Test the hypotheses below with the given data. let alpha = 0.05. sample 1: average = 138.4, sigma = 6.71, sample size = 48 sample 2: average = 142.5, sigma = 8.92, sample size = 39 this is an example of

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Answer 1

Answer:

solution: this question solution is:-

Hypothesis testing with two populations.

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A null hypothesis is that the mean nose lengths of men and women are the same. The alternative hypothesis is that men have a longer mean nose length than women. A statistical test is done and the p-value is 0.225. Which of the following is the most appropriate way to state the conclusion? a. The mean nose lengths of the populations of men and women are identical. b. There is not enough evidence to say that the populations of men and women have different mean nose lengths. c. Men have a greater mean nose length. d. The probability is 0.225 that men and women have the same mean nose length

Answers

Answer:

b. There is not enough evidence to say that the populations of men and women have different mean nose lengths.

See explanation below.

Step-by-step explanation:

Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the means for the two groups are different (men have longer mean nose length than women), the system of hypothesis would be:

Null hypothesis: $\mu_(men) \leq \mu_(women)$

Alternative hypothesis: $\mu_(men) > \mu_(women)$

Assuming that we know the population deviations for each group, for this case is better apply a z test to compare means, and the statistic is given by:

$z=\frac{\bar X_(men)-\bar X_(women)}{\sqrt{(\sigma^2_(men))/(n_(men))+(\sigma^2_(women))/(n_(women))}}$ (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Let's assume that the calculated statistic is $z_(calc)$

Since is a right tailed test test the p value would be:

$p_v =P(Z>z_(calc))=0.225$

And we know that the p value is 0.225. If we select a significance level for example 0.05 or 0.1 we see that $p_v >\alpha$

And on this case we have enough evidence to FAIl to reject the null hypothesis that the means are equal. So then the best conclusion would be:

b. There is not enough evidence to say that the populations of men and women have different mean nose lengths.

Amy goes to a pumpkin patch and picks out a pumpkin that weighs 3,550 grams. If 1 gram = 0.0352 ounces, how many ounces does the pumpkin weigh? A) 124.56 ounces
B) 124.96 ounces
C) 125.56 ounces
D) 125.96 ounces

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9514 1404 393

Answer:

B) 124.96 ounces

Step-by-step explanation:

To find ounces, multiply the number of grams by the number of ounces in each gram.

3550 × 0.0352 = 124.96 . . . ounces

A _________________is a numerical value that describes a population.

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Answer:

A parameter is a numerical value that describes a population.

Step-by-step explanation:

hope it helps

Answer: parameter

Step-by-step explanation:

What is the greatest common factor of 5x^6+35x^4+15x^3

Answers

5 will go into everything. That is one of the factors.

x^3 is in everything as well.

The highest common factor is 5x^3

$(5x^6)/(5x^3) = x^(6-3) = x^3$

$(35x^4)/(5x^3) = 7x^(4-3) = 7x$

$(15x^3)/(5x^3) = 3*x^(3-3) = 3*1 = 3$

So the greatest common factor (determined by the last term) is 5x^3

And the left over polynomial is x^3 + 7x + 3

Over the past several months, the water level of a lake has been decreasing by 3% each week. If the highest water level before the decrease started was 520 ft, what was the level at the end of 8 weeks?