Sound waves, water waves, and light waves are all alike in that they all

Answers

Answer 1
Answer: Sound and water waves are longitudinal waves, they require a medium to travel through and occilate particles 90 degrees to the wave motion
Light is a transverse wave. It doesnt require a medium to travel through.
All three reflect, refract and diffract


Light is difficult to think of because it acts in ways which waves cannot explain in some cirumstances. It acts like a particle (called photons) in some conditions, but acts like a normal sound or water wave does in others. Try not to get too caught up in light being a wave or a particle because even physists dont know how to explain it yet.
Answer 2
Answer:

Final answer:

Sound waves, water waves, and light waves all spread out from a source and can transfer energy without transporting matter. They obey the principle of superposition and can be reflected, refracted, and diffracted. Examples also in many practical scenarios support the concept.

Explanation:

All sound waves, water waves, and light waves share some common properties as they are all types of wave motion. These waves all spread out from a source and can transfer energy without transporting matter. They also follow the principle of superposition, where the resultant wave amplitude is the sum of the individual wave amplitudes. Additionally, they can be reflected, refracted, and diffracted.

For example, when throwing a pebble into a pond, the water waves spread out in rings from where the pebble was dropped (the source). The waves transfer the energy of the impact through the water, yet the water molecules themselves don't travel in the direction of the wave's motion—they merely move up and down.

The same principles apply to sound waves and light waves, though the type of energy transferred and the manner in which they're affected by the medium they're passing through can differ.

Learn more about Waves here:

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An acorn with a mass of 0.0300 kilograms falls from a tree. What is its kinetic energy when it reaches a velocity of 5.00 m/s?

Answers

Kinetic energy = 1/2 (mass) x (speed squared).

KE = 1/2 (0.03) x (5 x 5) = 0.375 kilogram-meter squared / second squared = 0.375 Joule.

What is the new weight of a 10kg object on a planet that has twice the earths mass. (assume that the radius of the planet is the same as earths)

Answers


Weight = (mass) x (acceleration of gravity) .

Acceleration of gravity on a planet's surface is proportional to

                         (planet's mass) / (planet's radius)² .

On Earth's surface, acceleration of gravity is 9.8 m/s² .

Weight of 10 kg mass = (10 kg) x (9.8 m/s²) = 98 newtons.

On the surface of a planet with twice the Earth's mass
all stuffed into the same radius, the acceleration of gravity
would be 19.6 m/s² ... double what it is on Earth.

Weight of 10 kg would be (10 kg) x (19.6 m/s²) = 196 newtons ...
double its Earth weight.

Assumes matter is made of small particles in constant motion

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Kinetic molecular Theory of Matter. This is the model or theory that you are looking for.

A bird can fly 30km/hr. How many hours does it take to fly 22,000 m?

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It would take a bird .73 repeating hours. 
The answer is (22/30) because 22000 m becomes 22 km.

When two gears are mashed, the revolutions per minute (rpm) are inversely proportional to the number of gears

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Not exactly.  The RPM is inversely proportional
to the number of teeth on the gears.

Note that in order for them to stay meshed, that'salso going to work out
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A very small 100-g object is attached to one end of a massless 10-cm rod that is pivoted without friction about the opposite end. The rod is held vertical, with the object at the top, and released, allowing the rod to swing. What is the speed of the object at the instant that the rod is horizontal?

Answers

Answer:

1.40071 m/s

Explanation:

m = Mass of object = 100 g

v = Velocity of object

h = Height of drop = 10 cm

g = Acceleration due to gravity = 9.81 m/s²

Here, the loss of potential energy is equal to the gain in kinetic energy as energy is conserved

mgh=(1)/(2)mv^2\n\Rightarrow gh=(1)/(2)v^2\n\Rightarrow v^2=2gh\n\Rightarrow v=√(2gh)\n\Rightarrow v=√(2* 9.81* 0.1)\n\Rightarrow v=1.40071\ m/s

The speed of the object at the instant that the rod is horizontal is 1.40071 m/s