what organ absorbs excess water from undigested food prior to its release from the body as a solid waste

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Related Questions

The metric unit of force is _____. kg kg/cm3 kg/cm2 N
Which temperature corresponds to standard temperature as 0 degrees Celsius? a. 273 K b. 100 K c. 32 K d. 0 K
Does a stick of dynamite contain force?
Which of the following is a result of reduced levels of red blood cells and elevated levels of white blood cells in the body?
Two physics students, Ben and Bonnie, are in the weightlifting room. Bonnie lifts the 50 kg barbell over her head (approximately .60 m) 10 times in one minute; Ben lifts the 50 kg barbell the same distance over his head 10 times in 10 seconds. Which student does the most work? Which student delivers the most power? Explain your answers.

What is the minimum speed with which he’d need to run off the edge of the cliff to make it safely to the far side of the river? the answer was 6 m/s the world-record time for the 100 m dash is approximately 10 s. given this, is it reasonable to expect brady to be able to run fast enough to achieve brady's leap? a.yes, the obtained speed is less than the world-record.
b.yes, the obtained speed is almost equal to the world-record.
c.no, the obtained speed is greater than the world-record.
d.no, the obtained speed is almost equal to the world-record.

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The answer is

A. Yes, the obtained speed is less than the world record

The explanation:

when the obtained speed is 6 m /s

and the world record speed = distance / time = 100 m / 10 s = 10 m/s

So, Yes, the obtained speed is less than the world record

Not only is it less, its also a reasonable average speed for a somewhat athletic person. Therefore, the leap is entirely possible.

-Samuel Brady gained his lasting notoriety for his leap over the Cuyahoga River around 1780 in what is now Kent, Ohio. After following a band of Indians into the Ohio country, a failed ambush attempt resulted in the band chasing Brady near the Cuyahoga River. To avoid capture, Brady leaped across a 22-foot (6.7 m) wide gorge of the river (which was widened considerably in the 1830s for construction of the Pennsylvania and Ohio Canal) and fled to a nearby lake where he hid in the water under a fallen tree using a reed for air.

Part (a): The minimum speed of Brady should be \boxed{6\text{ m/s}} to cross the cliff.

Part (b): The speed of Brady’s leap is possible to achieve, as it is less than the speed of world record.

Further Explanation:

(a)

Brady jumps from a cliff to go on other side. He crosses 22\text{ ft} horizontal distance from a height of 20\text{ft}. To jump from cliff, he follows the Newton’s law of motion.

Given:

The horizontal distance is 22\text{ ft}.

The vertical distance is 20\text{ft}.

Concept:

The horizontal distance in meter is 6.71\text{ m}.

The vertical distance in meter is 6.10\text{ m}.

To obtain the time of flight, applying one of the equation of motion given as:

s=ut+(1)/(2)at^2

Substitute 0\text {m/s} for u and rearrange the above equation for t :

t=\sqrt{(2s)/(a) }

Substitute 6.10\text{ m} for s and 9.81\text{ m}/\text{s}^2 for a in above equation.

\begin{aligned}t&=\sqrt{(2*6.10)/(9.81)}\text{ s}\n&=1.12\text{ s}\end{aligned}

The time of flight and time taken to cover horizontal distance are equal.

Horizontal velocity of Brady given as:

\begin{aligned}v&=(6.71)/(1.12)\text{ m/s}\n&\approx6\text{ m/s}\end{aligned}

Thus, the minimum speed of Brady should be \boxed{6\text{ m/s}} to cross the cliff.

(b)  

The minimum speed with which Brady is running is 6\text{ m/s}.

The speed of world record given as:

\begin{aligned}V&=(100)/(10)\text{ m/s}\n&=10\text{ m/s}\end{aligned}  

Thus, the speed of Brady’s leap is possible to achieve, as it is less than the speed of world record.

