PHYSICS HIGH SCHOOL

Determine the mass percent (to the hundredths place) of h in sodium bicarbonate (nahco3).

Answers

Answer 1

Answer:

The mass percent of H in NaHCO₃ is 1.19%

We'll begin by calculating the molar mass of NaHCO₃. This can be obtained as follow:

Molar mass of NaHCO₃ = 23 + 1 + 12 + (16×3)

= 23 + 1 + 12 + 48

= 84 g/mol

From the molar mass of NaHCO₃, we can see that 1 g of H is present in 84 g of the compound (NaHCO₃)

Finally, we shall determine the mass percent of H in NaHCO₃. This can be obtained as follow:

Mass of H = 1 g

Mass of NaHCO₃ = 84 g

Mass percent of H =?

Mass percent = $(mass of element )/(mass of compound ) X 100$

Mass percent of H = $(1)/(84)$ × 100

Mass percent of H = 1.19%

Therefore, the mass percent of H in NaHCO₃ is 1.19%

Learn more: brainly.com/question/18763214

Answer 2

Answer:

NaHCO3 = 84.0066 g/mol

H = 1.00794 g/mol

(1.00794 g/mol) / (84.0066 g/mol)

= 0.011998

= 1.20% H

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If two waves with EQUAL amplitudes and wavelengths travel through a medium in such a way that a particular of the medium is the crest of one wave and at the trough of the other wave at the same time, what will happen to that particle?

Select all that apply.There is no sound in the vacuum of space. Why?
Sound must travel through something that vibrates.
There is no energy in space.
There is no air to vibrate the human eardrum.
Space is too full of light energy.

Answers

Answer:

Sound must travel through something that vibrates.

There is no air to vibrate the human eardrum.

Explanation:

Waves can be divided into two types:

- Electromagnetic waves: these are waves produced by the oscillations of electric and magnetic field. This type of wave does not need a medium to propagate, so they can also travel through a vacuum

- Mechanical waves: these are waves produced by the vibrations of the particles in a medium - therefore, they do need a medium to propagate. Sound waves are part of this type, so they cannot travel through a vacuum.

According to these definitions, we can say that the correct choices are the following:

Sound must travel through something that vibrates. --> because they are mechanical waves

There is no air to vibrate the human eardrum. --> because they are mechanical waves

1. Sound must travel through something that vibrates.
and
3. There is no air to vibrate the human eardrum.

A clever engineer designs a "sprong" that obeys the force law fx =−q(x−xe)3, where xe is the equilibrium position of the end of the sprong and q is the sprong constant. for simplicity, we'll let xe =0m. then fx =−qx3.

Answers

The unit of q is N/m³.While the potential energy of the compressed spring will be $\rm U(x)= -(qx^4)/(4)$ .

What is the potential energy of spring?

When a springdeviates from its mean position, it attempts to regain equilibrium by applying a force that is equivalent to but opposite to the external force.

Spring force has been used in bicycle carriers and launchingmechanisms, where the energy generated by disrupting the spring'sbalance is used as potential energy.

The given equation for the force law is;

$\rm f_x =-q(x-x_e)$

Where,

$\rm x_e$ is equilibrium position of the end of the spring

q is a spring constant

If at equilibriumposition;

$\rm x_e=0$

$\rm F_X= -qx^3 \n\n \rm q = (F_x)/(x^3) \n\n$

So the unit derived will be;

q = N/m³

The potential energy of the spring is found by;

$\rm F_x=- (du)/(dx) \n\n U(x)= -\int\limits^x_0 {F(x)} \, dx \n\n U(x)= -\int\limits^x_0 -qx^3 \, dx \n\n U(x)=- (qx^4)/(4)$

Hence the unit of q is N/m³.While the potentialenergy of the compressed spring will be $\rm U(x)= -(qx^4)/(4)$ .

To learn more about the potential energy of spring refer to the link;

brainly.com/question/2730954

The objective of this question is to compute the units of q and calculate the expression for the P.E of the compressed spring

Answer:

q = N/m³

$\mathbf{U(x) = -(qx^4)/(4)}$

Explanation:

Given that:

The equation for the force law is:

$F_x = -q (x -x_e)^3$

where;

$x_e$ e = equilibrium position of the end of the spring

i.e. $x_e$ = 0

q = is the spring constant

Also;

$F_x = -qx^3$

From above the units of q can be calculated by making q the subject of the formula :

$q = (F_x)/(x^3)$

where x is in meters and F is in Netwon;

Then :

q = N/m³

The Potential energy P.E of the compressed spring can be calculated by using the integral:

$F_x = -(dU)/(dx)$

$U(x) = - \int F_x dx$

$U(x) = - \int ^x_0 (-qx^3) \ dx$

$\mathbf{U(x) = -(qx^4)/(4)}$

A stealth bomber is flying straight and level at a constant speed of 150 m/s at an altitude of 3500 m above the ground. It drops a bomb intended to hit a specific target on the ground. a) How long will it take for the bomb to hit the ground?

b) At what horizontal distance away from its target must the bomber release the bomb in order to strike its target?

**disregard air resistance**

Answers

$Height = (1)/(2) gt^2 \n \n 3500 = (1)/(2) (9.8)(t^2)\n \n3500 = 4.9t^2\n\nt^2 =714.285714286\n\n\boxed {t=26.73~seconds}$

$\sf Horizontal ~distance = velocity * time\n\n Horizontal distance =150 * 26.73 \n\nHorizontal ~distance =4009.5$

The amount of matter in a substance or object is called:
??? What the answer

Answers

Answer:

mass!!

Explanation:

You are at the Super Bowl. The coach puts you in during the 4th quarter to be the quarterback to secure your team the win. Since you are fresh off the bench, you are able to throw the ball with more force than the last person. What advantages, using Newton's second law, will this have when playing?

Answers

Answer:

the ball will fly faster, and longer distance, which means there is going to be less air resistnace friction acting upon the ball.

Explanation:

F = ma

Force = mass x acceleration

Mass of football remains constant, fresh arm of QB provides higher acceleration.

Ball will get to receiver faster.

According to Newton's 2nd law of motion, if you hit a baseball with a bat it will _____.