An independent random sample is selected from an approximately normal population with unknown standard deviation. Find the degrees of freedom and the critical t-value for the given sample size and confidence level.(a) n = 6, CL = 90%(b) n = 21, CL = 98%(c) n = 29, CL = 95%(d) n = 12, CL = 99%

Answers

Answer 1
Answer:

(a) For n = 6, CL = 90%,  

The degrees of freedom: 5, Critical t-value: 2.571

(b) For n = 21, CL = 98%,

The degrees of freedom: 20, Critical t-value: 2.845

(c) For n = 29, CL = 95%,

The degrees of freedom: 28, Critical t-value: 2.048

(d) For n = 12, CL = 99%,

The degrees of freedom: 11, Critical t-value: 3.106

Use the concept of critical t- value defined as:

A critical value is a number that is used in hypothesis testing to compare to a test statistic and evaluate whether or not the null hypothesis should be rejected. The null hypothesis cannot be rejected if the test statistic's value is less extreme than the crucial value.

(a) Given that,

n = 6 and a confidence level of 90%,

The degrees of freedom are,

n-1 = 6-1

The degrees of freedom = 5.

To find the critical t-value,

Look it up in the t-distribution table using a confidence level of 90% and a degree of freedom of 5.

From the table,

The critical t-value is approximately 2.571.

(b) Given that,

n = 21 and a confidence level of 98%,

The degrees of freedom are,

n-1 = 21-1

The degrees of freedom = 20.

By referring to the t-distribution table with a confidence level of 98% and degrees of freedom of 20,

The critical t-value is approximately 2.845.

(c) Given that,

n = 29 and a confidence level of 95%,

The degrees of freedom are,

n-1 = 29-1

The degrees of freedom = 28

Using the t-distribution table with a confidence level of 95% and degrees of freedom of 28,

The critical t-value is approximately 2.048.

(d) Given that,

n = 12 and a confidence level of 99%,

The degrees of freedom are,

n-1 = 12-1

The degrees of freedom = 11

By consulting the t-distribution table with a confidence level of 99% and degrees of freedom of 11,

The critical t-value is approximately 3.106.

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Answer 2
Answer:

Final answer:

To find the degrees of freedom and critical t-value for each given sample size and confidence level, we can use the t-distribution and a t-table. The degrees of freedom (df) for each sample is equal to the sample size minus 1. The critical t-value can be found using the t-table with the corresponding degrees of freedom and the confidence level.

Explanation:

To find the degrees of freedom and critical t-value for each given sample size and confidence level, we can use the t-distribution and a t-table. The degrees of freedom (df) for each sample is equal to the sample size minus 1. For example, for (a) n = 6, df = 6 - 1 = 5. The critical t-value can be found using the t-table with the corresponding degrees of freedom and the confidence level.

For (a) n = 6, CL = 90%, the critical t-value is approximately 1.943.

For (b) n = 21, CL = 98%, the critical t-value is approximately 2.861.

For (c) n = 29, CL = 95%, the critical t-value is approximately 2.045.

For (d) n = 12, CL = 99%, the critical t-value is approximately 3.106.

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Answers

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Or
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Answers

Answer:

h^(-1)(x)=x^3+6x^2+12x+7

Explanation:

Given the below function;

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Applying the above, we'll have;

\begin{gathered} (x+2)^3=y+1 \n x^3+3x^2\cdot2+3x\cdot2^2+2^3=y+1 \n x^3+6x^2+12x+8=y+1 \end{gathered}

Step 6: Subtract 1 from both sides of the equation;

\begin{gathered} x^3+6x^2+12x+8-1=y+1-1 \n x^3+6x^2+12x+7=y \n \therefore y=x^3+6x^2+12x+7 \end{gathered}

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Answers

Answer:

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Step-by-step explanation:

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  ((a-r) +(b-r))^2 = (2r)^2 +(b -a)^2

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  -4r(a+b) = -4ab . . . . . . . . subtract common terms from both sides, also -2ab

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Answers

Answer:

160

Step-by-step explanation:

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Answers

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Answers

Answer:

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