Learn more:

1. Projectile motion of a body: brainly.com/question/11023695

2. Body in pure rolling motion: brainly.com/question/9575487

3. Newton’s law of motion: brainly.com/question/6125929

Answer Details:

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords:

1780, Brady's Leap, Captain, Sam, U.S. Continental Army, horizontally, cliff, Ohio's Cuyahoga, gorge, leap, 22 ft, 20 ft, minimum, speed, river, 100 m, dash, 10 s, jump, time of flight, vertical and distance.

Choose the best answer for each situation. A scientist with the EPA examining water for contamination writes down that there was an iridescent sheen on the surface of the water. What type of data did the scientist record?

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The scientist has written down and example of qualitative data. Since he specifically wrote down that there was an iridescent sheen on the surface of the water, he is writing down the quality of water as seen by him. The type or condition cannot be expressed numerically, which makes it a qualitative type of data.

A 25.0-meter length of platinum wire with a cross-sectional area of 3.50 × 10^−6 meter^2 has a resistanceof 0.757 ohm at 20°C. Calculate the resistivity of the wire. [Show all work, including the equation and
substitution with units.]

Answers

The resistivity of the plantinum wire is 1.06 × 10⁻⁷Ωm

Calculating Resistivity

From the question,

We are to determine the resistivity of the wire

Resistivity can be calculated from the formula

\rho = (RA)/(l)

Where \rho is the resistivity of the wire

R is the resistance

A is the cross-sectional area

and l is the length of the wire

From the given information,

R = 0.757 ohm (Ω)

A = 3.50 × 10⁻⁶ m²

l = 25.0 m

Putting the parameters into the formula, we get

\rho = (0.757 * 3.50 * 10^(-6) )/(25)

\rho = 0.10598 * 10^(-6)

\rho = 1.0598 * 10^(-7)

\rho \approx 1.06 * 10^(-7) \ \Omega m

Hence, the resistivity of the plantinum wire is 1.06 × 10⁻⁷Ωm

Learn more on Calculating Resistivity here: brainly.com/question/5595373

R= (rou * L) / area
where R is the wire resistance
rou: resistivity of the wire material
L : wire length
A : cross section area of wire
by sub.
0.757= (rou*25)/ 3.5*10^-6
25*rou = 2.6495*10^-6
rou= 1.0598*10^-7 ohm.m

Displacement vectors of 5 km north, 3 km east, 2 km south, and 3 km west combine to a total displacement of___. A. 3 km north.. B. 13 km west.. C. 0 km.. D. 2 km south..

Answers

The answer is A. 3 km north

Displacement (D) is the shortest distance from the initial to the final position.
In this example distance is 5 km north - 2 km south = 3 km north (look at the image).

Answer: Forces and Motion Unit Test (Connexus)

1. A. 3 km north

2.B. The airplane

3. C. at a particular instant

4. D. all of the above

5. C. the front seat of the car

6. C. inertia

7. C. one-third its weight on Earth's surface

8.D. gravity

9.D. all of the above

10. C. Pascal's principle

11.D. The weight of the balloon is less than the weight of the air displaced by the balloon

12.C. fluid displaced by the object

13. displacement

14.vector addition

15. positive

16 projectile

17. force,mass

18. increases

19.equally

These are the answers I put for the typed out Essay's

20. Speed is the distance traveled by an object where as, velocity is distance traveled by an object per unit time in a particular direction. Speed is a scaler quantity where as velocity is a vector quantity.

21. Acceleration is the rate of change, which means the change in velocity (vf-vi) with time(t) Where vf if the final velocity and vi is the initial velocity

22. Acceleration can be described as changes in speed, direction or both. The ball is moving at a constant speed, but its direction is changing continuously Because it's direction is changing, the ball is experiencing continuous acceleration.

23. For graph A, I can say that velocity is constant until it reaches time of 8 seconds and a constant velocity is again exhibited starting at time 12 seconds

24. For Graph B, the velocity is changing as time pass by since the slope is changing, At time of 2 seconds, graph A has greater velocity since it has a steeper slope.

25. 300 meters

26. Graph A shows greater velocity because Graph A has a steeper slope than Graph B.

27. 38 kg * 2.2 m/s=83.6 kg-m/s

28. The pressure inside the tube is greater than the pressure outside the tube because primarily of the smaller area of the tube. This increases up the pressure and let the fluid rise up.

