Answer:
Was this correct? I am pretty sure it is since you are going from a solid to a gas in the first reaction.
Explanation:
(1) CaCO3(s) --> CaO(s) + CO2(g) --- solid to solid & gas ** most entropy here
(2) 2 Mg(s) + O2(g) --> 2 MgO(s) solid & gas to a solid
(3) H2O(g) --> H2O(l) gas to a liquid
(4) CO2(g) --> CO2(s) gas to a solid
As temperature rises and a substance transforms from a solid to a liquid to a gas, entropy increases. Because they have the most flexibility to move, gases have the highest entropy values. Here the first reaction has high entropy. The correct option is 1.
The level of unpredictability in a system is known as entropy. The degree of randomness is highest when comparing the three forms of matter solid, liquid, and gas because the gas particles move freely.
(1) CaCO3(s) --> CaO(s) + CO2(g) --- solid to solid & gas - most entropy here
(2) 2 Mg(s) + O2(g) --> 2 MgO(s) solid & gas to a solid
(3) H2O(g) --> H2O(l) gas to a liquid
(4) CO2(g) --> CO2(s) gas to a solid
Thus the correct option is 1.
To know more about entropy, visit;
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become?
Answer:
A physicist
Explanation:
A physicist is one who deals with matter energy and how they are related
(B) The equation is not balanced.
(C) The valence of the nitride ion is incorrect.
(D) The valance of the magnesium ion is incorrect.
(E) The coefficient of N₂ is incorrect.
Can someone explain this one?
To round off the measurement 3255 mL to three significant digits, the correct answer is (c) 3250 mL.
To round off a measurement to three significant digits, we look at the digit to the right of the third significant digit. If this digit is 5 or greater, we round up. If it is less than 5, we round down. In the given measurement of 3255 mL, the digit to the right of the third significant digit is 5, so we round up. Therefore, the correct answer is (c) 3250 mL.
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reactivity increases
atomic radius increases
atomic mass increases
valence electrons decrease
Answer : The net ionic equation will be,
Explanation :
In the net ionic equations, we are not include the spectator ions in the equations.
Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.
The balanced ionic equation will be,
The ionic equation in separated aqueous solution will be,
In this equation, are the spectator ions.
By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.
The net ionic equation will be,