Answer:
Hygroscopic substances
Explanation:
Hygroscopic compounds are those that absorb moisture and a large amount of water and they become wet. They should not be confused with deliquescent substances that absorb water and forms solution.
Hygroscopic substances froms pasty substances and not solution while the liquid ones only becomes diluted. Examples are sodium trioxonitrate(v) (NaNO₃), copper (ii) oxide CuO, and concentrated tetraoxosulphate (vi) acid (H₂SO₄)
Hydrophilic substances, like cellulose found in cotton and paper pulp, can soak up large amounts of water. Some chemical compounds, such as sodiumcarbonate decahydrate and copper(II) sulfate pentahydrate, have this property. Moreover, phosphorus(V) oxide, although used for removing water from compounds, also shows a great affinity for water.
A compound that has the ability to soak up large amounts of water is termed a hydrophilic substance. Hydrophilic substances are attracted to water, absorbing it readily. For example, cotton and paper pulp, used in towels, are made of molecules of cellulose that contain many –OH groups.
Water molecules are attracted to these -OH groups and form hydrogen bonds with them, drawing large amounts of H₂O up the cellulose fibers. Additionally, some compounds like sodium carbonate decahydrate and copper(II) sulfate pentahydrate also have the ability to soak up water. Another example is phosphorus(V) oxide, which has a great affinity for water and is used for removing water from compounds.
#SPJ12
B. exothermic.
C. spontaneous.
D. endothermic.
Answer:
163.940671 grams
Explanation:
You can view more details on each measurement unit: molecular weight of Na3PO4 or grams This compound is also known as Trisodium Phosphate. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Na3PO4, or 163.940671 grams.
Helppp
Answer:F =MAX
Explanation:I did that
Answer:
F=MAX
Explanation:
I DID THAT TODAY AT 9:05AM FRIDAY 1/22/2021
The correct answer is 9.6h.
As you know, a radioactive isotope's nuclear half-life tells you exactly how much time must pass in order for an initial sample of this isotope to be halved.
Using the formula , A = Ao.
where , A- final mass after decay
Ao - initial mass
n - the number of half-lives that pass in the given period of time
Now, putting all the values, we get
1.3 × mg = 0.050 mg ×
Take the natural log of both sides of the equation to get,
㏑ = ㏑
㏑ = n. ln
n = 1.6
Since n represents the number of half-lives that pass in a given period of time, you can say that
t= 1.6 × 6 h
t = 9.6h
Hence, it will take 9.6 h until the radioactive isotope decays.
Learn more about radioactive isotope andhalf life here:-
#SPJ1
Using the formula for radioactive decay and the provided half-life of technetium-99m, it can be calculated that it takes approximately 28.5 hours for 0.050 mg of technetium-99m to decay to a quantity of 1.3 x 10^-2 mg.
The decay of a radioactive isotope is an exponential process based on the half-life, which is, in turn, constant for any given isotope. The general formula for the remaining quantity of a radioactive isotope after a given time is given by: N = N0 (0.5) ^(t/t1/2), where (N0) is the initial amount, (N) is the remaining amount, (t) is time, and (t1/2) is the half-life of the isotope. In this case, we are given the initial quantity (N0 = 0.050 mg), the remaining quantity (N = 1.3 x 10^-2 mg), and the half-life (t1/2 = 6.0 hours).
We can solve for time (t) in the equation: N = N0 (0.5) ^(t/t1/2). Plugging in the values, we get 1.3 x 10^-2 = 0.050 x (0.5)^(t/6), and solving for t, we find that it takes approximately 28.5 hours for the technetium-99m to decay to 1.3 x 10^-2 mg.
#SPJ11
Answer:
In polar coordinates, the origin is called the pole.
Explanation:
The position of a point in a polar coordinate system is defined by using the distance from a fixed point and an angle made with a fixed ray from that point. It is a two-dimensional coordinate system.
The polar coordinates is defined as
Where, r is radius and θ is the angle with the polar axis, i.e. positive axis.
In a coordinate system (0,0) is called origin.
In polar coordinate system (0,0) is called pole.
Therefore, in polar coordinates, the origin is called the pole.