1)/(x)}{\frac{-1}{2x^\big{(3)/(2)}}} = \lim_(x \to 0^+) -2√(x)

Redefine the limit:

\displaystyle lny = \lim_(x \to 0^+) -2√(x)

Substitute in x = 0 once more using the limit rule:

\displaystyle \lim_(x \to 0^+) -2√(x) = -2√(0)

Evaluating it, we have:

\displaystyle \lim_(x \to 0^+) -2√(x) = 0

Substitute in the limit value:

\displaystyle lny = 0

e both sides:

\displaystyle e^\big{lny} = e^\big{0}

Simplify:

\displaystyle y = 1

And we have our final answer.

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit:  Limits

Having trouble with this one

Answers

Answer:

Yes

Step-by-step explanation:

If the diagonals are perpendicular, then the slope of AC will be the opposite reciprocal of the slope of BD.

The slope of AC is:

m = (3 − 3) / (6 − 0) = 0

The slope of BD is:

m = (0 − 6) / (3 − 3) = undefined

The opposite reciprocal of 0 is undefined, so the diagonals are indeed perpendicular.

Specifically, AC is horizontal and BD is vertical.

Any help will mark brainliest

Answers

4 x 2 tens = 80, 28 x 14 = 392

The following rule describes the relationship between x and y.Rule: Multiply x by 4 to get y.
Complete the table for the given rule.
X Y
0 __
1 __
2 __

Answers

Y

0
4
8
Hope this helps :)

What percent of 68 is 34

Answers

Answer:

50

Step-by-step explanation:

Which inequality represents the situation: The cost, c is more than $6

Answers

Answer: C > $6

Step-by-step explanation:

C is greater than (but not equal to) $6

C > $6