What is a compound called that has the ability to soak up large amounts of water?

Answers

Answer 1
Answer:

Answer:

Hygroscopic substances

Explanation:

Hygroscopic compounds are those that absorb moisture and a large amount of water and they become wet. They should not be confused with deliquescent substances that absorb water and forms solution.

Hygroscopic substances froms pasty substances and not solution while the liquid ones only becomes diluted. Examples are sodium trioxonitrate(v) (NaNO₃), copper (ii) oxide CuO, and concentrated tetraoxosulphate (vi) acid (H₂SO₄)

Answer 2
Answer:

Final answer:

Hydrophilic substances, like cellulose found in cotton and paper pulp, can soak up large amounts of water. Some chemical compounds, such as sodiumcarbonate decahydrate and copper(II) sulfate pentahydrate, have this property. Moreover, phosphorus(V) oxide, although used for removing water from compounds, also shows a great affinity for water.

Explanation:

A compound that has the ability to soak up large amounts of water is termed a hydrophilic substance. Hydrophilic substances are attracted to water, absorbing it readily. For example, cotton and paper pulp, used in towels, are made of molecules of cellulose that contain many –OH groups.

Water molecules are attracted to these -OH groups and form hydrogen bonds with them, drawing large amounts of H₂O up the cellulose fibers. Additionally, some compounds like sodium carbonate decahydrate and copper(II) sulfate pentahydrate also have the ability to soak up water. Another example is phosphorus(V) oxide, which has a great affinity for water and is used for removing water from compounds.

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Transferring or sharing electrons between atoms forms

Answers

It forms something called a bond.

A reaction that occurs when the reactants are simply put together isA. automatic.
B. exothermic.
C. spontaneous.
D. endothermic.

Answers

The answer is C. spontaneous. Spontaneous reactions occur without being driven by an outside force.
Hope that helped you.
C. spontaneous would be ur answer!

Hope I helped:P

What is the mass of 1 mole of Na3,PO4?

Answers

Answer:

163.940671 grams

Explanation:

You can view more details on each measurement unit: molecular weight of Na3PO4 or grams This compound is also known as Trisodium Phosphate. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Na3PO4, or 163.940671 grams.

Helppp meee plzzz plzzzz
Helppp

Answers

Answer:F =MAX

Explanation:I did that

Answer:

F=MAX

Explanation:

I DID THAT TODAY AT 9:05AM FRIDAY 1/22/2021    

A patient is given 0.050 mg of technetium-99 m (where m means metastable—an unstable but long-lived state), a radioactive isotope with a half-life of about 6.0 hours.How long until the radioactive isotope decays to 1.3×10−2 mg ?

Answers

The correct answer is 9.6h.

As you know, a radioactive isotope's nuclear half-life tells you exactly how much time must pass in order for an initial sample of this isotope to be halved.

Using the formula , A = Ao.1/2^n

where , A- final mass after decay

Ao - initial mass

n - the number of half-lives that pass in the given period of time

Now, putting all the values, we get

1.3 × 10^-2 mg = 0.050 mg × 1/ 2^n

Take the natural log of both sides of the equation to get,

(1.3 . 10^(-2) / 0.050 ) = ㏑((1/2)^(n))

(1.3 . 10^(-2) / 0.050 ) = n. ln(1/2)\n

n = 1.6

Since n represents the number of half-lives that pass in a given period of time, you can say that

n = t /  t _(1/2)

t= 1.6 × 6 h

t = 9.6h
Hence, it will take 9.6 h  until the radioactive isotope decays.

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Final answer:

Using the formula for radioactive decay and the provided half-life of technetium-99m, it can be calculated that it takes approximately 28.5 hours for 0.050 mg of technetium-99m to decay to a quantity of 1.3 x 10^-2 mg.

Explanation:

The decay of a radioactive isotope is an exponential process based on the half-life, which is, in turn, constant for any given isotope. The general formula for the remaining quantity of a radioactive isotope after a given time is given by: N = N0 (0.5) ^(t/t1/2), where (N0) is the initial amount, (N) is the remaining amount, (t) is time, and (t1/2) is the half-life of the isotope. In this case, we are given the initial quantity (N0 = 0.050 mg), the remaining quantity (N = 1.3 x 10^-2 mg), and the half-life (t1/2 = 6.0 hours).

We can solve for time (t) in the equation: N = N0 (0.5) ^(t/t1/2). Plugging in the values, we get 1.3 x 10^-2 = 0.050 x (0.5)^(t/6), and solving for t, we find that it takes approximately 28.5 hours for the technetium-99m to decay to 1.3 x 10^-2 mg.

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In polar coordinates, the origin is called the _____.

Answers

In polar coordinates, the origin is called the pole. Polar coordinate system is actually a two dimensional coordinate system. In this type of system the reference point is known by the name of pole. I hope that this is the answer that you were looking for and the answer has come to your desired help.

Answer:

In polar coordinates, the origin is called the pole.

Explanation:

The position of a point in a polar coordinate system is defined by using the distance from a fixed point and an angle made with a fixed ray from that point. It is a two-dimensional coordinate system.

The polar coordinates is defined as

P(r,\theta)

Where, r is radius and θ is the angle with the polar axis, i.e. positive axis.

In a coordinate system (0,0) is called origin.

In polar coordinate system (0,0) is called pole.

Therefore, in polar coordinates, the origin is called the pole.