A particle is being accelerated through space by a 10 N force. Suddenly the particle encounters a second of 10 N force in the opposite direction. The particle with both forces acting?

Answers

Answer 1
Answer:

Answer:

The particle will be rendered still

Explanation:

The particle will be rendered still because of the Newton’s 1st law of motion states that a body will continue to move on forever until contacted by an equal and opposite force. The same case has been produced here and it is justifying the law. If the Force has another direction and magnitude than 10 N then the body will continue to move on in the direction of the greater force.


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What is the bond between Hydrogen and Chlorine?

Answers

polar covalent bond
Hydrogen chloride is a diatomic molecule, consisting of a hydrogen atom H and a chlorine atom Cl connected by a polar covalent bond. The chlorine atom is much more electronegative than the hydrogen atom, which makes this bond polar.
covalent bond
chlorine and hydrogen atoms form a single covalent bond. in hydrogen chloride gas because the electrons are shared, not transferred from one atom to another. when it is dissolved in water to become hydrochloric acid.

Aristotle, the ancient Greek philosopher, thought that heavy objects fall to Earth faster than lighter objects. How could Aristotle's hypothesis be supported or disproved?

Answers

Gravitational potential energy=mass of object x gravitational field strength on earth(9.8 usually rounded to 10) x the height the object is held at

Therefore if two objects were held at the same height, the object with more mass(the heavier object) will fall faster because it's gravitational potential energy is greater than that of the lighter object

Is energy conserved when a ball falls to the ground

Answers

Of course. You've certainly heard that energy is conserved, period. Why would you think it's different when a ball falls to the ground ? ?

The current through a 10-ohm resistor connected to a 120-v power supply is

Answers

Answer:

12 A

Explanation:

Voltage, V = 120 V

Resistance, R  10 ohm

By using ohm's law

V = i x R

where, i is the current

i = V / R

i = 120 / 10

i = 12 A

thus, the current is 12 A.

A 1.00 l sample of a gas at 25.0◦c and 1.00 atm contains 50.0 % helium and 50.0 % neon by mass. what is the partial pressure of the neon. express your answer in atmospheres.

Answers

V = Volume of sample of gas = 1.00 L = 0.001 m³

T = temperature of the gas = 25.0 ⁰C = 25 + 273 = 298 K

P = pressure = 1.00 atm = 101325 Pa

n = number of moles of gas

using ideal gas equation

PV = n RT

101325 (0.001) = n (8.314) (298)

n = 0.041

n₁ = number of moles of helium

n₂ = number of moles of neon

m₁ = mass of helium = n₁ (4) = 4 n₁

m₂ = mass of neon = n₂ (20.2) = 20.2 n₂

given that :

m₁ = m₂

4 n₁ = 20.2 n₂

n₁ = 5.05 n₂

also

n₁ +  n₂ = n

5.05 n₂ +  n₂ = 0.041

n₂ = 0.0068

mole fraction of neon is given as

mole fraction = n₂ /n = 0.0068/0.041 = 0.166

P₂ = partial pressure of neon = (mole fraction) P

P₂ = (0.166) (1)

P₂ = 0.166 atm



The partial pressure of the neon is  0.16 atm.

Explanation:  

 A 1.00 l sample of a gas at 25.0◦c and 1.00 atm contains 50.0 % helium and 50.0 % neon by mass. what is the partial pressure of the neon. express your answer in atmospheres.

The partial pressure is the notional pressure of constituent gas if it is occupied alone by the entire volume of the original mixture at the same temperature.

50.0 % helium and 50.0 % neon by mass.

P = 1 atm

Mass of the gases = M

Moles of helium = (0.5M)/(4 g/mol)\nMoles of neon = (0.5M)/(20 g/mol)

By using ideal gas equation we get:

PV=nRT\nn=(PV)/(RT)=(1.00 L* 1.00 atm)/(0.0820 L atm/mol K* 298 K)=0.0409 mol

where n =total number of moles of gases

0.0409 mol=(0.5M)/(4 g/mol)+(0.5M)/(20 g/mol)

M = 0.2728 g

Then we can find the mass and mole of gases

The gas molar volume is the volume of one mole of the gas at a given temperature and pressure.

Mass of helium gas = (0.2728g)/(2)=0.1364 g

Moles of helium gas =n_1=(0.1364 g)/(4 g/mol)=0.0341 mole

Mass of neon gas  = (0.2728g)/(2)=0.1364 g

Moles of neon gas = n_2=(0.1364 g)/(20 g/mol)=0.00682mole

Partial pressure of the neon gas:P* \chi_2=P* (n_2)/(n_1+n_2)=1 atm* (0.00682)/(0.00682+0.0341)=0.16 atm

Therefore the partial pressure of the neon gas is 0.16 atm.

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Transforme 0,4m em mm

Answers

1m = 1000 mm

0,4m = 0,4 * 1000 = 400mm