20. What is the density of a fluid with a massof 10 kg that takes up a space of 60 mL?

Answers

Answer 1

Answer: Density = mass / volume. For that particular fluid, Density = (10,000 gm)/(60 ml) = (166 and 2/3) gm per ml. (That's roughly 8 times the density of the most dense substance on Earth.)

Related Questions

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Current is constant at all points in a parallel circuit
The material through which a mechanical wave travels is
What is the currency for performing work and what is its unit?
Which of the following questions would be answered using concepts from physics?A. What are the forces that cause a pendulum to swing? B. How does rust form from iron and water? C. How high will a thrown object rise before gravity pulls it back to Earth? D. In what ratio do hydrogen and oxygen combine to form water?

What is the electric field experienced by a charged balloon if the charge on the balloon is 9.4 × 10-10 coulombs and the force it experiences is 8.2 × 10-2 newtons?

Answers

Answer:

Electric field, $E=8.72* 10^7\ N/C$

Explanation:

It is given that,

Charge on the balloon, $q=9.4* 10^(-10)\ C$

Force experienced by the balloon, $F=8.2* 10^(-2)\ N$

The relation between electric force and electric field is given by :

$E=(F)/(q)$

$E=(8.2* 10^(-2))/(9.4* 10^(-10))$

$E=8.72* 10^7\ N/C$

Hence, the electric field experienced by a charged balloon is $8.72* 10^7\ N/C$

We know, F = q.E
E = F/q
Here, F = 8.2 * 10⁻²
q = 9.4 * 10⁻¹⁰

Substitute values into the expression:
E = 8.2 * 10⁻² / 9.4 * 10⁻¹⁰
E = 8.72 * 10⁷ N/C

Hope this helps!

When Emma pushes a bag with a force of 27 newtons, the coefficient of kinetic friction between the bag and the floor is 0.23. What is the normal force acting on the bag by the floor?

Answers

This can be answered by manipulating the formula for the coefficient of kinetic friction, which is as follows:

Let: μ = coefficient of kinetic friction
F = force
N = normal force

μ = F / N

Substituting the given values:

0.23 = 27N / N
N = 27 / 0.23
N = 117.39 N

A 2,100 kg car is lifted by a pulley. If the cable breaks at 4.50 m, what is the velocity of the car when it hits the ground

Answers

The problem involves the conversion of potential energy to kinetic energy as the object falls from rest. Energy is conserved, so the equation used is:

PEi + KEi = PEf + KEf

Since the object is falling from rest, the initial kinetic energy is zero. Also, since the object hits the ground at its final position, the final potential energy is zero. This leaves:

PEi = KEf
mgh = 1/2 mv^2

*cancel out mass on both sides of the equation

gh = 0.5v^2
v = sqrt(2gh) = sqrt(2*9.81*4.5) = 9.40 m/s --> final ans.

A ball of a mass 0.3 kg is released from rest at a height of 8 m. How fast is it going when it hits the ground? Acceleration due to gravity is g=9.8 m/s^2

Answers

In order to solve this problem, there are two equations that you need to know to solve this problem and pretty much all of kinematics. The first is that d=0.5at^2 (d=vertical distance, a=acceleration due to gravity and t=time). The second is vf-vi=at (vf=final velocity, vi=initial velocity, a=acceleration due to gravity, t=time). So to find the time that the ball traveled, isolate the t-variable from the d=0.5at^2. Isolate the t and the equation now becomes $√((2d)/a)$ . Solving the equation where d=8 and a=9.8 makes the time $√((2*8)/9.8)$ =1.355 seconds. With the second equation, the vi=0 m/s, the vf is unknown, a=9.8 m/s^2 and t=1.355 sec. Substitute all these values into the equation vf-vi=at, this makes it vf-0=9.8(1.355). This means that the vf=13.28 m/s.

Answer:

The answer is 12.5 m/s

v=the square root of 2 x(gh)

or v = the square root of 2 x (9.8 x 8)

Explanation:

What type of force pulls in two opposite directions?a. tension (associated with normal faults)
b. normal (associated with longitudinal faults)
c. transform (associated with transform faults)
d. compression (associated with reverse faults)
Which is not a type of fault?
a. normal
b. reverse
c. diagonal
d. transform

Answers

Answer

a. tension (associated with normal faults)

c. diagonal

Explanation

A pull of spring or of string on both ends of an object is called tension. So for the question one, the answer is tension (associated with normal faults)

There are three types of faults. Faults are produced by stress or strain by moving plates. These faults are: normal faults, reverse faults and transcurrent or Strike-slip. Strike-slip faults can also be called transform fault. The answer to the second question is c. diagonal.

Answer:

Tension Force (associated with normal faults)

Explanation:

As we know that tension force is an internal force between the molecules which opposes the tendency of molecules to separate out.

The tension force of string is always in opposite directions at two ends of string and it is always along the length

Answer:

Diagonal

Explanation:

As we know that there are four types of vaults

1) Normal vaults

2) Longitudinal vaults

3) Reverse vaults

4) Transform vaults

Which of the following is not an integer?A. -52/13
B. -3.0
C. 48/6
D. 48/5

Answers

Answer:

The answer is D.

Explanation:

A integer can be positive, negative, or 0. So by simplifying all the fractions (making them into mixed numbers) we can find out that D results in a decimal, which is not a integer.

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