D = distance between the cars at the start of time = 680 km
v₁ = speed of one car
v₂ = speed of other car = v₁ - 10
t = time taken to meet = 4 h
distance traveled by one car in time "t" + distance traveled by other car in time "t" = D
v₁ t + v₂ t = D
(v₁ + v₂) t = D
inserting the values
(v₁ + v₁ - 10) (4) = 680
v₁ = 90 km/h
rate of slower car is given as
v₂ = v₁ - 10
v₂ = 90 - 10 = 80 km/h
The slower car travels at 75 km/hr while the faster car travels at 85 km/hr. They meet up after both traveling for 4 hours, thereby covering the 680 kilometers between them.
The subject of this question is algebra - specifically involving rates of speed and time. Here's how you would find the answer:
The result would be 75 km/hr for the slower car and 85 km/hr for the faster car. They meet up after both traveling for 4 hours, thereby covering the 680 kilometers between them.
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Air from the equator moves toward the poles slower than the ground below it, so friction causes the air to veer east. In contrast, air from the poles moves toward the equator faster than the ground below it, so friction causes it to veer to the west.
B.
Air from the equator moves toward the poles faster than the ground below it, so friction causes the air to veer west. In contrast, air from the poles moves toward the equator slower than the ground below it, so friction causes it to veer to the east.
C.
Air from the equator moves toward the poles faster than the ground below it, so friction causes the air to veer east. In contrast, air from the poles moves toward the equator slower than the ground below it, so friction causes it to veer to the west.
D.
Air from the poles moves toward the equator faster than the ground below it, so friction causes the air to veer east. In contrast, air from the equator moves toward the poles slower than the ground below it, so friction causes it to veer to the west.
Answer:
The answer to your question is A. Hope this helped
B. moving with a constant speed
C. slowing down
D. maintaining a constant velocity
Answer:
Zero acceleration means velocity that's not changing.
Explanation:
Answer:
The mass of the dog food added is 9.03 kg
Explanation:
Given;
mass of the shopping cart, m₁ = 14.5 kg
let the mass of the bag added = m₂
the force applied, F = 12 N
initial velocity of the cart-bag system, u = 0
distance traveled by the system, d = 2.29 m
time of motion of the system, t = 3.0 s
The acceleration of the system is calculated as;
The total mass of the system (M) is calculated as follows;
F = Ma
M = F/a
M = (12)/(0.51)
M = 23.53 kg
The mass of the dog food added is calculated as;
m₂ = M - m₁
m₂ = 23.53 kg - 14.5 kg
m₂ = 9.03 kg
Answer:
Explanation:
Case I:
initial velocity, u = 0 m/s
Final velocity, v' = v Sinθ /g
Height = h
acceleration = g
Use third equation of motion, we get
. ... (1)
Case II:
initial velocity, u = v1
Final velocity, v = v2
height = h
acceleration due to gravity = g
Use third equation of motion, we get
Substitute the value of h from equation (1) ,we get
B) they would not be able to see anything outside the window.
C) lasers can not be transmitted through the vacuum of space.
D) the sound of the explosion would not be transmitted back to their ship.
Answer:
D. the sound of the explosion would not be transmitted back to their ship.
Explanation:
Sound is a type of mechanical wave so it needs a solid to move through. Since space is a vacuum, the Klingon crew would not be able to hear the explosion.
height?
(1) 0.0 N (3) 5.0 N, down
(2) 5.0 N, up (4) 9.8 N, down