29. The fertilizer is pushed up the tube.

Explanation: I hope this helps :)

A spacecraft is fueled using hydrazine (N2H4; molecular weight of 32 grams per mole [g/mol]) and carries 1640 kilograms [kg] of fuel. On a mission to orbit a planet, the fuel will first be warmed from −186 degrees Fahrenheit [°F] to 78 degrees Fahrenheit [°F] before being used after the long space flight to reach the planet. The specific heat capacity of hydrazine is 0.099 kilojoules per mole kelvin [kJ/(mol K)]. If there is 300 watts [W] of power available to heat the fuel, how long will the heating process take in units of hours [h]?

Answers

The expression for thermal energy and power we were able to find the time necessary to heat the fuel is t = 689 h

To find

  • Time

The international measurement system (SI) establishes the fundamental units in the measurement processes, this is defined by convention, giving uniformity in the calculation process and measurement exchange. Before starting the exercise we must reduce the magnitude to the SI system

          PM = 32 g / mol ((1 kg)/(1000 g) g) = 32 10-3 kg / mol

          T₀ = 5/9 (ºF -32) + 273.15 = 5/9 (186 32) +273.15 = 152.0 K

          T_f = 5 * (78 - 32) +273.15 = 298.7 K

          c_e = 0.099 kj / mol k ((1000J)/(1 kJ)) = 0.099 10³ J / mol K

The mole is the amount of matter of the international system (SI), the moles exist must be calculated since they are the mass of the compound for this we use a direct rule of proportions, if a mole has more than 32 10⁻³ kg, when moles are 1640 kg

           n = (m)/(PM)

           n = 1640/32 10⁻³

           n = 51.25 10³ mol

If we assume that all energy transfer is thermal, we can use  

           Q = m\  c_e ( T_f - T_o)

           Q = 51.25 10³ 0.099 10³ (298.7 -152.0)

           Q = 7.44 10⁸ J

             

Power defined by the relationship between work and time

           P = (W)/(t)

In this case the thermal work is equal to the heat ( W=Q)

           t = (Q)/(P)

           t = 7.44 10⁸ / 300

           t = 2.48 10⁶ s

They indicate that the answer is given in hours, let's reduce the time

           t = 2.48 106 s (1h / 3600s)

           t = 6.89 10² h

In conclusion, with the relationship of thermal energy and power, we were able to set the time necessary for the amount of fuel to be t = 689 h

Learn more about thermal energy and power here:

brainly.com/question/11278589

Answer:

The value is t = 689.029 \  hours

Explanation:

From the question we are told that

The molar mass of hydrazine is Z =  32 g/mol = (32)/(1000) = 0.032 \  kg/mol

The initial temperature is T_i  =  -186 ^o F = (-186-32) *(5)/(9) +273.15 = 152\ K

The final temperature is T_f  =  78 ^o F = (78-32) *(5)/(9) +273.15 = 298.7 \ K

The specific heat capacity is c_h  =  0.099 [kJ/(mol K)] = 0.099 *10^3 J/(mol/K)

The power available is P = 300 \ W

The mass of the fuel is m =   1640 \  kg

Generally the number of moles of hydrazine present is

n  =  (m)/(Z)

=> n  =  (1640)/(= 0.032)

=> n  =  51250 \ mol

Generally the quantity of heat energy needed is mathematically represented as

Q =  n * c_h * (T_f -T_i)

=> Q =  51250  * 0.099 *10^3  * (298.7 - 152)

=> Q =  7.441516913 * 10^(8) \  J

Generally the time taken is mathematically represented as

t =  (Q)/(P)

=> t =  (7.441516913 * 10^(8) )/(300)

=> t = 2480505.6377 s

Converting to hours

t = (2480505.6377)/(3600)

=> t = 689.029 \  hours

The rings of Saturn occupy the region inside Saturn's Roche limit.

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I suppose this is a true or false question and that sentence is true.