Which of these is the area of a sector of a circle with r = 18”, given that its arc length is 6π?a.54.00 in2B)113.10 in2C)169.65 in2D)339.29 in2

Answers

Answer 1

Answer: The formulas for arc length and area of a sector are quite close in their appearance. The formula for arc length, however, is related to the circumference of a circle while the area of a sector is related to, well, the area! The arc length formula is $AL= ( \beta )/(360) *2 \pi r$ . Notice the "2*pi*r" which is the circumference formula. The area of a sector is $A s= ( \beta )/(360) * \pi r ^(2)$ . Notice the "pi*r squared", which of course is the area of a circle. In our problem we are given the arc length and the radius. What we do not have that we need to then find the area of a sector of the circle is the measure of the central angle, beta. Filling in accordingly, $6 \pi = ( \beta )/(360) *2 \pi (18)$ . Simplifying by multiplying by 360 on both sides and then dividing by 36 on both sides gives us that our angle has a measure of 60°. Now we can use that to find the area of a sector of that same circle. Again, filling accordingly, $A_(s) = (60)/(360) * \pi (18) ^(2)$ , and $A_(s) =54 \pi$ . When you multiply in the value of pi, you get that your area is 169.65 in squared.

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Please solve the equation below.

2x+4=3(x-4)

Answers

Question:-

solve the equation below :-

2x+4=3(x-4)

Answer:-

x = 16

Explanation:-

=> 2x+4 = 3(x-4)

=> 2x+4 = 3x-12

=> 2x+4 - 4 = 3x-12 - 4 (Subtract 4 on both the sides)

=> 2x = 3x-16

=> 2x-3x = -16

=> -x = -16

=> -x/-1 = -16/-1

=> x =16

Answer:

x=16

Step-by-step explanation:

$\sf 2x+4=3(x-4)$

$\sf 2x+4=3x-12$

$\sf 2x+4-4=3x-12-4$

$\sf 2x=3x-16$

$\sf 2x-3x=3x-16-3x$

$\sf -x=-16$

$\sf \cfrac{-x}{-1}=\cfrac{-16}{-1}$

$\sf x=16$

a house plan is drawn to a scale of 1 cm=2 metres.What is the length of a window 1.5cm long on the plan?

Answers

1cm=2m therefore 1.5cm=3 meters because .5 is half of 1 and 1 is half of 2 enjoy!=)

Because 1 cm _ _ _ 2 metres ; 0.5 cm _ _ _ 1 metres ;
1.5 cm _ _ _ 3 metres.

-5v-6=3v+10 i really hate math but i need help

Answers

OK. We could have gotten along nicely without the comment.

-5v - 6 = 3v + 10

I think what you're trying to find is the number that ' v ' must be
in order to make the equation a true statement. That number
is called the 'solution' of the equation.

To find it, you have to massage and manipulate the equation around
until you have ' v ' and nothing else on one side. You can do anything
you want to a whole side of the equation, but whatever you do to one
side, you must immediately do to the other side. Here's one way you
could go about it:

-5v - 6 = 3v + 10

Add 5v to each side: -6 = 8v + 10

Subtract 10 from each side: -16 = 8v

Divide each side by 8 : -2 = v

Now, was that so painful ?

Is -5 equal to 5? I need help

Answers

Answer:

yes

Step-by-step explanation:

Yes It is I think! There’s no difference so it should be yes! It’s the same thing! If you do get this wrong I am very sorry! I just think it is!

Expand and simplify1) 3 ( 2x + 1 ) + 5x
2) ( x + 3 ) ( x + 4 )
3) ( x + y ) ^2
4) ( 2x + 1 ) ( x - 3 )

Answers

Question:

→To simple the given equations

( 2x + 1 ) + 5x
( x + 3 ) ( x + 4 )
( x + y ) ²
( 2x + 1 ) ( x - 3 )

Answer:

Part 1:

$\green{step \: 1}$

→ $3 ( 2x + 1 ) + 5x$

$\green{step \: 2}$

→ $6x + 3 + 5x$

$\green{step \: 3}$

→ $\blue{11x + 3✓}$

part 2:

$\green{step \: 1}$

→ $( x + 3 ) ( x + 4 )$

$\green{step \: 2}$

→ ${x}^(2) + 4x + 3x + 12$

$\green{step \: 3}$

→ $\blue{ {x}^(2) + 7x + 12✓}$

part 3:

$\green{step \: 1}$

→ $( x + y ) ^2$

$\green{step \: 2}$

→ $\blue{{x}^(2) + {y}^(2) + 2xy✓}$

part 4:

$\green{step \: 1}$

→ $( 2x + 1 ) ( x - 3 )$

$\green{step \: 2}$

→ $2 {x}^(2) - 6x + x - 3$

$\green{step \: 3}$

→ $\blue{2 {x}^(2) - 5x - 3✓}$

★What do you mean by simplifying an equation:

Simplifying an evaluation means to solve any difficult or easy equation in as simple form as possible .

★Steps we can do to simplify the equation:

Open brackets/parentheses to make the equation more simplified.

Add /subtract numbers or numbers with same variable/constant.

thankyou ❤️

Draw a line segment and copy it to the right of the original segment. Explain your steps and justify each step used. Bisect the original line segment from problem one. Draw an angle and copy it to the right of the original angle. Explain your steps and justify each step used. Bisect the original angle from problem three.

Answers

Draw a line segment of any length roughly , and 'copy' it to the right of the segment, writing down the steps you use.

For example:

we draw a line segment of 4 inch.
For the 'copy', you would 'measure' the line drawn, and duplicate it to the right, measuring it to make sure it is the exact length of the first line.

To bisect the original line segment measure the line with a ruler or other device, and calculate 1/2 distance from one end, mark it, measure from left end to mark, make sure right section is equal in length. Line can also bisect by using a compass. open the compass more than half length of the line segment and them draw an arc from it by placing it at one end of the line segment , repeat the process from the other end of the line segment and then a point at which both these arc intersect will be the mid point of the line segment.
Draw an angle, and copy it to the right of the original angle. Explain your steps, and justify each step used.
Draw an angle of 90 degree and labeled it to avoid confusion.
Now use a scale to draw a ray and label the vertex point so we can know the point where to place compass.Use compass to draw an arc on angle.This angle will help you measure where to put the new point on our new angle.
Similarly draw the same arc on the new ray. This is the first step in finding the new point.
now use compass to measure the difference between the two places where the arc meets the angle on angle . use the measurements from the previous step to draw another arc. This step is to help establish a point where the two arcs meet.Now draw a point where the two arcs met and drew a line through it.

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