as a puppy, kim's dog weighs 15 ounces. as an adult, kim's dog weighs 8 pounds. how many ounces did kim's dog gain

Answers

Answer 1

Answer: The answer is 113 ounces.

Kim's dog weighs 8 pounds. Since 1 pound is 16 ounces, Kim's dog weighs 8 × 16 ounces = 128 ounces.
As a puppy, Kim's dog weighs 15 ounces.
So, the weigh that Kim's dog gained is subtraction of 128 ounces and 15 ounces:
128 ounces - 15 ounces = 113 ounces.

Therefore, Kim's dog gained 113 ounces.

Answer 2

Answer:

Answer:

113 ounces

Step-by-step explanation:

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A baseball player got 61 hits one season. He got h of the hits in one game. What expression represents the number of hits he got in the rest of the games? The player had nothing hits in the rest of the games.

Answers

Answer:

$(61-h)$

Step-by-step explanation:

Total number of hits by baseball player in one season = 61

Number of hits in one game = $h$

To find:

The expression to represent the number of hits that the player got in the rest of the games = ?

Solution:

Number of hits that the player got in one game = $h$

Let the number of hits that the player got in rest of the games = $x$

As per the given question statement,

The sum of $h$ and $x$ will be equal to 61.

$h+x=61\n\Rightarrow \bold{x =61-h}$

Therefore, the player had $(61-h)$ hits in the rest of the games.

Im timed i need the answer NOWFind the distance between point A(0,4) and point B (-2,-7) rounded to the nearest tenth.

A.3.6
B. 11.1
C.11.2
D.3.7

Answers

Answer:

C.11.2

Step-by-step explanation:

The distance between 2 points is given by

d = sqrt( (x2-x1)^2 + (y2-y1)^2)

= sqrt( ( -2-0)^2 + (-7-4)^2)

= sqrt( (-2)^2 + (-11)^2)

= sqrt( 4 + 121)

= sqrt(125)

= 11.18033989

To the nearest tenth

11.2

Cylinder a has a radius 2 cm and contains water to a height of 10cm cylinder b has a radius 5cm and is empty. Some of the water is poured from cylinder a to b the height is now the same

Answers

Answer:

h = 1.38 cm

Step-by-step explanation:

The question is at what value is the height of both cylinders the same:

The area of the circular base on each cylinder is:

$Area=\pi r^2\nA=4\pi \ cm^2\nB=25\pi \ cm^2$

The initial volume in cylinder A is:

$V=4\pi *10\nV=40\pi\ cm^3$

We have that Va + Vb = 40π. The height of water in each cylinder as a function of volume is:

$h_A=(V_a)/(4\pi)\nh_B=(V_b)/(25\pi)$

If both heights are the same:

$(V_a)/(4\pi)=(V_b)/(25\pi)\nV_b=(25)/(4)V_a \nV_a+V_b=40\pi\nV_a+(25)/(4)V_a=40\pi\nV_a=5.5172\pi\ cm^3$

The height 'h' is:

$h=(5.5172\pi)/(4\pi)\n h=1.38\ cm$

Final answer:

The question refers to the mathematics of the volume of a cylinder. It involves calculating the initial volume of water in cylinder A, and then determining the volume of water in cylinder B after it has received water from cylinder A.

Explanation:

The subject of the question is related to the mathematical concept of volume, specifically the volume of a cylinder. In this scenario, we are dealing with two cylinders and the volume of water transferred between them.

Firstly, the volume of water in cylinder A initially can be calculated using the formula for the volume of a cylinder, which is V = πr²h, where r is the radius of the base and h is the height. So, for cylinder A with radius 2 cm and height 10 cm, the volume of water initially is V = π(2)²(10) = 40π cm³.

After some water is transferred from cylinder A to cylinder B, the question states that the height of water in both cylinders is the same. It means that the volume of water in cylinder B is now equal to that of a cylinder with radius 5 cm and the same height as cylinder A after the transfer which can also be found by the formula V = πr²h.

Learn more about Volume of cylinder here:

brainly.com/question/16788902

#SPJ12

A box is to be made out of a 6 by 14 piece of cardboard. Squares of equal size will be cut out of each corner, and then the ends and sides will be folded up to form a box with an open top. Find the length L, width W, and height H of the resulting box that maximizes the volume.